a. F- concentration decreases
b.the dissociation constant, K, increases
c. HF concentration decreases
d. H+ concentration decreases
When gaseous hydrogen chloride is passed through a sodium chloride solution, precipitation of the sodium chloride occurs as a result of an excess of chloride ions in the solution (caused by the dissociation of HCl). Here the concentration of H⁺ decreases. The correct option is D.
When another electrolyte (which includes an ion that is also present in the first electrolyte, i.e., a common ion) is added, the common ion effect suppresses the ionisation of the first electrolyte. It is thought to be a result of Le Chatlier's principle, often known as the equilibrium law.
An increase in the concentration of one of the ions dissociated in the solution by the addition of another species containing the same ion will result in an increase in the degree of association of ions in a solution where there are several species associating with each other via a chemical equilibrium process.
Here the common ion 'F' in KF supresses the dissociation of HF.
Thus the correct option is D.
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also how many grams of salt NaCl will be produced and how many grams of water H2O be produced?
(2) low temperature and high pressure
(3) high temperature and low pressure
(4) high temperature and high pressure
(3) increases the reaction rate and has a higher activation energy
(4) increases the reaction rate and has a lower activation energy
Answer: Option (4) is the correct answer.
Explanation:
Activation energy is the minimum amount of energy required by the reactants to participate in the chemical reaction.
Therefore, reactant molecules whose energy is less than the activation energy are not able to participate in the reaction. Hence, a catalyst lowers the activation energy so that molecules with less energy can also participate in the reaction.
Thus, a catalyst is a specie that increases the reaction rate and has a lower activation energy.
Explanation:
The given data is as follows.
V = 250.0 ml, T = 58^{o}C = 58 + 273 = 331 K
n = 2.48 moles, P = ? , R = 0.082 atm L /K mol
Therefore, calculate the pressure using ideal gas equation as follows.
PV = nRT
P =
=
= 0.269 atm
Thus, we can conclude that pressure of the given gas is 0.269 atm.