(5, ꝏ)
(–ꝏ, 0) U (0, 5)
(–ꝏ, 5) U (5, ꝏ)
Answer:
(–ꝏ, 0) U (0, 5)
Step-by-step explanation:
The relation can be written as ...
x³ < 5x²
x³ -5x² < 0
x²(x -5) < 0
This is not true for x = 0. It is true for x < 5, otherwise. Then the solution set is ...
x ∈ {(–ꝏ, 0) U (0, 5)}
The cube of any number from the set (-∞, 0) ∪ (0, 5) is less than five times the square of the number. So, the third option is correct.
Mathematically, a set is a collection of distinct, well-defined objects forming a group.
Let the number be x.
Then, according to the question:
x³ > 5x²
x³ - 5x² > 0
x²(x - 5) > 0
x² > 0 or x - 5 > 0
x > 0 or x > 5
This implies that
x ∈ (-∞, 0) ∪ (0, 5)
Hence, the correct answer is the third option, (-∞, 0) ∪ (0, 5).
Learn more about Set here:
#SPJ3
Answer:
-4(2t+1)(2t-7)
Step-by-step explanation:
First factor out the common term -4
Then factor out -4^2
Answer:
the answer is( -42t+1)(2t-7)
A. x = 15
B. x = 6
C. x = 24
D. x = 12
Answer:
X=2×3=6
Step-by-step explanation:
Y=5, x=2×3=6
I hopethis helps
BRAINLIEST PLEASE
a:
b:
C:
Step-by-step explanation:
2x (5x - 1) + (3x^2 - 7x - 2)
= 10x^2 - 2x + 3x^2 - 7x - 2
= 13x^2 - 9x - 2
a = 13
b = -9
c = 2