The limiting reagent and the number of S'mores produced for each of the reactions is given below:
Reaction 1. The limiting reagent is Cp; 1.6 S'mores are produced.
Reaction 2. The limiting reagent is M;2 S'mores are produced.
Reaction 3. The limiting reagent is Gc; 2.5 S'mores are produced.
Reaction 4. The limiting reagent is M;1 S'more is produced.
The equation of the reaction shows the stoichiometry between reactants and products.
For the given reaction, the equation of reaction is as follows:
1M + 2Gc + 3Cp ----> 1Gc2MCp3
where:
From the equation of reaction:
The stoichiometric equation is: 2Gc + 1M + 3Cp ----> 1Gc2MCp3
The ratio of Gc to M to Cp is 2 : 1 : 3
Reaction 1. 4 Gc + 2M + 5 Cp
The ratio of Gc to M to Cp in the reaction above is 2 : 1 : 2.5
3 Cp makes 1 S'more
5 Cp will make 5 * 1/3 S'more = 1.6 S'mores
Reaction 2. 6 Gc + 2M + 9 Cp
The ratio of Gc to M to Cp in the reaction above is 3 : 1 : 4.5
1 M makes 1 S'more
2 Cp will make 2 * 1/1 S'more = 2 S'mores
Reaction 3. 5 Gc + 3M + 9 Cp
The ratio of Gc to M to Cp in the reaction above is 1.6 : 1 : 3
2 Gc makes 1 S'more
5 Gc will make 5 * 1/2 S'more = 2.5 S'mores
Reaction 4. 7 Gc + 1M + 6 Cp
The ratio of Gc to M to Cp in the reaction above is 7 : 1 : 6
Therefore the limiting reagent is M
1 M makes 1 S'more
The limiting reagent and the number of S'mores produced for each of the reactions is given below:
1. The limiting reagent is Cp; 1.6 S'mores are produced.
2. The limiting reagent is M;2 S'mores are produced.
3. The limiting reagent is Gc; 2.5 S'mores are produced.
4. The limiting reagent is M;1 S'more is produced.
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Answer:
There are currently a variety of advanced medical treatment screening programs for certain types of cancer that have resulted in more people having a better chance of healing or living longer.
Explanation:
Exercise helps cancer survivors cope with and recover from treatment; exercise may improve the health of long term cancer survivors and extend survival. Physical exercise will benefit throughout the spectrum of cancer. However, an understanding of the amount, type and intensity of exercise needed has not been fully elucidated. There is sufficient evidence to promote exercise in cancer survivors following careful assessment and tailoring on exercise prescription.
"The field of oncology will benefit from understanding the importance of physical activity both for primary prevention as well as in helping cancer survivors cope with and recover from treatments, improve the health of long term cancer survivors and possibly even reduce the risk of recurrence and extend survival after a cancer diagnosis" (P. Rajarajeswaran, R. Vishnupriya)
Additional studies will be needed to more firmly establish physical activity benefits to cancer survivors.
Exercise is key both in the prevention and treatment of cancer, since it improves the quality and life expectancy of patients.
How would you market your services to clients that have cancer?
The benefits of exercise against cancer are innumerable: it helps prevent it, reduces the side effects of chemotherapy and radiotherapy, decreases cancer recurrence, improves vital energy, mobility and balance and reduces fatigue, maintains muscle mass, improves self-esteem and sleep quality, decreases the level of anxiety, depression and stress.
No one doubts the importance of physical activity, exercise and sport in global health, in the prevention and even in the treatment of numerous diseases. Among these diseases is cancer. There are more than 10,000 scientific publications that have studied the links between exercise and cancer and almost all of them with positive results regarding the prevention of numerous types of tumors, the decrease in cancer recurrence and the best prognosis of the latter if You exercise.
It is scientifically proven that properly prescribed physical exercise can be performed without risk during and after chemotherapy and radiotherapy treatments. However, it is necessary to adjust its intensity, duration, weekly frequency and type of exercise to the general condition of the patient. Physical exercise will improve the quality of life, fatigue and mood of the cancer patient being treated. It will also improve the prognosis of the disease, its quality of future life and its final life expectancy.
