Explanation:
4.92*10-3=4.92/10^3=
4.92/1000=0.00492
Answer:
NF3< H2S< H2O< He
Explanation:
The average speed of a gas depends on the relative molecular mass of the gas. Lighter gases have a greater average speed and move faster than heavier gases.
Hence, we need to arrange these gases listed in the question in order of decreasing molecular mass in order to obtain the order of increasing Urms assuming equivalent amounts and all gases are at the same temperature and pressure.
Hence; NF3< H2S< H2O< He
The rank in order of increasing Urms for the gases given, assuming the same amount, temperature, and pressure is as follows: NF₃, H₂S, H₂O, and He.
Urms, or root mean square speed, of a gas, depends on the molar mass of the gas and the temperature. It is determined by the formula Urms = sqrt(3kT/M), where k is Boltzmann's constant, T is temperature, and M is the molar mass. The greater the molar mass, the lower the Urms. Looking at the molar masses of the gases H₂S (34 g/mol), He (4 g/mol), NF₃(71 g/mol), and H₂O (18 g/mol), we can rank them in order of increasing Urms as NF₃ 1st), H₂S (2nd), H₂O (3rd), and He (4th).
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Answer:
4,25% v/v H3PO4
Explanation:
The concentration of phosphoric acid (H3PO4) is expressed as a volume / volume percentage, which means:
%v/v H3PO4 = (mL of pure H3PO4/mL of solution)*100%
In other words, we are only interested in the final volume of the solution to which the phosphoric acid was diluted, regardless of its composition. Which in this case is 1 L (1000 mL).
We can then apply the following equation, commonly used to calculate the initial or final concentration (or volume) of a substance when it is diluted:
Ci*Vi=Cf*Vf
Where:
Ci, is the initial concentration of the substance.
Vi, the initial volume of the substance
Cf, the final concentration reached after dilution
Vf, the final volume of the solution at which the substance was diluted
In this case, the incognite would be the final concentration of H3PO4 reached after dilution, that is, Cf. Therefore, we proceed to clear Cf from the previous equation and replace our data:
Cf = (Ci*Vi)/Vf = (85% v/v * 50 mL)/1000 mL = 4,25 % v/v
Note that being up and down in the division, the mL unit is canceled to result in% v / v.
Answer:
1. Mass of Carbon is 56.89g
2. Mass of Hydrogen is 6.33g
3. Mass of Oxygen is 75.88
Explanation:
The following were obtained from the question.
Mass of the compound = 139.1g
Mass of CO2 produced = 208.6g
Mass of H2O produced = 56.93
1. Determination of mass of Carbon (C). This is illustrated below:
Molar Mass of CO2 = 12 + (2x16) = 44g/mol
Mass of C = 12/44 x 208.6
Mass of C = 56.89g
2. Determination of the mass of Hydrogen (H). This is illustrated below:
Molar Mass of H2O = (2x1) + 16 = 18g/mol
Mass of H = 2/18 x 56.93
Mass of H = 6.33g
3. Determination of the mass of oxygen (O).
This is illustrated below:
Mass of the compound = 139.1g
Mass of C = 56.89g
Mass of H = 6.33g
Mass of O = Mass of compound - (mass of C + Mass of H)
Mass of O = 139.1 - (56.89 + 6.33)
Mass of O = 139.1 - 63.22
Mass of O = 75.88
Answer:
The three isomers having the molecular formula are drawn in the figure below.
Explanation:
B) Jet Fuel
C) steel
Mg+
O
Cl-
Na+
Answer:
Chlorine
Explanation:
Answer:
That would be the negative ion: Cl-.