same number of each kind of atom appears in the reactants and in the products
1. The nitric acid solution will oxidize and thus dissolve _________. This will allow to identify ________.
2. To distinguish between ________, we can use the nickel nitrate
3. The nickel nitrate solution will oxidize and thus dissolve ________ and will not oxidize or dissolve ________.
Options:
a. Zn and Pt
b. Zn, Pb and Pt
c. Pb and Pt
d. Pb
e. Zn
f. Pt
g. Zn and Pb
Answer:
1.) The nitric acid solution will oxidize and thus dissolve _*(Zn and Pb)*_. This will allow to identify _**Pt**_.
2) To distinguish between _*(Zn and Pb)*_, we can use the nickel nitrate.
3) The nickel nitrate solution will oxidize and thus dissolve _**Zn**_ and will not oxidize or dissolve _**Pb**_.
Explanation:
1) Unlike Zinc and Lead, Platinum does not react with Nitric acid. So, it will be the only metal from step 1 that doesn't react. Pt is identified in this manner.
2) Nickel is higher than Lead in the activity series, but Zinc is higher than both of them in the activity series. This selectivity can be used to distinguish between Zinc and Lead metal powders.
3) Because Zinc is higher than Nickel in the activity series, it means that Zinc metal can and will displace Nickel from Nickel Nitrate solution. Therefore the Nickel Nitrate solution will oxidize and dissolve the Zinc metal.
But, there will be no reaction with the Lead metal powders sample as Pb is lower than Ni in the activity series, so, Nickel Nitrate solution will not oxidize or dissolve the Lead metal powders.
Answer : The mass of silver chlorate will be 2.654 grams.
Explanation :
The balanced chemical reaction is,
First we have to calculate the moles of oxygen gas at STP.
As, 22.4 L volume of oxygen gas present in 1 mole of oxygen gas
So, 0.466 L volume of oxygen gas present in mole of oxygen gas
Now we have to calculate the moles of silver chlorate.
From the balanced chemical reaction, we conclude that
As, 3 moles of oxygen produced from 2 moles of silver chlorate
So, 0.0208 moles of oxygen produced from moles of silver chlorate
Now we have to calculate the mass of silver chlorate.
Molar mass of silver chlorate = 191.32 g/mole
Therefore, the mass of silver chlorate will be 2.654 grams.
Answer:
The ratio of solution 1 to solution 2 is 24.20 to 100.00.
Explanation:
We will mix V₁ (L) of solution 1 with V₂ (L) of solution 2 to get the final solution.
So the mole concentration in the final solution is calculated as below, note that C₁ is the concentration of solution 1, and C₂ is the concentration of solution 2
Then we can calculate for the ratio
or
2. A carbon-carbon bond with a bond order of 3
3. A carbon-carbon bond with a bond order of O
4. carbon-carbon bond with a bond order of 1
Answer:
Bond length of C=C is largest(134 pm) because both the carbon atoms have same electronegativity. In case of C=O. and C=N carbon is bonded to highly electronegative atoms so bond length is shoreter as compared to C=C
b) All bases
c) all solvents
d) nonpolar solvents
Answer:
d) Non-polar solvents
Answer:
The new volume of the balloon is 539 L
Explanation:
As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide less times per unit time against them. This means that the pressure will be less because it represents the frequency of gas strikes against the walls. In this way, pressure and volume are related, determining Boyle's law that says:
"The volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure"
Boyle's law is expressed mathematically as:
Pressure * Volume = constant
o P * V = k
Having an initial state 1 and an final state 2 will be fulfilled:
P1 * V1 = P2 * V2
So, in this case, you know:
Replacing:
760 mmHg*200 L= 282 mmHg*V2
Solving:
V2=539 L
The new volume of the balloon is 539 L