What is the number of neutrons in Hydrogen, O (A= 1, Z= 1)?

Answers

Answer 1
Answer:

Answer:

Explanation:

Hydrogen has 1 proton and one nuetron

Oxygen has 8 protons nad 8 neutrons


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As we drive an automobile, we dont't think about the chemical consumed and produced. Prepare a list of the principal chemicals consumed and produced during the operation of an automobile.

HELP ASAP WHICH ONE IS THE ANSWE A OR B OR C OR D ???? ! !!!

Answers

Answer:

1. C

2.B

Explanation:

A chemist prepares a solution of potassium permanganate (KMnO4) by measuring out 3.8 umol of potassium permanganate into a 100 mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's potassium permanganate solution. Round your answer to 2 significant digits. x 5 ? Explanation Check

Answers

Answer:

3,8×10⁻⁵ mol/L of potassium permanganate solution

Explanation:

To calculate concentration in mol/L you must convert the 3,8 umol to moles and 100 mL to liters, knowing 1 umol are 1×10⁻⁶mol and 1L are 1000 mL.

3,8 umol × (1×10⁻⁶mol / 1 umol ) = 3,8×10⁻⁶mol of potassium permanganate.

100 mL × ( 1L / 1000 mL) = 0,100 L

Thus, concentration in mol/L is:

3,8×10⁻⁶mol / 0,100 L = 3,8×10⁻⁵ mol/L of potassium permanganate solution

I hope it helps!

Classify each of the following chemical reactions as a synthesis decomposition and single displacement or double displacement reaction

Answers

1. Synthesis reaction : there is only 1 product formed from 2 or more reactant

E.g:

H_2(g)+N_2(g)\text{ }\Rightarrow2NH_3(g)\text{ }

2. Decomposition : reaction that occurs in presence of UV light and only 1 reactant that decomposes into 2 or more products.

E.g:

CH_3Br(g)+UV_(light)\Rightarrow CH_3(g)\text{ + Br (g)}

3. Single displacement :reaction that occurs when 1 reactant displaces other reactant from its compound:

E.g:

Zn(s)+CoCl_2(aq)\text{ }\Rightarrow ZnCl_2(aq)\text{ + Co(s)}

4. Double displacement :reaction that occurs when both reactant displaces each other.

E.g :

K_2S(aq)+Co(NO_3)_2\Rightarrow2KNO_3(aq)\text{ + }CoS(s)\text{ }

A substance with a high vapor pressure at normal temperatures is often referred to as volatile. As the temperature of a liquid increases, the kinetic energy of its molecules also increases and as the kinetic energy of the molecules increases, the number of molecules transitioning into a vapor also increases, thereby increasing the vapor pressure.

Answers

As the temperature of a liquid or stable will increase its vapor strain additionally will increase. Conversely, vapor strain decreases because the temperature decreases.

The better the vapor strain of a substance, the extra the awareness of the compound withinside the gaseous section and the extra the quantity of vaporization

. Liquids range substantially of their vapor pressures. substance with a excessive vapor strain at everyday temperatures is regularly called volatile. The strain exhibited through vapor gift above a liquid floor is referred to as vapor strain. As the temperature of a liquid will increase, the kinetic strength of its molecules additionally will increase.

Read more about vapour:

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What will be the theoretical yield of tungsten(is) ,W, if 45.0 g of WO3 combines as completely as possible with 1.50 g of H2

Answers

Answer:

35.6 g of W, is the theoretical yield

Explanation:

This is the reaction

WO₃  +  3H₂  →   3H₂O  +  W

Let's determine the limiting reactant:

Mass / molar mass = moles

45 g / 231.84 g/mol = 0.194 moles

1.50 g / 2 g/mol = 0.75 moles

Ratio is 1:3. 1 mol of tungsten(VI) oxide needs 3 moles of hydrogen to react.

Let's make rules of three:

1 mol of tungsten(VI) oxide needs 3 moles of H₂

Then 0.194 moles of tungsten(VI) oxide would need (0.194  .3) /1 = 0.582 moles (I have 0.75 moles of H₂, so the H₂ is my excess.. Then, the limiting is the tungsten(VI) oxide)

3 moles of H₂ need 1 mol of WO₃ to react

0.75 moles of H₂ would need (0.75 . 1)/3 = 0.25 moles

It's ok. I do not have enough WO₃.

Finally, the ratio is 1:1 (WO₃ - W), so 0.194 moles of WO₃ will produce the same amount of W.

Let's convert the moles to mass (molar mass  . mol)

0.194 mol . 183.84 g/mol = 35.6 g

2Identify at least two factors which influence
periodic poperties of elements in groups
and periods​

Answers

atomic radius

ionization potential

Atomic radius and Ionization Energy