As the speed of the particles decreases, intermolecular forces become stronger. Thus, the correct option for this question is A.
The intermolecular forces may be defined as the forces of attraction. that is present between atoms, molecules, and ions when they are placed close to each other in order to form a compound or element. This force is continuously acting on the neighboring particles of different molecules.
It is found that at low temperature, when the speed of molecules/particles decrease, they migrate closer to one another that results in their intermolecular forces that become stronger as compared to the initial one.
As the attraction between molecules gradually increases, their movement decreases, and undergo fewer collisions between them.
Therefore, as the speed of the particles decreases, intermolecular forces become stronger. Thus, the correct option for this question is A.
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Answer:
B
Explanation:
C in CH4 :
H in CH4 :
O in O2 :
C in CO2 :
O in CO2 :
H in H2O :
O in H2O :
Which atom is reduced?
Which atom is oxidized?
The oxidation numbers of the atoms of the specified elements in each of the given atoms are;
1) -4
1) -42) +1
1) -42) +13) 0
1) -42) +13) 04) +4
1) -42) +13) 04) +45) -2
1) -42) +13) 04) +45) -26) +1
1) -42) +13) 04) +45) -26) +17) -2
1) -42) +13) 04) +45) -26) +17) -2Atom oxidized = C
1) -42) +13) 04) +45) -26) +17) -2Atom oxidized = CAtom reduced = O
1) C in CH4
To get the oxidation number of C;
Oxidation state of hydrogen atom is +1 and so if the oxidation state of C is x, then we have;
x + 4(+1) = 0
x + 4 = 0
x = -4
2) H in CH4
Oxidation state on Carbon atom in this case is -4. Thus;
-4 + 4x = 0
4x = 4
x = +1
3) O in O2
This is oxygen gas that exists in it's free state and as such oxidation number is 0.
4) C in CO2
Oxidation state of O here is -2. Thus;
x + 2(-2) = 0
x - 4 = 0
x = +4
5) O in CO2
Oxidation state of C is +4 here. Thus;
4 + 2x = 0
2x = -4
x = -4/2
x = -2
6) H in H2O
Oxidation state of oxygen here is -2. Thus;
2x - 2 = 0
2x = 2
x = 2/2
x = +1
7) O in H2O
Oxidation state of hydrogen here is +1. Thus;
2(1) + x = 0
x = -2
Finally, oxidation number of carbon increased, then it is the atom that was oxidized while the atom reduced is the Oxygen atom.
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Answer:
1. -4
2. +1
3. 0
4. +4
5. -2
6. +1
7. -2
reduced = H
oxidized = O
Explanation:
Know oxidation rules.
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Answer:
1.25 g
Explanation:
Now we have to use the formula;
N/No = (1/2)^t/t1/2
N= mass of cesium-137 left after a time t (the unknown)
No= mass of cesium-137 present at the beginning = 5.0 g
t= time taken for 5.0 g of cesium-137 to decay =60 years
t1/2= half life of cesium-137= 30 years
Substituting values;
N/5= (1/2)^60/30
N/5= (1/2)^2
N/5= 1/4
4N= 5
N= 5/4
N= 1.25 g
Therefore, 1.25 g of cesium-137 will remain after 60 years.
a. 2-keto acid decarboxylase AND alcohol dehydrogenase
b. alcohol dehydrogenase
c. transaminase
d. acetolactate synthasee. 2-ketoacid decarboxylase
Answer:
A. 2-keto acid decarboxylase and alcohol dehydrogenase
Explanation:
2-keto acid decarboxylase and alcohol dehydrogenase are used to produce many higher alcohols. These enzymes also display a high degree of specificity on their substrate
oxygen (O)
carbon (C)
radon (Rn)
The element that has been a halogen from the given elements have been Chlorine. Thus, option A is correct.
Halogen has been given as the group of metallic compounds that have been consisted of the one valence electrons in their last orbitals.
The halogens have been the most reactive elements and belong to group 18 of the periodic table. From the given set of elements, the number of valence electrons in the following has been:
Since the element having 1 valence electron has been Chlorine. Thus, the element that has been a halogen from the given elements have been Chlorine. Thus, option A is correct.
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Answer is chlorine (Cl)
Answer:
Lewis structure of Hydronium ion is shown below :
Explanation:
Lewis structure : It is a representation of valence electrons on the atoms in a molecule
Here , Hydronium ion is given , which contains 1 atom of oxygen and 3 atoms of hydrogen .
Oxygen has a total of 6 valence electrons and hydrogen contains 1 valence electron .
Oxygen share its 3 valence electrons with 3 hydrogen atoms and left with 3 valence electrons. From these three valence electrons of oxygen atom two electrons will be shown as a pair of electrons on oxygen atom but a single electron can not be shown . So , to simplify this, one positive charge is shown overall .
Resonance structure will be same as the hybrid structure because all three atoms are same , that is hydrogen .
Answer:
two atoms of oxygen. For H2O, there is one atom of oxygen and two atoms of hydrogen.