Ne belongs to what group. a. noble gases, b.alkali metals, c. halogens, d. alkaline earth metals

Answers

Answer 1

Answer: The answer is A hope this helps

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A solution of NaOH has a concentration of 25.00% by mass. What mass of NaOH is present in 0.250 g of this solution? Use the periodic table in the toolbar if needed.

Answers

Answer : The mass of NaOH present in the solution is, 0.0625 grams

Explanation : Given,

Mass % = 25 %

Mass of solution = 0.250 g

Formula used :

$Mass\%=\frac{\text{Mass of}NaOH}{\text{Mass of solution}}* 100$

Now put all the given values in this formula, we get the mass of NaOH.

$25=\frac{\text{Mass of}NaOH}{0.250g}* 100$

$\text{Mass of}NaOH=0.0625g$

Therefore, the mass of NaOH present in the solution is, 0.0625 grams

The concentration of NaOH is 25.00% by mass, it means that 25.00% of the mass of the solution is of NaOH. Hence:

$m_(NaOH)=25.00\%* m_(solution)\Longrightarrow m_(NaOH)=(25)/(100)* 0.250~g\iff\n\n\boxed{m_(NaOH)=0.0625~g}$

Which statement is true about the cell membrane? It allows an unlimited amount of water to enter. It stops waste substances from passing through. It is not selective about which gases enter or leave the cell. It is selective about which substances enter or leave the cell.

Answers

Answer:

It is selective about which substances enter or leave the cell.

Explanation:

Also srry for spamming u all the time.

UwU hope this helps tho

Answer:

It is selective about which substances enter or leave the cell

Explanation:

I have learned this already

Write the full ionic equation and net ionic equation for sodium dihydrogen phosphate + calcium carbonate, sodium oxilate + calclium carbonate, and sodium hydrogen phosphate + calcium carbonate

Answers

Answer:

Sodium dihydrogen phosphate + calcium carbonate

Full ionic equation

2 Na⁺(aq) + 2 H₂PO₄⁻(aq) + CaCO₃(s) ⇄ 2 Na⁺(aq) + CO₃²⁻(aq) + Ca(H₂PO₄)₂(s)

Net ionic equation

2 H₂PO₄⁻(aq) + CaCO₃(s) ⇄ CO₃²⁻(aq) + Ca(H₂PO₄)₂(s)

Sodium oxalate + calcium carbonate

Full ionic equation

2 Na⁺(aq) + C₂O₄²⁻(aq) + CaCO₃(s) ⇄ 2 Na⁺(aq) + CO₃²⁻(aq) + CaC₂O₄(s)

Net ionic equation

C₂O₄²⁻(aq) + CaCO₃(s) ⇄ CO₃²⁻(aq) + CaC₂O₄(s)

Sodium hydrogen phosphate + calcium carbonate

Full ionic equation

2 Na⁺(aq) + HPO₄²⁻(aq) + CaCO₃(s) ⇄ CaHPO₄(s) + 2 Na⁺(aq) + CO₃²⁻(aq)

Net ionic equation

HPO₄²⁻(aq) + CaCO₃(s) ⇄ CaHPO₄(s) + CO₃²⁻(aq)

Explanation:

Let's consider two kind of equations:

Full ionic equation: includes all ions and species that do not dissociate in water.
Net ionic equation: includes only ions that participate in the reaction (not spectator ions) and species that do not dissociate in water.

Write the full ground state electron configuration of f+.

Answers

Answer:- $1s^22s^22p^4$ .

Explanation:- Atomic number for fluorine(F) is 9 and it's electron configuration is $1s^22s^22p^5$ . $F^+$ is formed when F loses one electron from it's valence shell.

$F\rightarrow F^++1e^-$

Second shell is the valence shell for fluorine and so it loses one electron from 2p to form $F^+$ and the electron configuration of the ion becomes $1s^22s^22p^4$ .

Final answer:

The ground state electron configuration of F+ is 1s²2s²2p⁴, which is derived from the neutral Fluorine's configuration 1s²2s²2p⁵ by removing one electron from the outermost 2p orbital.

Explanation:

The question asked for the full ground state electron configuration of F+. The neutral Fluorine atom (F) has 9 electrons. Its electron configuration is: 1s²2s²2p⁵. When Fluorine loses one electron it becomes a positively charged ion (F+), so its electron configuration will be: 1s²2s²2p⁴. This is because the electron is removed from the outermost shell, specifically the 2p orbital. This ground-state electron configuration refers to the most stable arrangement of electrons around the nucleus.

Learn more about Ground state electron configuration here:

brainly.com/question/33895511

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To plan ahead using REPS and Checks, choose the minimum space cushion needed to maintain folloying distance traveling at 25 MPH (for a cargo van)?

Answers

The minimum space cushion defines the required amount of space which vehicles should maintain in other to afford them the time and space to gain control in emergency scenarios. Hence, the minimum space cushion required in the scenario is 4 seconds.

In cases of mishaps or accidents, the space cushion might just afford other cars the space to maneuver their way to safety rather than being caught up in the collison or accident.

The required space cushion in most scenario is usually between 2 - 5 seconds, with additional space afforded depending on the length and type of the vehicle.

Therefore, to ensure safety, the required minimum spacecushion to be left when driving being a cargo van traveling at a speed of 25mph is 4 seconds.

Learn more :brainly.com/question/24535523

Final answer:

In order to ensure safety while driving a cargo van at 25 MPH, the driver should maintain a space cushion of about 3-4 van lengths, which accounts for speed, reaction time, and distance needed to apply brakes and avert a collision.

Explanation:

The subject of your question revolves around optimal space cushion required for safety while driving a cargo van at the speed of 25 MPH, adhering to REPS (Reference point, Eye lead time, Posting and Scanning) and Checks (Check side mirrors and Rearview mirror every 5-8 seconds). This question falls under the domain of physics, as it involves velocity (speed of the vehicle), distance (space cushion), and time.

As a general rule of thumb, for every 10 miles per hour, a driver should ideally stay approximately one car length away from the car in front of them. Therefore, at 25 MPH, the driver should maintain a distance of at least 2.5 car lengths. In the case of a cargo van, which is typically larger than a regular car, this distance should ideally be increased to 3-4 van lengths to ensure safe stopping distance and reaction time in case of any sudden stoppage by the vehicle ahead.