Answer:
Explanation:
This question seeks to test the knowledge of Avogadro's law. Avogadro's law states that equal volume of gases, at constant temperature and pressure, contain the same number of molecules. The meaning here is that the volume of a given mass of (ideal) gas is directly proportional to the number of molecules. Thus, an increase in volume of an ideal gas will lead to an increase in the number of molecules of the gas. Also, an increase in the number of molecules of an ideal gas will lead to an increase in the volume of the gas at constant temperature and pressure.
the specific heat of the resulting Nacl solutions is 4.06j/gc
calculate the heat of neutralisation of hcl and naoh in kj/mol nacl products
Answer:
62.12kJ/mol
Explanation:
The neutralization reaction of HCl and NaOH is:
HCl + NaOH → NaCl + H₂O + HEAT
You can find the released heat of the reaction and heat of neutralization (Released heat per mole of reaction) using the formula:
Q = C×m×ΔT
Where Q is heat, C specific heat of the solution (4.06J/gºC), m its mass and ΔT change in temperature (27.5ºC-20.0ºC = 7.5ºC).
The mass of the solution can be finded with the volume of the solution (50.0mL of HCl solution + 50.0mL of NaOH solution = 100.0mL) and its density (1.02g/mL), thus:
100.0mL × (1.02g / mL) = 102g of solution.
Replacing, heat produced in the reaction was:
Q = C×m×ΔT
Q = 4.06J/gºC×102g×7.5ºC
Q = 3106J = 3.106kJ of heat are released.
There are 50.0mL ×1M = 50.0mmoles = 0.0500 moles of HCl and NaOH that are reacting releasing 3.106kJ of heat. That means heat of neutralization is:
3.106kJ / 0.0500mol of reaction =
Answer:but-1-ene
Explanation:This is an E2 elimination reaction .
Kindly refer the attachment for complete reaction and products.
Sodium tert-butoxide is a bulky base and hence cannot approach the substrate 2-chlorobutane from the more substituted end and hence major product formed here would not be following zaitsev rule of elimination reaction.
Sodium tert-butoxide would approach from the less hindered side that is through the primary centre and hence would lead to the formation of 1-butene .The major product formed in this reaction would be 1-butene .
As the mechanism of the reaction is E-2 so it will be a concerted mechanism and as sodium tert-butoxide will start abstracting the primary hydrogen through the less hindered side simultaneously chlorine will start leaving. As the steric repulsion in this case is less hence the transition state is relatively stabilised and leads to the formation of a kinetic product 1-butene.
Kinetic product are formed when reactions are dependent upon rate and not on thermodynamical stability.
2-butene is more thermodynamically6 stable as compared to 1-butene
The major product formed does not follow the zaitsev rule of forming a more substituted alkene as sodium tert-butoxide cannot approach to abstract the secondary proton due to steric hindrance.
Speed of the car =
Given time = 37.0 s
Converting time from seconds to hours:
1 hr= 60 min; 1 min = 60 s
Calculating distance from speed and time:
Converting distance from km to m:
So the distance traveled by the car in 37.0 s is 894 m.
Substance A: 8.2 g/cm3
Substance B: 3.5 cm and 30.0g
Substance C: 10.0g and 40mL
Substance D: 0.5 g/cm3
Substance E: 2.0cm by 3.0cm by 1.0cm and 4.0g
Most Dense_ _ _ _ _
Least Dense
The order of density of substances ranging from most dense to least dense is :substance B>substance A>substance E>substance C>substance D.
It is a ratio of substance's mass per unit of volume.Symbol most commonly used for density is р.The SI unit of densityis kilogram per cubic meter .It explains how tightly a material is packed together.
There are2 types of density :1)absolute density 2) relativedensity.Absolute density is the massof any substance per unit volume and relative density is the ratio of density of a substance to the density of a given reference material.
Reference material used forrelative density is water.The instrument used for measuring density or relative density of liquids is hydrometer. Densityis measured at constant temperature and pressure.
To learn more about density and it's types click here:
#SPJ2
Answer:
So 1st it is B then D then E then a then C
Answer:
10% is a share in NAMSEK worth as a percentage of a share in ODX Group Inc., in year 4
The share of NAMSEK in year 4 is around $ shares (as given from the above table). Hence the value of one share will be $2.5/share
The share of ODX Group Inc., in year 4 is around $ shares (as given from the above table). Hence the value of one share is $
Therefore a share in NAMSEK worth as a percentage of a share in ODX Group Inc., in year 4 will be
= 0.1 or 10 %