Answer:
vague symptoms are characteristic of an acute toxin, because of the of the lack of well defined consistency that these symptoms have in relation to the course of the disease progress.
Answer:
See the attached file for the structure
Explanation:
See the attached file
Answer:
Covalent bond or common bond is one of the types of chemical bonds. This connection arises from electronic participation. In fact, atoms that need to receive electrons to achieve stable electron arrangement (noble gas electron arrangement or octagonal arrangement) share electrons in their valence layer with other atoms. In this case, the transfer of electrons from one atom to another does not take place, but only a pair of electrons, called a bonded or shared electron pair, belongs to the nucleus of two atoms.
Answer:
S = 6.40 × 10⁻⁷ M
Explanation:
In order to calculate the solubility (S) of M(OH)₂ in pure water we will use an ICE Chart. We recognize 3 stages: Initial, Change and Equilibrium, and we complete each row with the concentration or change in concentration.
M(OH)₂(s) ⇄ M²⁺(aq) + 2 OH⁻(aq)
I 0 0
C +S +2S
E S 2S
The solubility product (Kps) is:
Kps = 1.05 × 10⁻¹⁸ = [M²⁺].[OH⁻]²=S.(2S)²
1.05 × 10⁻¹⁸ = 4S³
S = 6.40 × 10⁻⁷ M
Answer: 1.5 m
Explanation: E=mgh=Fh
30 J = 20 N * h
h = 30/20 = 1.5 m
Answer:
1.5 m
Explanation:
it just is its easy made A on test
The reaction forms 0.112 mol H_2.
We have the masses of two reactants, so this is a limiting reactant problem.
We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.
Step 1. Gather all the information in one place with molar masses above the formulas and everything else below them.
M_r: __89.64 ___18.02 ___________2.016
______SrH_2 + 2H_2O → Sr(OH)_2 + 2H_2
Mass/g: 5.00 ___5.47
Step 2. Calculate the moles of each reactant
Moles of SrH_2 = 5.00 g SrH_2 × (1 mol SrH_2 /89.64 g SrH_2)
= 0.055 77 mol SrH_2
Moles of H_2O = 5.47 g H_2O × (1 mol H_2O/18.02 g H_2O)
= 0.3036 mol H_2O
Step 3. Identify the limiting reactant
Calculate the moles of H_2 we can obtain from each reactant.
From SrH_2: Moles of H_2 = 0.055 77 mol SrH_2 × (2 mol H_2 /1 mol SrH_2) = 0.112 mol H_2
From H_2O: Moles of H_2 = 0.3036 mol H_2O × (2 mol H_2/2 mol H_2O)
= 0.3036 mol H_2
SrH_2 is the limiting reactant because it gives the smaller amount of H_2.
It produces 0.112 mol H_2.
Taking into account the definition of ionic and covalent bond, the bonds that chlorine forms with sodium (to form NaCl) and with carbon (to form CCl₄) are different in both compounds.
An ionic bond is a type of chemical bond that occurs when one atom gives up an electron to the other, in order for both to achieve electronic stability.
This union normally occurs between metal and nonmetal elements with different electronegativity, which means that the elements have different capacity to attract electrons.
In other words, an ionic bond is produced between metallic and non-metallic atoms, where electrons are completely transferred from one atom to another. During this process, one atom loses electrons and another one gains them, forming ions. Usually, the metal gives up its electrons forming a cation to the nonmetal element, which forms an anion.
The covalent bond is the chemical bond between atoms where electrons are shared, forming a molecule. Covalent bonds are established between non-metallic elements, such as hydrogen H, oxygen O and chlorine Cl. These elements have many electrons in their outermost level (valence electrons) and have a tendency to gain electrons to acquire the stability of the electronic structure of noble gas.
In the case of NaCl, Na is a metal while Cl is a nonmetal. So NaCl is an ionic bond.
On the other hand, in the case of CCl₄ both C and Cl are two non-metallic elements. So CCl₄ is a covalent bond.
In summary, the bonds that chlorine forms with sodium (to form NaCl) and with carbon (to form CCl₄) are different in both compounds.
Learn more about
ionic bond:
brainly.com/question/24755818?referrer=searchResults
brainly.com/question/24776745?referrer=searchResults
covalent bond:
brainly.com/question/24900155?referrer=searchResults
Answer:
No, NaCl is formed by an ionic bond, and CCl4 would be formed by covalent bonds.
Explanation:
NaCl is an ionic bond because of their opposite charges while carbon and chlorine are sharing their electrons making it a covalent bond.