Taking into account the definition of ionic and covalent bond, the bonds that chlorine forms with sodium (to form NaCl) and with carbon (to form CCl₄) are different in both compounds.
An ionic bond is a type of chemical bond that occurs when one atom gives up an electron to the other, in order for both to achieve electronic stability.
This union normally occurs between metal and nonmetal elements with different electronegativity, which means that the elements have different capacity to attract electrons.
In other words, an ionic bond is produced between metallic and non-metallic atoms, where electrons are completely transferred from one atom to another. During this process, one atom loses electrons and another one gains them, forming ions. Usually, the metal gives up its electrons forming a cation to the nonmetal element, which forms an anion.
The covalent bond is the chemical bond between atoms where electrons are shared, forming a molecule. Covalent bonds are established between non-metallic elements, such as hydrogen H, oxygen O and chlorine Cl. These elements have many electrons in their outermost level (valence electrons) and have a tendency to gain electrons to acquire the stability of the electronic structure of noble gas.
In the case of NaCl, Na is a metal while Cl is a nonmetal. So NaCl is an ionic bond.
On the other hand, in the case of CCl₄ both C and Cl are two non-metallic elements. So CCl₄ is a covalent bond.
In summary, the bonds that chlorine forms with sodium (to form NaCl) and with carbon (to form CCl₄) are different in both compounds.
Learn more about
ionic bond:
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covalent bond:
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Answer:
No, NaCl is formed by an ionic bond, and CCl4 would be formed by covalent bonds.
Explanation:
NaCl is an ionic bond because of their opposite charges while carbon and chlorine are sharing their electrons making it a covalent bond.
Answer:
The correct answer is 1.10.
Explanation:
Based on the given information, the molarity of the NaOH is 0.15 M, that is, 0.15 moles per liter of the solution.
Now the moles present in the 15 ml of the solution will be,
0.015 × 0.15 = 2.25 × 10⁻³ moles of NaOH or 0.0025 moles of NaOH
Now, molarity of the HNO₃ given is 0.20 M, which means 0.2 moles per liter of the solution.
Now the moles present in the 30 ml of the solution will be,
0.030 × 0.2 = 0.006 moles of HNO₃
Now the complete disintegration of acid and base will be,
NaOH (aq) (0.025 moles) ⇔ Na⁺ (aq) (0.025) + OH⁻ (aq) (0.025 moles)
HNO₃ (aq) (0.006 moles) ⇔ H⁺ (0.006 moles) + NO₃⁻ (aq) (0.006 moles)
Now the additional Hydrogen ions at titration point is,
= 0.006 - 0.0025 = 0.0035 moles of H+
Now the concentration of H+ ions in the 45 ml of the solution will be,
= 0.0035/45 × 1000
= 0.078 M
pH = -log[H⁺] = -log [0.078]
= 1.10
Answer:
1. micro
2. centi
3. milli
4. kilo
Explanation:
Prefixes, in mathematical exponents, are defined as the alphabetical names associated with the mathematical factors. Some examples are as follows:
10⁶ = Mega
10⁹ = Giga
10⁻⁹ = Nano
10⁻¹² = Pico
So, in order to name the metric system prefixes associated with each of the given mathematical factor, we first convert the factor into exponent form and then write its prefix, as follows:
10⁻⁶ = micro
1/100 = 0.01 = 1 x 10⁻² = centi
0.001 = 1 x 10⁻³ = milli
1000 = 1 x 10³ = kilo
Answer:
The correct answer is D.
Explanation:
Water can evaporate, and if it does, the density decreases
Answer:
Explanation:
Hexanoic acid [CH 3(CH 2) 4COOH] is barely soluble in water (about 1.0 g/100 g of water). Palmitic acid [CH 3(CH 2) 14COOH], with its large nonpolar hydrocarbon component, is essentially insoluble in water. The carboxylic acids generally are soluble in such organic solvents as ethanol, toluene, and diethyl ether.
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