The drama club spent $8.50 per person on food for a cast party. The total cost of the flood was $229.50. How many people were at the cast party?

Answers

Answer 1

Answer:

Answer:

229.50 ÷ 8.50= 27 people

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Does anyone know the answer???
Write the equation in standard form using integers y=3x+8
Which of the graphs best represents a system of equations that has no solution? A) Graph A B) Graph B C) Graph C D) Graph D

You are to take a multiple-choice exam consisting of 100 questions with 5 possible responses to each question. Suppose that you have not studied and so must guess (select one of the five answers in a completely random fashion) on each question. Let x represent the number of correct responses on the test. (a) What is your expected score on the exam? (Hint: Your expected score is the mean value of the x distribution.) (b) Compute the variance and standard deviation of x. Variance = Standard deviation =

Answers

Answer:

a) 20

b) Variance 16, standard deviation 4

Step-by-step explanation:

For each question, there are only two possible outcomes. Either you guesses the answer correctly, or you do not. The probability of guessing the answer of a question correctly is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

$E(X) = np$

The variance of the binomial distribution is:

$V(X) = np(1-p)$

The standard deviation of the binomial distribution is:

$√(V(X)) = √(np(1-p))$

100 questions

So n = 100.

You guess

5 options, one correct. So $p = (1)/(5) = 0.2$

(a) What is your expected score on the exam?

$E(X) = np = 100*0.2 = 20$

(b) Compute the variance and standard deviation of x.

Variance:

$V(X) = np(1-p) = 100*0.2*0.8 = 16$

Standard deviation:

$√(V(X)) = √(16) = 4$

If there are 100 cm in
1 meter, how many
centimeters are in 6
meters?

Answers

Answer:

there are 600 cm in 6 meters

Answer: 600 cm

Step-by-step explanation:

100cm = 1 m

Then ? cm = 6m

Since cm is smaller than m, cm would need more to be equal or equivalent to m. Therefore we say, what multiply by 1m gives you 6m? Because they are asking for 6m. Whatever you do to one side you do to the other.

6(100)cm = 6(1) m

600cm = 6m

A college professor states that this year's entering students appear to be smarter than entering students from previous years. The college's records indicate that the mean IQ for entering students from earlier years. is 110.3. Suppose we want to sample a smaller number of this year's entering students and carry out a hypothesis test to see if the professor statement can be supported. State the null and alternative hypothesis.

Answers

Answer:

$H_(0)$ : μ = 110.3

$H_(a)$ : μ > 110.3

Step-by-step explanation:

Let μ be the mean IQ of this year's entering students.

Then null and alternative hypotheses are:

$H_(0)$ : μ = 110.3 (this year's students mean IQ is at most the mean IQ of the entering students from previous years)

$H_(a)$ : μ > 110.3 (this year's students mean IQ is higher than the mean IQ of the entering students from previous years)

Please help me with this problem

Answers

I think the answer is A. Hope this help

A is the answer
So your welcome

What percentage is 125 from 1000

Answers

Answer:

12.5%

Step-by-step explanation:

125 is 12.5% of 1000

Find an equation of the line described. Write the equation in slope-intercept form when possible. Slope 1, through (-4,3)

Answers

The equation of the line:

$y=mx+b$

The point-slope form of the equation of the line:

$y-y_1=m(x-x_1)$

We have:

$m=1\ and\ A(-4;\ 3)\to x_1=-4\ and\ y_1=3$

Substitute:

$y-3=1(x-(-4))\n\ny-3=x+4\ \ \ |+3\n\n\boxed{y=x+7}$

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A study is being conducted to compare the average training time for two groups of airport security personnel: those who work for the federal government and those employed by private security companies. From a random sample of 12 government-employed security personnel, average training time was 72 hours, with a sample standard deviation of 8 hours. In a random sample of 16 privately employed security personnel, training time was 65.4 hours, with a sample standard deviation of 12.3 hours. Assume that training time for each group is normally distributed. Use the following notations:μ1: The mean training time for the population of airport security personnelemployed by the federal government.μ2: The mean training time for the population of airport security personnelemployed by private security companies.The goal of the statistical analysis is to determine whether the sample data support the hypothesis that average training time for government-employed security personnel is higher than those employed by private security companies.1. What is the null hypothesis H0?Select one:a. μ1- μ2 <= 0b. μ1- μ2 < 0c. μ1- μ2 =/ 0d. μ1- μ2 > 02. What is the alternative hypothesis Ha?Select one:a. μ1- μ2 > 0b. μ1- μ2 <= 0c. μ1- μ2 = 0d. μ1- μ2 >= 0

If ST=19 and S lies at -4 , where could T be located?