Answer:
?=0.522
Explanation:
5.22*10^-3=?*10^-2
5.22*0.01=?*0.1
0.522=?
This is my first time answer question, thx!
Answer:
0.522
Explanation:
Answer:
76.0 years
Explanation:
Step 1: Given data
Step 2: Calculate the rate constant (k)
We will use the following expression.
k = ln 2/ t1/2 = ln 2 / 12.0 y = 0.0578 y⁻¹
Step 3: Calculate the time elapsed
For a first-reaction order, we will use the following equation.
ln [A]/[A]₀ = -k × t
t = ln [A]/[A]₀ / (-k)
t = (ln 10.0 ppbm/809 ppbm) / (-0.0578 y⁻¹)
t = 76.0 y
Answer:
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 4 g
volume = 2 cm³
We have
We have the final answer as
Hope this helps you
Answer:
2.11 molecules of CO₂
Explanation:
Given data:
Mass of CO₂ = 15.2 g
Molecules of CO₂ = ?
Solution:
Number of moles of CO₂:
Number of moles = mass/molar mass
Number of moles = 15.2 g/ 44 g/mol
Number of moles = 0.35 mol
Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.
1 mole = 6.022 × 10²³ molecules
0.35 mol × 6.022 × 10²³ molecules / 1 mol
2.11 molecules of CO₂
When Americium (Am-241) undergoes alpha decay(He-4) it forms neptunium (Np-237) based on the following pathway:
²⁴¹Am₉₅ → ²³⁷Np₉₃ + ⁴He₂
The energy released in given as:
ΔE = Δmc²
where Δm = mass of products - mass of reactants
= [m(Np-237) + m(He-4)] - [m(Am-241)]
= 237.0482+4.0015-241.0568 = -0.0073 g/mol = -7.3 * 10⁻⁶ kg/mol
ΔE = -7.3*10⁻⁶ kg/mol * (3*10⁸ m/s)² = -5.84*10¹¹ J/mol
(c) Why might the suggestion for part (b) be of benefit to middle-distance runners?
Answer:
a) [HCO₃⁻] = 10,2 mM.
b) Sodium bicarbonate.
c) Yes.
Explanation:
a) The equilibrium of this reaction is:
CO₂ + H₂O ⇄ HCO₃⁻ + H⁺
Using Henderson-Hasselbalch equation:
pH = pka + log₁₀
Replacing:
7,03 = 6,1 + log₁₀
Thus, [HCO₃⁻] = 10,2 mM
b) A possible treatment of metabolic acidosis is with sodium bicarbonate. By Le Chateleir's principle the increasing of HCO₃⁻ will shift the equilibrium to the left decreasing thus, H⁺ concentration.
c) The shifting of the equilibrium to the left will increase CO₂ concentration producing in the body the need to increase breathing, increasing, thus, concentration of O₂ improving cardiac function in exercise.