Write the equation in standard form using integers y=3x+8

Answers

Answer 1

Answer:

Answer:

3x − y = −8

Step-by-step explanation:

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PLEASE HELP I WILL GIVE BRAINLIST!!!!!!!!!!!!Change to the fractional equivalent. 0.7777777... Be sure to simplify your
answer.

Answers

Answer:

7/9

Step-by-step explanation:

7 divided by 9 is .7777777777....

Margaret said the exact product of 602 and 341 is 205,282. Is she correct? Use paper and the standard algorithm to support your reasoning.

Answers

Answer:

Yes, she is. The exact product of 602 and 341 is 205,282.

Step-by-step explanation:

To determine the exact product of 602 and 341, both numbers must be multiplied, obtaining the result. To do this, said number can be decomposed, to facilitate the operation and to be able to corroborate the accuracy of the result.

So, we can multiply 602 by 300, plus 602 by 40 and 602 by 1, and add the results.

Therefore, since 602 times 300 is equal to 180,600 (602 x 300 = 180,600); that 602 times 40 is equal to 24,080 (602 x 40 = 24,080); and since 602 times 1 is equal to 602, all those values must be added.

So 180,600 plus 24,080 equals 204,680. And in turn, 204,680 plus 602 equals 205,282. Therefore, the proposed result is correct.

What is 785 divided by 345 i need some help

Answers

Answer:

2.3

Step-by-step explanation:

Divide 785 by 345 and round it to the nearest tenth.

Find the range, variance, and standard deviation for the given sample data. Include appropriate units in the results.Listed below are the measured radiation absorption rates (in W/kg) corresponding to various cell phone models. If one of each model is measured for radiation and the results are used to find the measures of variation, are the results typical of the population of cell phones that are in use?
0.950.95
0.730.73
0.630.63
0.910.91
1.321.32
1.481.48
0.630.63
1.231.23
0.910.91
1.411.41
0.670.67
The range of the sample data is
nothing
▼
(Round to three decimal places as needed.)
Sample standard
deviationequals=nothing
▼
kg.kg.
left parenthesis Upper W divided by kg right parenthesis squared .W/kg2.
W.W.
Upper W divided by kg.W/kg.
(Round to three decimal places as needed.)
Sample
varianceequals=nothing
▼
kg.kg.
left parenthesis Upper W divided by kg right parenthesis squared .W/kg2.
Upper W divided by kg.W/kg.
W.W.
(Round to three decimal places as needed.)
If one of each model is measured for radiation and the results are used to find the measures of variation, are the results typical of the population of cell phones that are in use?
A. No, because it is necessary to have at least 5 of each cell phone in order to get a meaningful result. Only including one of each cell phone model is not representative of each cell phone model.
B. Yes, because the results from any sample of cell phones will be typical of the population.
C. Yes, because each model is being represented in the sample. Any sample that considers all possible cell phone models will produce results typical of the population of cell phones.
D. No, because some models of cell phones will have a larger market share than others. Measures from different models should be weighted according to their size in the population.

Answers

Answer:

$Range = 1.48-0.63=0.850 W/kg$

$s= 0.320 W/Kg$

$s^2 = 0.320^2= 0.103 W^2 /kg^2$

D. No, because some models of cell phones will have a larger market share than others. Measures from different models should be weighted according to their size in the population.

Step-by-step explanation:

For this case we have the following data values:

0.95,0.73,0.63,0.91,1.32,1.48,0.63,1.23,0.91,1.41,0.67

The first step on this case is order the datase on increasing way and we got:

0.63 0.63 0.67 0.73 0.91 0.91 0.95 1.23 1.32 1.41 1.48

The range is defined as $Range = Max-Min$

And if we replace we got:

$Range = 1.48-0.63=0.850 W/kg$

The sample standard deviation is given by this formula:

$s= \sqrt{(\sum_(i=1)^n (X_i -\bar X)^2)/(n-1)}$

And if we replace we got $s= 0.320 W/Kg$

And the sample variance is just the standard deviation squared so we got:

$s^2 = 0.320^2= 0.103 W^2 /kg^2$

And for the last question about : If one of each model is measured for radiation and the results are used to find the measures of variation, are the results typical of the population of cell phones that are in use?

We can conclude this:

D. No, because some models of cell phones will have a larger market share than others. Measures from different models should be weighted according to their size in the population.

Use the numbers from 1 to 9 to fill in the blanks to get the smallest possible answer.