Research the benefits and risks of exercise and youth.
The benefits of physical activity and sports in young people imply a better physical condition, but also plays a fundamental role from the psychological and social. Every healthy habit is best incorporated from childhood, so that it becomes natural and everyday and improves the quality of life of our future adults.
The benefits of physical activity in youth are several:
Children and young people should perform daily physical activities in the form of commuting, games, recreational activities, physical education, programmed exercises and sports, in the context of school and clubs, if possible integrating other family members.
B. -1,+1,0
C. -2,+3,-1
D. 0,0,0
Three resonance structures contribute to the structure of dinitrogen monoxide.
The resonance structure is invoked when a single structure can not sufficiently explain all the bonding properties of a compound. All the various contributing structures contribute to the final structure of the compound but not all to the same degree.
There are three resonance structures of dinitrogen monoxide. The most stable structure is always the structure that has the formal charges as -1, +1 and zero as shown.
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Answer:
A. 0, +1, -1
Explanation:
You can draw the lewis structure for NNO 3 ways: With two double bonds N=N=O, with a triple bond between the N and O and single bond between the two N's, or a triple bond between the two N's and a single bond between the N and O.
The goal is to have formal charges that are as small as possible, to have no identical formal charges on adjacent atoms, and to have the most negative formal charge on the most electronegative atom. The most stable structure is the one with the triple bond between the two N's because it gives the formal charges 0, 1, and -1 respectively. Unlike the other two structures, the negative formal charge is correctly placed on O, the most electronegative atom.
(liquid)
Pressure (atm)
0.5-
0.25
Ice
(solid)
Water vapor
(gas)
0
000
Temperature (°C)
O A. Gas
O B. Solid and gas
O C. Solid and liquid
D. Solid
Water is in the solid phase at 0.25 atm and 0°C.
A pressure of 50 kPa and a temperature of 50 °C correspond to the “water” region—here, water exists only as a liquid. At 25 kPa and 200 °C, water exists only in the gaseous state.
Under standard atmospheric conditions, water exists as a liquid. But if we lower the temperature below 0 degrees Celsius, or 32 degrees Fahrenheit, water changes its phase into a solid called ice.
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#SPJ2
in 5.164 g of Call2?
Answer:
1.06x10²² formula units
Explanation:
First we convert 5.164 g of CaI₂ into moles, using its molar mass:
Then we convert 0.0176 moles into formula units, using Avogadro's number, which relates the number of formula units present in 1 mol:
Given:
Radiation emission in Cs atom = 9,192,632,770 cycles
To determine:
The wavelength of the above radiation
Explanation:
It is given that :-
1 sec equivalent to 9,192, 631, 770
Now, frequency (ν) = cycles /sec = 9,192, 631, 770/sec
Wavelength of a radiation is given as:
λ = c/ν
where c = speed of light = 3*10⁸ m/s
λ = 3*10⁸ ms⁻¹/9,192, 631, 770 s⁻¹ = 0.0326 m
Ans: Thus the wavelength of this radiation is 0.033 m
Answer:
The specific heat of magnesium is 1.04 J/g°C.
Explanation:
Heat lost by the magnesium = Q
Mass of the magnesium = m = 62.08 g
Heat capacity of magnesium= c = ?
Initial temperature of the magnesium =
Final temperature of the magnesium= T = 35.60 °C
Heat absorbed by coffee cup calorimeter = Q'
Heat capacity of coffee cup calorimeter = C = 1.79 J/°C
Initial temperature of coffee cup calorimete = = 23.19°C
Final temperature of coffee cup calorimete = T = 35.60 °C
Heat absorbed by the water = q
Mass of water = m' = 77.81 g
Heat capacity of water = c' = 4.18 J/g°C
Initial temperature of water = = 0°C
Final temperature of water = T
According law of conservation of energy , energy lost by coffee will equal to heat required to raise temperature of water and coffee cup calorimeter.
On solving we get:
c = 1.04 J/g°C
The specific heat of magnesium is 1.04 J/g°C.