Answer:
B
Explanation:
Newton's third law. states that:
Action and reaction are equal and opposite.
B. two
C. three
D. four
Answer:
C. three
Explanation:
A lithium atom must lose one valence electron to achieve a full valence shell, resulting in a positively charged lithium cation (Lit) with a noble gas configuration similar to helium.
To achieve a full valence shell, a lithium atom must lose one electron. Lithium has an atomic number of 3, which means it has three electrons: two in the first shell and one in the second shell. Since the first shell (1s) is already full with two electrons, lithium has a single electron in the 2s subshell of the second shell. This single electron is the valence electron.
According to the Lewis diagram, lithium (Li) has only one valence electron in its second shell. By transferring this lone electron to another atom, lithium's electron configuration will resemble that of helium (He), with two electrons in its first shell, thus achieving a stable noble gas configuration. This transfer results in the formation of a lithium cation, denoted as Lit, with a charge of 1+.
It is important to note that when lithium becomes a cation, it does not necessarily mean it has a complete valence shell in terms of helium or neon. Instead, it has achieved stability by having a full inner shell, which mimics the noble gas configuration of helium.
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Answer : The number of drops pf the stock solution mist be added are, 50 drops.
Explanation :
As we are given that the concentration of stock solution 1 mg/mL and pipette delivers 20 drops/mL. That means,
1 mg of epinephrine = 1 mL = 20 drops
The final volume of Locke's solution = 25 mL
and the final concentration needed =
As, 1 mL of solution contains =
So, 25 mL of solution contains =
Conversion used :
Now we have to determine the number of drops needed.
As, 1 mg of epinephrine contains 20 drops.
So, 2.5 mg of epinephrine contains 2.5 × 20 = 50 drops.
Therefore, the number of drops pf the stock solution mist be added are, 50 drops.
If you want to achieve a final concentration of 100 µg/mL of epinephrine in a 25 mL solution, when using a stock solution of 1 mg/mL and a pipette that delivers 20 drops/mL, you need to add 50 drops of your stock solution.
Since we are asked to find the number of drops of stock solution required to achieve a final concentration of 100 µg/mL in a 25 mL solution, the first step is to convert the concentration of the stock solution to the same units, µg/mL. Hence, 1 mg/mL is equal to 1000 µg/mL. Further, we know that 1 mL of the stock solution contains 1000 µg of epinephrine, and our pipette delivers 20 drops/mL, so 1 drop of stock solution contains 1000 µg / 20 drops = 50 µg. Thus, if we need a 100 µg/mL concentration in 25 mL, we need a total of 100 µg/mL * 25 mL = 2500 µg of epinephrine. Therefore, to achieve this, we must add 2500 µg / 50 µg/drop = 50 drops of our stock solution. Hence,
50 drops
of the stock solution should be added to achieve the desired concentration.
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Answer:
a) 1.866 × 10 ⁻¹⁹ J b) 3.685 × 10⁻¹⁹ J
Explanation:
the constants involved are
h ( Planck constant) = 6.626 × 10⁻³⁴ m² kg/s
Me of electron = 9.109 × 10 ⁻³¹ kg
speed of light = 3.0 × 10 ⁸ m/s
a) the Ek ( kinetic energy of the dislodged electron) = 0.5 mu²
Ek = 0.5 × 9.109 × 10⁻³¹ × ( 6.40 × 10⁵ )² = 1.866 × 10 ⁻¹⁹ J
b) Φ ( minimum energy needed to dislodge the electron ) can be calculated by this formula
hv = Φ + Ek
where Ek = 1.866 × 10 ⁻¹⁹ J
v ( threshold frequency ) = c / λ where c is the speed of light and λ is the wavelength of light = 358.1 nm = 3.581 × 10⁻⁷ m
v = ( 3.0 × 10 ⁸ m/s ) / (3.581 × 10⁻⁷ m ) = 8.378 × 10¹⁴ s⁻¹
hv = 6.626 × 10⁻³⁴ m² kg/s × 8.378 × 10¹⁴ s⁻¹ = 5.551 × 10⁻¹⁹ J
5.551 × 10⁻¹⁹ J = 1.866 × 10 ⁻¹⁹ J + Φ
Φ = 5.551 × 10⁻¹⁹ J - 1.866 × 10 ⁻¹⁹ J = 3.685 × 10⁻¹⁹ J
Answer:
Around 2.0 L of ethylene glycol needs to be added to the car radiator
Explanation:
The depression in freezing point ΔTf of a solution is directly proportional to its molality (m), i.e.
From the given information:
= freezing pt of solution = -10.0 C
= freezing pt of pure solvent = 0 C
Kf = freezing pt depression constant = 1.86 C/m
i = 1 for ethylene glycol antifreeze
Volume of water = 6.50 L = 6500 ml
Density of water = 1.00 g/ml
Therefore mass of water =
Molar mass of ethylene glycol = 62 g/mol
Mass of ethylene glycol needed =
Density of ethylene = 1.11 g/ml
Therefore, volume needed =
Molar mass of the weak base = 82.0343g/mole.
Note: pKa = -logKa
pKb = -logKb
pH + pOH = 14
[H+ ] [OH- ] = 10^-14
Answer:
11.39
Explanation:
Given that:
Given that:
Mass = 1.805 g
Molar mass = 82.0343 g/mol
The formula for the calculation of moles is shown below:
Thus,
Given Volume = 55 mL = 0.055 L ( 1 mL = 0.001 L)
Concentration = 0.4 M
Consider the ICE take for the dissociation of the base as:
B + H₂O ⇄ BH⁺ + OH⁻
At t=0 0.4 - -
At t =equilibrium (0.4-x) x x
The expression for dissociation constant is:
x is very small, so (0.4 - x) ≅ 0.4
Solving for x, we get:
x = 2.4606×10⁻³ M
pOH = -log[OH⁻] = -log(2.4606×10⁻³) = 2.61
pH = 14 - pOH = 14 - 2.61 = 11.39
The green house gases in the atmosphere can change the behavior of energy on earth. Thus i agree with this statement.
The green house effect is defined as a process by which the radiations from the sun are absorbed by the green house gases like methane, Chloro fluoro carbons and not reflected back into the space. This makes the surface as insulator and prevents it from freezing.
Due to the increased level of green house gases, the temperature of the earth increases considerably and thereby causes global warming, depletion of ozone layer, smog and air pollution, etc.
It is the natural green house effect which affect the behaviour of heat energy radiated by the sun. The green house gases never let the radiations escape from the earth and increase the surface temperature of earth. This leads to global warming.
Thus green house gases affects the solar energy.
To know more about Global warming, visit;
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Answer:
I agree
Explanation:
because the sunlight passes through the atmosphere and is absorbed by earth's surface.