Answer:
28.2 g of NaOH
Explanation:
We need to calculate the grams of NaOH needed to react with 25.0 g of Cl₂ in the following reaction:
2 NaOH(aq) + Cl₂(g) → NaOCI(aq + H₂0(I) + NaCl(aq)
We are going to solve this by making use of the molar ratio between Cl₂ and NaOH given by the reaction equation where we see that every mol of Cl₂ will react with 2 moles of NaOH.
So first we need to convert the 25.0 g of Cl₂ to moles:
Then we need to calculate the moles of NaOH needed to react with these moles of Cl₂ knowing that every mol of Cl₂ will react with 2 moles of NaOH:
Next we must convert these moles to grams:
28.2 g are needed to react with 25.0 g of Cl₂ in the production of NaOCl
Answer:
9.92g
Explanation:
2.50 in31×16.39 cm31 in3×0.242 gcm3=9.92 g
The answer I got was False, is this correct?
Answer: yes it is false
Explanation:
The statement is false. A synthetic process with a lower E-factor produces less waste than a process with a higher E-factor.
The E-factor is a measure of the waste generated during a manufacturing process. It is calculated by dividing the total mass of waste produced by the mass of the desired product. A lower E-factor indicates that less waste is generated per unit of product.
In this case, the synthetic process with an E-factor of 3.0 produces less waste than the process with an E-factor of 17.4. This means that the process with an E-factor of 3.0 is more efficient in terms of waste reduction.
Answer:
The freezing point of a solution is lowered compared to the freezing point of the pure solvent. The amount of depression of the freezing point is proportional to the molality of the solute. The greater the molality of a solution, the lower its freezing point. To compare the freezing points of these solutions, we need to determine which one has the highest molality.
First, we need to determine the number of particles that each solute will produce in solution, as this affects the amount of depression of the freezing point.
KNO3 dissociates into two ions: K+ and NO3-, so it will produce two particles per formula unit.
BaCl2 dissociates into three ions: Ba2+ and two Cl-, so it will produce three particles per formula unit.
Ethylene glycol does not dissociate in solution, so it will produce one particle per molecule.
Na3PO4 dissociates into four ions: three Na+ and one PO43-, so it will produce four particles per formula unit.
Now, we can calculate the molality (moles of solute per kilogram of solvent) for each solution:
For 0.10 m KNO3: molality = 0.10 mol / 1 kg = 0.10 m
For 0.10 m BaCl2: molality = 0.10 mol x 3 particles / 1 kg = 0.30 m
For 0.10 m ethylene glycol: molality = 0.10 mol / 1 kg = 0.10 m
For 0.10 m Na3PO4: molality = 0.10 mol x 4 particles / 1 kg = 0.40 m
So, the solutions in order of decreasing freezing points are:
0.10 m Na3PO4 (highest molality)
0.10 m BaCl2
0.10 m KNO3 and 0.10 m ethylene glycol (same molality, but KNO3 has a smaller van't Hoff factor than ethylene glycol, so it will have a slightly higher freezing point)
Explanation:
Answer:
5.56×10²² molecules of AlPO4
Explanation:
i think thats is the correct answer if its wrong im really sorry
Caffeine has two sp2 and one sp3 hybridized carbon atoms in its structure.
Caffeine has three carbon atoms in its structure, and the hybridization of these carbon atoms determines the types of bonds they form. Two of the carbon atoms in caffeine are sp2-hybridized, while the remaining carbon atom is sp3-hybridized.
The sp2-hybridized carbon atoms form double bonds with nitrogen atoms and are found in the pyrimidine and pyrazole rings of the caffeine molecule. They have trigonal planar geometry with bond angles of approximately 120 degrees.
The sp3-hybridized carbon atom is found in the methyl group (CH3) attached to the pyrimidine ring. It forms single bonds with three hydrogen atoms and has tetrahedral geometry with bond angles approximately 109.5 degrees.
#SPJ3
Answer:
76.0 years
Explanation:
Step 1: Given data
Step 2: Calculate the rate constant (k)
We will use the following expression.
k = ln 2/ t1/2 = ln 2 / 12.0 y = 0.0578 y⁻¹
Step 3: Calculate the time elapsed
For a first-reaction order, we will use the following equation.
ln [A]/[A]₀ = -k × t
t = ln [A]/[A]₀ / (-k)
t = (ln 10.0 ppbm/809 ppbm) / (-0.0578 y⁻¹)
t = 76.0 y
Answer:
Potassium (K) [First element in period 4]