CHEMISTRY COLLEGE

Which best explains why an iceberg floats?Water expands and becomes denser when it freezes.

Water contracts and becomes denser when it freezes.

Answers

Answer 1

Answer:

The options to this question are incomplete. The remaining two options are:

C. Water expands and becomes less dense when it freezes.

D. Water contracts and becomes less dense when it freezes.

The answer is C. Water expands and becomes less dense when it freezes.

Explanation:

Water is a chemical compound that exists in the three states of matter viz: solid as ICE, gas as vapour and liquid as WATER. However, due to the DENSITY properties of each state, ice floats on water. Ice is less dense than water.

When liquid water freezes, it's particles expands i.e increases in volume. Hence, it becomes less dense than water. This causes an iceberg to float on water because it has a lesser density compared to the liquid water caused by an expansion of its particles.

Related Questions

HELP ASAP WHICH ONE IS THE ANSWE A OR B OR C OR D ???? ! !!!
The correct electron configuration for magnesium is: 1s 22s 22p 63s 3 True False
What is the freezing point (°C) of a solution prepared by dissolving 11.3 g of Ca(NO3)2 (formula weight = 164 g/mol) in 115 g of water? The molal freezing point depression constant for water is 1.86 °C/m.
Does the density of a liquid depend on its volume? Write your answer as a CER.
A 0.5-m3 rigid tank contains refrigerant-134a initially at 200 kPa and 40 percent quality. Heat is transferred now to the refrigerant from a source at 358C until the pressure rises to 400 kPa. Determine (a) the entropy change of the refrigerant, (b) the entropy change of the heat source, and (c) the total entropy change for this process.

Which compound contains covalent bonds?A - BeO
B- NaCl
C- CaS
D- MgF2
E - SO2

Answers

Answer:

Explanation:

Thus is because both the elements are non metals.

Answer:

SO2

Explanation:

SO2 is covalent since it is formed by the sharing of electrons between sulphur and oxygen also both the sulphur and oxegen atoms are non metal.

and we know that non-metal non-metal always bond together via covelent bonding

How many grams of chloride are there in 256 g of magnesium chloride?

Answers

Given :

Mass of given magnesium chloride, m = 256 g.

To Find :

How many grams of chloride are there in 256 g of magnesium chloride.

Solution :

Molecular formula of magnesium chloride is $MgCl_2$ .

Molecular formula of $MgCl_2$ is, M = 95.211 g/mol .

Mass of chlorine in 1 mol of $MgCl_2$ is , m = 35.5 × 2 = 71 g.

So, amount of chlorine in 256 gram $MgCl_2$ :

$m =(71* 256)/(95.211)\n\nm = 190.90\ g$

Hence, this is the required solution.

Select the complexes that exhibit geometric isomerism. check all that apply. check all that apply. [co(h2o)2(ox)2]− [co(h2o)2(nh3)2(ox)]+ [co(en)3]3+ [ni(co)2cl2] [ni(nh3)2(en)2]2+

Answers

Geometric isomerism in another name is called cis-trans isomerism or it is called E-Z isomerism.
[Co(H2O)2(ox)2]- it is an octahedral complex which has two of bidentate ligand and another two of ligand. It exists as cis-trans isomers.
[Co(en)3]³+ it is an octahedral complex which has three bidentate ligands and it cannot exist as cis-trans isomers.
[Ni(CO)2CL2] is a square planar complex which has two of one ligand another two of ligand. It exists as cis-trans isomers.
[Co(H2O)2 (NH3)2(ox)]+ it is an octahedral complex with one of bidentate ligand two of each another ligand. It exists as cis-trans isomers.
[Ni(NH3)2 (en)2]²+ is an octahedral complex with one of a bidentate ligand and two each of another ligand. It exists as cis-trans isomers.
Following compounds exhibit geometric isomerism.
[Co(H2O)2 (ox)2]-
[Co(H2O2) (NH3)2 (ox)]+
[Ni(Co)2 CL2]
[Ni(NH3)2 (en)2]²+

The concentration of a certain sodium hydroxide solution was determined by using the solution to titrate a sample of potassium hydrogen phthalate (abbreviated as KHP). KHP is an acid with one acidic hydrogen and a molar mass of 204.22 g/mol. In the titration, 24.46 mL of the sodium hydroxide solution was required to react with 0.1082 g KHP. Calculate the molarity of the sodium hydroxide.

