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Explanation:
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Answer:
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Explanation:
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Answer:
Three atoms are attached to the central atom in NF3.
Explanation:
The central atom is always regarded as the atom having the least electronegativity in a molecule or ion. We can decide on what atom should be the central atom by comparing the relative electro negativities of the atoms in the molecule or ion.
If we consider NF3, we can easily see that nitrogen is less electronegative than fluorine, hence nitrogen is the central atom in the molecule. We can also observe from the molecular model that three atoms of fluorine were attached to the central atom. Hence there are three atoms attached to the central atom in the molecule NF3.
(b) By a mechanically reversible, adiabatic process [T 2 =208.96K; P 2 = 67.65 kPa; W= -994.4 kJ] For each case calculate the final temperature, pressure and the work done by the gas. C p =21 Jmol- 1K-1.
Answer:
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Explanation:lol just grabbing your points
lol just grabbing your points
lol just grabbing your points
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lol just grabbing your points
lol just grabbing your points
lol just grabbing your points
lol just grabbing your points
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Alkaline Earth Metals
Alkali metals
Noble Gases
Lanthanides
Answer:
alkali metals- Group 1
Explanation:
they have less valence electrons and therefore are more reactive
Answer:
0.051
Explanation:
Let's consider the following reaction.
2 SO₂(g) + O₂(g) ⇄ 2 SO₃(g)
We can compute the pressures using an ICE chart.
2 SO₂(g) + O₂(g) ⇄ 2 SO₃(g)
I 3.3 0.79 0
C -2x -x +2x
E 3.3-2x 0.79-x 2x
The partial pressure of sulfur trioxide gas is 0.47 atm. Then,
2x = 0.47
x = 0.24
The pressures at equilibrium are:
pSO₂ = 3.3-2x = 3.3-2(0.24) = 2.82 atm
pO₂ = 0.79-x = 0.79-0.24 = 0.55 atm
pSO₃ = 0.47 atm
The pressure equilibrium constant (Kp) is:
Kp = pSO₃² / pSO₂² × pO₂
Kp = 0.47² / 2.82² × 0.55
Kp = 0.051
Answer:
0.295 mol/L
Explanation:
Given data:
Volume of solution = 3.25 L
Mass of BaBr₂ = 285 g
Molarity of solution = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Number of moles of solute:
Number of moles = mass/ molar mass
Molar mass of BaBr₂ = 297.1 g/mol
Number of moles = 285 g/ 297.1 g/mol
Number of moles= 0.959 mol
Molarity:
M = 0.959 mol / 3.25 L
M = 0.295 mol/L
The question is about calculating the molarity of a solution. First, convert the given mass of solute into moles using the molar mass. Then, using the molarity formula, divide the moles of solute by the volume of the solution in liters.
In order to determine the molarity of the solution, we will divide the amount of solute (in moles) by the volume of the solution (in liters). The formula for molarity (M) is:
M = moles of solute/volume of solution in liters
First, we need to convert the mass of BaBr2 into moles. The molecular weight of BaBr2 is 297.14 g/mol. So, 285 g of BaBr2 is equal to 285/297.14 = 0.959 moles.
The volume of the solution is given as 3.25 L. So, plugging these values into the formula gives us the molarity of the solution:
M = 0.959 moles/3.25 L = 0.295 M
So, the molarity of the solution is 0.295 M.
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