Why is most space exploration accomplished with spacecraft that do not have astronauts on board

Answers

Answer 1

Answer: Because of the enormous expense of creating conditions aboard
a spacecraft in which astronauts can survive, and the huge extra
weight and expense of guaranteeing their safety.

Answer 2

Answer:

Answer:

Explanation:

so people dont have to risk their lives to discover space. They want to test its safety out by using rovers and other robots.

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Scientists have observed that the average sunspots have increased in the last 50 years. Which of these statements best describes an effect of this increase in sunspots? A) Earth's temperature has become cooler.
B) Earth's temperature has not changed over time.
C) Earth's temperature has become warmer.
D) Earth's temperature has reduced by fifty times.

Answers

Answer:

Earth's temperature has become cooler

Explanation:

The number of sunspots, as you have learned, can indicate whether the sun is in a maximum-activity period or a minimum-activity period. Some scientists believe this can have an overall effect on the climate of Earth.

The right answer for the question that is being asked and shown above is that: "B) Earth's temperature has not changed over time." Scientists have observed that the average sunspots have increased in the last 50 years. The statement that best describes an effect of this increase in sunspots Earth's temperature has not changed over time.

A motorcycle traveling at a speed of 44.0 mi/h needs a minimum of 44.0 ft to stop. If the same motorcycle is traveling 79.0 mi/h, determine its minimum stopping distance (in ft), assuming the same rate of acceleration.

Answers

Answer:

141.78 ft

Explanation:

When speed, u = 44mi/h, minimum stopping distance, s = 44 ft = 0.00833 mi.

Calculating the acceleration using one of Newton's equations of motion:

$v^2 = u^2 + 2as\n\nv = 0 mi/h\n\nu = 44 mi/h\n\ns = 0.00833 mi\n\n=> 0^2 = 44^2 + 2 * a * 0.00833\n\n=> 1936 = -0.01666a\n\na = -116206.48 mi/h^2 or -14.43 m/s^2$

Note: The negative sign denotes deceleration.

When speed, v = 79mi/h, the acceleration is equal to when it is 44mi/h i.e. -116206.48 mi/h^2

Hence, we can find the minimum stopping distance using:

$v^2 = u^2 + 2as\n\nv = 0 mi/h\n\nu = 79 mi/h\n\na = -116206.48 mi/h\n\n=> 0^2 = 79^2 + (2 * -116206.48 * s)\n\n6241 = 232412.96s\n\ns = (6241)/(232412.96) \n\ns = 0.0268531 mi = 141.78 ft$

The minimum stopping distance is 141.78 ft.

Two identical freight cars roll without friction (one at 1 m/s, the other at 2 m/s) toward each other on a level track. They collide, couple together, and roll away in the direction that _________.

Answers

Answer:

They collide, couple together, and roll away in the direction thatthe 2m/s car was rolling in.

Explanation:

We should start off with stating that the conservation of momentum is used here.

Momentum = mass * speed

Since, mass of both freight cars is the same, the speed determines which has more momentum.

Thus, the momentum of the 2 m/s freight car is twice that of the 1 m/s freight car.

The final speed is calculated as below:

mass * (velocity of first freight car) + mass * (velocity of second freight car) = (mass of both freight cars) * final velocity

(m * V1) + (m * V2) = (2m * V)

Let's substitute the velocities 1m/s for the first car, and - 2m/s for the second. (since the second is opposite in direction)

We get:

$m*1 + m*(-2) = 2m*V$

solving this we get:

V = - 0.5 m/s

Thus we can see that both cars will roll away in the direction that the 2 m/s car was going in. (because of the negative sign in the answer)

A long jumper leaves the ground at a 30 degree angle and travels 8.50 m. What is his take off speed?

Answers

Explanation:

To find the takeoff speed of the long jumper, we can utilize the physics principles of projectile motion. Given that the long jumper leaves the ground at a 30-degree angle and travels a distance of 8.50 m, we need to find the initial velocity (takeoff speed) of the jumper.

In projectile motion, we can break down the motion into horizontal and vertical components. The horizontal component remains constant, while the vertical component is affected by gravity.

To solve for the takeoff speed, we can focus on the vertical component of motion. The equation that relates the vertical displacement, initial velocity, launch angle, and acceleration due to gravity is as follows:

Δy = v₀y t + (1/2) g * t²,

where:

- Δy is the vertical displacement (8.50 m),

- v₀y is the vertical component of initial velocity (takeoff speed),

- t is the total time of flight, and

- g is the acceleration due to gravity (approximately 9.8 m/s²).

Since the vertical displacement at the peak of the jump is zero (the jumper is at the highest point), we can rewrite the equation as:

0 = v₀y * t + (1/2) g t².

However, we can derive a relation between the time of flight t and the initial velocity v₀y by using the launch angle θ. The time of flight is given by:

t = (2 v₀y sin(θ)) / g.

Substituting this expression for t in the above equation, we have:

0 = v₀y [(2 v₀y sin(θ)) / g] + (1/2) g [(2 v₀y sin(θ)) / g]².

Now, we can solve for v₀y:

0 = v₀y² (2 sin(θ) + sin²(θ)) / g.

Rearranging and isolating v₀y, we get:

v₀y = √[(g Δy) / (2 * sin(θ) + sin²(θ))].

With the given values:

Δy = 8.50 m,

θ = 30 degrees,

g ≈ 9.8 m/s²,

we can substitute these values into the formula:

v₀y = √[(9

Energy is produced in the Sun through a _____ process. nuclear chemical mechanical frictional

Answers

nuclear, normally nuclear fission

Yes, it is nuclear, but not fission. The sun produce energy through nuclear fusion.

physics Test 2 In a double slit experiment, if the separation between the two slits is 0.050 mm and the distance from the slits to a screen is 2.5 m, find the spacing between the first-order and second-order bright fringes when coherent light of wavelength 600 nm illuminates the slits.