Answers

Answer:

$Molarity_(NaOH)=0.02166\ M$

Explanation:

Moles of KHP :

Given, Mass of KHP = 0.1082 g

Molar mass of KHP = 204.22 g/mol

The formula for the calculation of moles is shown below:

$moles = (Mass\ taken)/(Molar\ mass)$

Thus,

$Moles= (0.1082\ g)/(204.22\ g/mol)$

$Moles= 5.2982* 10^(-4)\ mol$

According to the reaction shown below:

KHP + NaOH ⇒ KNaP + H₂O

1 mole of KHP reacts with 1 mole of NaOH

So,

$5.2982* 10^(-4)\ mol$ of KHP reacts with $5.2982* 10^(-4)\ mol$ of NaOH

Moles of NaOH = $5.2982* 10^(-4)\ mol$

Volume = 24.46 mL = 0.02446 L ( 1 mL = 0.001 L)

$Molarity=(Moles\ of\ solute)/(Volume\ of\ the\ solution)$

$Molarity_(NaOH)=(5.2982* 10^(-4))/(0.02446)$

$Molarity_(NaOH)=0.02166\ M$

The value of delta for the [C_rF_6]^3- complex is 182 kJ/mol. Calculate the expected wavelength of the absorption corresponding to promotion of an electron from the lower-energy to the higher-energy of orbital set in this complex. (Remember to divide by Avogadro's number.) Should the complex absorb in the visible range?

Answers

Answer: Yes the absorb in the visible range.

Explanation:

The relationship between wavelength and energy of the wave follows the equation:

$E=(Nhc)/(\lambda)$

where,

$E$ = energy of the wave = 182 kJ/mol = 182000 J/mol

N = avogadro's number = $6.023* 10^(23)$

h = plank constant = $6.6* 10^(-34)Js^(-1)$

c = speed of light = $3* 10^8m/s$

$\lambda$ = wavelength of the wave = ?

Putting all the values:

$182000=(6.023* 10^(23)* 6.6* 10^(-34)* 3* 10^8m/s)/(\lambda)$

$\lambda=0.65* 10^(-6)m=650nm$ $(1nm=10^(-9)m)$

The wavelength range for visible rays is 400 nm to 750 nm, thus the complex absorb in the visible range.

Final answer:

The expected wavelength of the absorption in the [CrF6]3- complex cannot be calculated without knowing the exact value of ΔE. Therefore, it is unclear if the complex will absorb in the visible range.

Explanation:

In this complex, the value of delta (Δ) is 182 kJ/mol. To calculate the expected wavelength of the absorption corresponding to the promotion of an electron from the lower-energy orbital to the higher-energy orbital, we can use the equation: Wavelength = (hc)/(ΔE), where h is Planck's constant and c is the speed of light. By substituting the given values and dividing by Avogadro's number, we can calculate the expected wavelength.

However, the information given in the question does not provide the exact value for ΔE. Without this information, it is not possible to calculate the expected wavelength accurately. Therefore, we cannot determine if the complex will absorb in the visible range.

Learn more about Calculating expected wavelength of absorption in a complex here:

brainly.com/question/38332205

#SPJ3

Bobby created a dilution of 1/100 of a bacterial sample by adding 1 mL of sample to 99 mL of saline. Unfortunately, after Bobby completed the dilution, he knocked the container over spilling the majority of the diluted sample out. After cleaning up the mess, he found he had 19 mL of diluted sample remaining. Can he still completed the microbial count and if so, then write out the steps on how would he determine the original cell concentration of his total remaining samp

Answers

Answer:

There is no short answer.

Explanation:

In the given example Bobby is creating a solution for his bacteria count which consists of 1% bacterial sample.

Considering that the solution was mixed homogeneously, he can apply the procedure to the remaining sample and get the results he wants.

Or if the average number of bacteria in a 1 mL sample is known, he can apply that information proportionally to the 100 mL mixture and find the original cell concentration.

I hope this answer helps.

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