MATHEMATICS COLLEGE

The bar diagram represents the ratio of points scored by the home team and the visiting team in a basket ball game. How many points did the visiting team score if the home team scored 84 points?

Answers

Answer 1

Answer:

Answer:

60 points.

Step-by-step explanation:

Bar diagram which represents the ratio of the points earned by the home team and visitor's team.

Fro the bar diagram,

Ratio of the points earned = $\frac{\text{Points earned by the home team}}{\text{Points earned by visitor's team}}$

= $(7)/(5)$

If the points earned by the home team = 84

$\frac{\text{Points earned by the home team}}{\text{Points earned by visitor's team}}$ = $(7)/(5)$

$\frac{84}{\text{Points earned by visitor's team}}$ = $(7)/(5)$

Points earned by the visitor's team = $(84* 5)/(7)$

= 60

Therefore, 60 points were earned by the visitor's team.

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During the period of time that a local university takes phone-in registrations, calls come inat the rate of one every two minutes.a. What is the expected number of calls in one hour?b. What is the probability of three calls in five minutes?c. What is the probability of no calls in a five-minute period?
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Amy goes to a pumpkin patch and picks out a pumpkin that weighs 3,550 grams. If 1 gram = 0.0352 ounces, how many ounces does the pumpkin weigh? A) 124.56 ounces
B) 124.96 ounces
C) 125.56 ounces
D) 125.96 ounces

Answers

9514 1404 393

Answer:

B) 124.96 ounces

Step-by-step explanation:

To find ounces, multiply the number of grams by the number of ounces in each gram.

3550 × 0.0352 = 124.96 . . . ounces

How do you solve the equation 2cos^2 - cosx = 0 for all solutions?

Answers

Answer:

π/2 and π/3

Step-by-step explanation:

Given the equation 2cos²x - cosx = 0, to find the solution to the equation, we will follow the following step.

let P = cosx

The equation becomes 2P²-P = 0

P(2P-1) = 0

P = 0 and 2P-1 = 0

P= 0 and P = 1/2

Since P = cosx

cosx = 0 and cos(x) = 1/2

If cos(x) = 0

x = cos⁻¹0

x = 90⁰

x = π/2

If cos(x) = 1/2

x = cos⁻¹1/2

x = 60⁰

x = π/3

Hence the solutions to the equation are π/2 and π/3.

Describe how the graph of y | x| -4 is like the graph of y= |x| and how it is different.

Answers

The graph y=|x|-4 is obtained from the graph y=|x| dy moving down 4 units the graph y=|x| along the y-axis (see, if x=0, then for y=|x|, y=0 and for y=|x|-4, y=-4).

These two graphs have the same form.

Answer:

The graph of y=|x|-4 is the same as y=|x|.

Step-by-step explanation:

WRITE THE expression in complete factored form 2y^2(p-4)-7(p-4)

Answers

For this case we have the following expression:
2y ^ 2 (p-4) -7 (p-4)
The first thing you should observe is the similar terms in both parts of the expression.
We note that the term (p-4) is repeated in both parts of the expression.
Therefore, by doing common factor (p-4) we have:
(p-4) (2y ^ 2-7)
Answer:
The expression in complete factored form is:
(p-4) (2y ^ 2-7)

p - 4 is common to the 2 parts so we have

(2y^2 - 7)(p - 4) Answer

The image of a parabolic lens is traced onto a graph. The function f(x) = 1/4 (x+8)(x-4) represents the image. Atwhich points does the image cross the x-axis?

O (-8, 0) and (4,0)
(8,0) and (-4, 0)
O (2, 0) and (-1,0)
O (-2, 0) and (1, 0)

Answers

The image of the parabolic lens crosses the x axis at the points

(-8, 0) and (4, 0)

How to find the points where the image cross x axis

To find the points where the graph of the function crosses the x axis we need to find the values of x that make f(x) equal to zero

hence we have that

f(x) = 1/4 (x + 8) (x - 4)

0 = 1/4 (x + 8) (x - 4)

x + 8 = 0

x = -8

x - 4 = 0

x = 4

hence we can say that the image of the parabolic lens crosses the x axis at the points (-8, 0) and (4, 0)

Learn more about parabolic lens at

brainly.com/question/24079297

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The height h, in feet, of a ball that is released 4 feet above the ground with an initial velocity of 80 feet per second is a function of the time t, in seconds, the ball is in the air and is given byh(t)=-16t^2+80t+4, 0 < t < 5.04

a. Find the height of the ball above the ground 2 seconds after it is released.

b. Find the height of the ball above the ground 4 seconds after it is released.

Please show work!