How many protons, electrons, and neutrons does the following isotope contain? 40 Ar

Answers

Answer 1

Answer:

The isotope 40Ar contains 18 protons, 18 electrons, and 22 neutrons.

The isotope 40Ar refers to the isotope of argon, which has an atomic number of 18.

Since the atomic number represents the number of protons in an atom, we can conclude that the isotope 40Ar contains 18 protons.

Argon is a neutral atom, so the number of electrons also matches the number of protons. Therefore, the isotope 40Ar contains 18 electrons.

To find the number of neutrons, we need to subtract the atomic number (protons) from the mass number (protons + neutrons). The mass number of 40Ar is 40. Subtracting the atomic number of 18 from the mass number gives us:

Number of neutrons = Mass number - Atomic number

Number of neutrons = 40 - 18

Number of neutrons = 22

Therefore, the isotope 40Ar contains 18 protons, 18 electrons, and 22 neutrons.

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Answer 2

Answer:

Answer:

18 protons, 18 electrons, 22 nuetrons

Explanation:

Argon has an atomic # of 18. Atomic #s show the amount of protons and electrons it has. Atomic mass - atomic # = # of nuetrons. 40-18=22

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As the temperature of a liquid increases, its vapor pressure(1) decreases
(2) increases
(3) remains the same

Answers

As the temperature of liquid increases, its vapor pressure increases. Therefore, option (2) is correct.

What is vapour pressure?

Vapour pressure can be defined as the pressure exerted by a vapor with its condensed phases in a closed system at a given temperature. The equilibrium vapor pressure is also served as an indicator of the rate of evaporation of a liquid.

A material that has a high vapor pressure at normal temperatures is commonly referred to as a volatile material. The pressure exhibited by the molecules of the gas above a liquid surface is called vapor pressure.

The temperature and the vapor pressure of liquid are directly related to each other. If the temperature of the liquid increases, more gasmolecules have the energy to escape from the surface of the liquid.

Therefore, the vapor pressure increases with an increase in the temperature of the liquid.

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As the temperature of a liquid increases, its vapor pressure increases

On a temperature versus time graph, how does the temperature at the beginning of a change of state compare with the temperature at the end of the change?

Answers

the answer is ALWAYS THE SAME.

Answer:B

Explanation:

Which of the following sequences lists the relative sizes of particles in a water mixture from smallest to largest? a. Solutions, suspensions, colloids
b. Solutions, colloids, suspensions
c. Colloids, solutions, suspensions
d. Colloids, suspensions, solutions
e. Suspensions, colloids, solutions

Answers

mostly A., im guessing

Jose times how long sugar takes to dissolve in warm water. He conducts four trials of his experiment. What should he conclude from his data?Trial Time
1 30 seconds
2 32 seconds
3 10 seconds
4 29 seconds
Sugar does not dissolve in water.
The time recorded for Trial 3 may be inaccurate.
His experiment has very low precision.

Answers

Answer:

His experiment has very low precision

Explanation:

Precision is how close the answers are together. The answers are increasing in time. So, this makes sence. None of the answers are similar to one another.

8.00*10^-5 mol was diluted to 500ml what is the concentration in Mol/L?

Answers

Make sure all units are consistent. Convert ml to L first. (500ml = 0.5L). Then divide the mole by the volume which would result to 1.6*10^-4mol/L. This can also be expressed as interms of molarity (M). 1 M = 1 mol/L hence the final answer is 1.6*10^-4 M.

Answer : The concentration in mol/L is $1.6* 10^(-4)mol/L$

Explanation : Given,

Moles = $8.00* 10^(-5)mol$

Volume of solution = 500 mL

Formula used :

$\text{Concentration}=\frac{\text{Moles of solute}* 1000}{\text{Volume of solution (in mL)}}$

Now put all the given values in this formula, we get:

$\text{Concentration}=(8.00* 10^(-5)mole* 1000)/(500mL)=1.6* 10^(-4)mol/L$

Therefore, the concentration in mol/L is $1.6* 10^(-4)mol/L$

While in Europe, if you drive 107km per day, how much money would you spend on gas in one week if gas costs 1.10 euros per liter and your car's gas mileage is 39.0mi/gal ? Assume that 1euro=1.26dollars.

Answers

That's a lot of conversions...
107*7 = 749km in one week
749/1.6 = 468.125 miles
468.125/39 = 12.0032051282 gallons of fuel needed
1 gallon = 4.54609 litres
1.1(Cost per litre)*4.54609(Number of litres per gallon)*12.0032051282(Number of gallons needed) = 60.0244158814 euros cost per week
60.0244158814 * 1.26 = 75.6307640105 dollar cost per week
$75.63

Answer:

$ 62.578

Explanation:

Conversion factors:

1 gal = 3.785 L

1.609km = 1 mi

$1.26 = 1 euro

1 week = 7 days

Converting the car’s mileage from mi/gal to km/L

39 mi/gal x 1 gal/3.785L x 1.609km/1 mi = 16.578 km/L

Finding the L required in a day

107 km x 1L/16.578 km = 6.45 L