Answer:
1/3
.................
An ordinary Regression model that treats the response Y is (a) True False, (w) True
What is Regression?
A statistical method called regression links a dependent variable to one or more independent (explanatory) variables.
A regression model can demonstrate whether changes in one or more of the explanatory variables are related to changes in the dependent variable.
A) Models for numerical response variable, like ANOVA and linear regression are special cases of GLMs
for these model the following holds
1. Random component has a normal distribution
2. Systematic component α+β₁x₁+β₂x₂+...........βₓxₓ
3. link function = identity (g(µ)=µ)
GLMs can generalise these models with response Y as normally distributed, hence the statement is True
B) With a GLM. Y does not need to have a normal distribution and one can model a function of the mean of Y instead of just the mean itself. but in order to get ML estimates the variance of Y must be small. This small variance of Y is the reason for ML estimator to be the best one. hence the statement is false.
An ordinary Regression model that treats the response Y is (a) True False, (w) True
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The zeroth derivative of a function is simply the function itself, so the zeroth order linear ODE takes the general form
whose solution is .
The domain of the function is the union of all of the "if" parts of the function definition:
... (-∞, -1) ∪ [-1, 1] ∪ (1, ∞) = (-∞, ∞)
A. The number of hours the battery will run is a function of the
number of computers Erik has.
B. Erik's choice of a laptop computer is a function of the amount of
power the battery will hold.
C. The amount of power in the battery is a function of the time Erik
runs the computer on the battery.
Answer:
C
Step-by-step explanation:
Because the more power the more battery. Therefore it is a function of time.
Answer:
Step-by-step explanation:
Given that a popcorn company builds a machine to fill 1 kg bags of popcorn. They test the first hundred bags filled and find that the bags have an average weight of 1,040 grams with a standard deviation of 25 grams.
i.e. Sample mean = 1040 and
Sample std dev s = 25 gm
Sample size n = 100
Hence by central limit theorem we have the sample mean follows a normal distribution with mean =1040 and std dev = s = 25 gm
Normal curve would be with mean 1040 and std deviatin 25
b) P(X>1115)
= 1-0.9987
=0.0013
i.e. 0.13% would receive a bag that had a weight greater than 1115 grams
y^-8y^3x^0x^-2
Answer:
Step-by-step explanation:
The options are not given; however, the question can still be solved
Given
Required
Simplify
Start by rewriting the expression
Apply the following laws of indices:
This gives:
Evaluate the exponents
Hence, is equivalent to
The expression which is equivalent to the exponential equation is .
Given data:
The exponential form is an easier way of writing repeated multiplication involving base and exponents. It has a base and a power
The exponential form of a number is a way of representing a number using exponents, where the base is typically a number greater than 1.
The exponential expression is represented as .
From the laws of exponents:
So, the expression is simplified as:
Hence, the equivalent expression is .
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