Round each answer to the number of significant figures in the parentheses.
Round each answer to the number of significant figures in - 1

Answers

Answer 1
Answer:

Answer:

87.100. 4.4000. 0.012000. 9000. 6,040,850. 630.00. 100.1000. 0.00024000


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Inside a calorimeter, two solutions are mixed and result in an endothermic reaction. Which of the following best illustrates how this reaction affects the water in the calorimeter? (2 points)Select one: a. The reaction has no effect on the water. The kinetic energy of the water molecules remains the same. b. The reaction causes the temperature of the water to increase. The kinetic energy of the water molecules increases. c. The reaction causes the temperature of the water to decrease. The kinetic energy of the water molecules decreases. d. The reaction causes the temperature of the water to decrease. Then, the water gains heat from the surroundings and the kinetic energy of the water molecules increases.

Write Lewis structural formulas for the following molecules: NH3 SO2
CH3OH HNO2
N2 CH2O

Answers

Answer :  The Lewis-dot structure of the following molecules are shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

(1) The given molecule is, NH_3

As we know that hydrogen has '1' valence electron, nitrogen has '5' valence electrons.

Therefore, the total number of valence electrons in NH_3 = 5 + 3(1)  = 8

According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.

(2) The given molecule is, SO_2

As we know that sulfur and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in SO_2 = 6 + 2(6)  = 18

According to Lewis-dot structure, there are 8 number of bonding electrons and 10 number of non-bonding electrons.

(3) The given molecule is, CH_3OH

As we know that carbon has '4' valence electrons, hydrogen has '1' valence electron and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in CH_3OH = 4 + 4(1) + 6  = 14

According to Lewis-dot structure, there are 10 number of bonding electrons and 4 number of non-bonding electrons.

(4) The given molecule is, HNO_2

As we know that hydrogen has '1' valence electron, nitrogen has '5' valence electrons and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in HNO_2 = 1 + 5 + 2(6) = 18

According to Lewis-dot structure, there are 8 number of bonding electrons and 10 number of non-bonding electrons.

(5) The given molecule is, N_2

As we know that nitrogen has '5' valence electrons.

Therefore, the total number of valence electrons in N_2 = 2(5) = 10

According to Lewis-dot structure, there are 6 number of bonding electrons and 4 number of non-bonding electrons.

(6) The given molecule is, CH_2O

As we know that carbon has '4' valence electrons, hydrogen has '1' valence electron and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in CH_2O = 4 + 2(1) + 6  = 12

According to Lewis-dot structure, there are 8 number of bonding electrons and 4 number of non-bonding electrons.

An aqueous CsCl solution is 8.00 wt% CsCl and has a density of 1.0643 g/mL at 20°C. What is the boiling point of this solution? Kb = 0.51°C/m for water. Enter your answer with 2 decimal places and no units.

Answers

Answer: The boiling point of solution is 100.53

Explanation:

We are given:

8.00 wt % of CsCl

This means that 8.00 grams of CsCl is present in 100 grams of solution

Mass of solvent = (100 - 8) g = 92 grams

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

Or,

\text{Boiling point of solution}-\text{Boiling point of pure solution}=i* K_b* \frac{m_(solute)* 1000}{M_(solute)* W_(solvent)\text{ (in grams)}}

where,

Boiling point of pure solution = 100°C

i = Vant hoff factor = 2 (For CsCl)

K_b = molal boiling point elevation constant = 0.51°C/m

m_(solute) = Given mass of solute (CsCl) = 8.00 g

M_(solute) = Molar mass of solute (CsCl) = 168.4  g/mol

W_(solvent) = Mass of solvent (water) = 92 g

Putting values in above equation, we get:

\text{Boiling point of solution}-100=2* 0.51^oC/m* (8.00* 1000)/(168.4g/mol* 92)\n\n\text{Boiling point of solution}=100.53^oC

Hence, the boiling point of solution is 100.53

If atoms contain charged particles, why do they not have a charge?

Answers

Answer:

every atom has no overall charge. because they contain equal numbers of positive protons and negative electrons. they cancel each other out making them a neutral atom.

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Answers

Microphone thing is a little bit better but it was ok I gotta it looked good but it didn’t get me wrong it I made a comment on my phone number so ttyttttytt was the day I wanna was a good day and then I’ll send ya my stuff and I get to see ya my mom stuff is the best thing ever I just wanna was a

A student puts 0.020 mol of methyl methanoate into an empty and rigid 1.0 L vessel at 450 K. The pressure is measured to be 0.74 atm. When the experiment is repeated using 0.020 mol of ethanoic acid instead of methyl methanoate, the measured pressure is lower than 0.74 atm. The lower pressure for ethanoic acid is due to the following reversible reaction.CH3COOH(g)+CH3COOH(g) ⇋ (CH3COOH)2(g)+Assume that when equilibrium has been reached, 50 percent of the ethanoic acid molecules have reacted.i. Calculate the total pressure in the vessel at equilibrium at 450 K.ii. Calculate the value of the equilibrium constant, Kp, for the reaction at 450 K

Answers

Explanation:

Starting moles of ethanol acid = 0.020 mol

At the equilibrium 50 % of the ethanol acid molecules reacted

∴ Moles of ethanol acid reacted = 0.020 mol * 50 %/100 %

                                                                   = 0.010 mol

Moles of ethanol acid remain = 0.020 mol + 0.010 mol = 0.010 mol

Moles of the product (CH3COOH)^(2) gas formed are calculated as

0.010 mol CH3COOH * 1 mol (CH3COOH)^(2) / 2 mol CH3COOH

= 0.005 mol (CH3COOH)^(2)

Therefore at the equilibrium total moles of gas present in the vessel are 0.010 mol CH3COOH and 0.005 mol (CH3COOH)^(2)

That is total gas moles at equilibrium = 0.010 mol + 0.005 mol = 0.015 mol

Now Calculate the pressure  :

0.020 mol gas has pressure of 0.74 atm therefore at the same condition what will be the pressure exerted by 0.015 mol gas

P1/n1 = P2/n2

P2 = P1*n2 / n1

      = 0.74 atm * 0.015 mol / 0.020 mol

     = 0.555 atm

Predict the products and write balanced net ionic equations for the following reactions. (g) SnCl2 is added to KMnO4 solution (acidic) forming Mn2

Answers

The product and balanced net ionic equations for the following reactions are SnCl₂  +  2KMnO₄ ⇒ 2 KCl + Sn(MnO₄)₂.

What is the net ionic equation?

Ionic equations are those equations that happened in an aqueous solution. The chemical equation is expressed in an electrolyte solution is expressed and dissociates ions.

In these reactions, each element or ion is dissociated into differently charged ions in a solution. Each of the ions is shown with different charges.

SnCl₂  +  2KMnO₄ ⇒ 2 KCl + Sn(MnO₄)₂. In the reaction, the tin chloride, and potassium magnesium oxide. It dissociates into charged ions, like potassium chloride and tin magnesium oxide. The chlorine will acquire a negative charge and magnesium oxide get a positive charge.

Thus, the net ionic equation is SnCl₂  +  2KMnO₄ ⇒ 2 KCl + Sn(MnO₄)₂.

To learn more about the ionic equation, refer to the link:

brainly.com/question/15466794

#SPJ2

Answer:

The answer to your question is:

Explanation:

Reaction

                  SnCl₂    +    2KMnO₄     ⇒    2 KCl     +    Sn(MnO₄)₂

                                               1 ----   Sn ----  1

                                               2 ----   K  ----- 2

                                               2 ----  Mn ----  2

                                               8 ----    O ----  8

                                               2 ----   Cl ----  2