2Na + 2H2O 2NaOH + H2
Answer: YES
Explanation: The given chemical equation can be balanced by balancing the stiochiometric number of each and every element.
This rule is in accordance with the Law of Conservation of Masses which states that the masses of the elements in any chemical equation are constant at any instant of time.
Thus the given equation can be written as
Answer:
The partial pressure of nitrogen is 0.402 atm.
Explanation:
Given data:
Number of moles of helium = 1 mol
Number of moles of nitrogen = 2 mol
Total pressure of mixture = 0.60 atm
Partial pressure of nitrogen = ?
Solution:
First of all we will calculate the mole fraction of nitrogen.
mole fraction of nitrogen = moles of nitrogen / total number of moles
mole fraction of nitrogen = 2 mol / 3 mol = 0.67
Partial pressure of nitrogen:
P₁ = [ n₁ /n(t)] × Pt
P₁ = 0.67 × 0.60 atm
P₁ = 0.402 atm
To find the partial pressure of nitrogen in a mixture, calculate the mole fraction of nitrogen and multiply it by the total pressure of the mixture. In this case, the partial pressure of nitrogen is 0.40 atm.
The question is about determining the partial pressure of nitrogen in a mixture of helium and nitrogen based on Dalton's Law of Partial Pressures. First, we find the mole fraction of nitrogen, which is the ratio of moles of nitrogen to the total moles in the mixture. In this scenario, the mole fraction (XN2) is 2 moles of nitrogen divided by the total moles (1 mole of helium + 2 moles of nitrogen), which equals 2/3.
Then we use Dalton's Law, which states that the partial pressure of nitrogen (PN2) can be found by multiplying the mole fraction by the total pressure of the mixture. Therefore, the partial pressure of nitrogen is 0.60 atm (total pressure) multiplied by 2/3 (mole fraction of nitrogen), yielding a partial pressure for nitrogen of 0.40 atm.
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B. farmer
C. painter
D. carpenter
Answer:
17 atoms are in 3(SO)4
Explanation:
There are 15 total atoms in
To find the total number of atoms in a chemical formula like 3(SO)4, you need to multiply the subscripts (the numbers outside the parentheses) by the number of atoms represented by each element within the parentheses and then multiply that by the coefficient (the number outside the formula).
In this case, you have:
Now, let's break it down:
The subscript for sulfur (S) is 1.
The subscript for oxygen (O) is 4.
So, for each (SO4) unit, you have 1 sulfur atom and 4 oxygen atoms.
Now, multiply this by the coefficient of 3:
= 3 * (1 sulfur atom + 4 oxygen atoms)
= 3 sulfur atoms + 12 oxygen atoms
So, in , there are a total of 3 sulfur atoms and 12 oxygen atoms, for a combined total of 15 atoms.
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