The statement, that describes the ‘control’in an experiment is "the name for the set of independent and dependent variables that will be controlled by the scientist."
A control is an element in an experiment that remains intact or unaffected by other variables. An experiment or observation aiming to minimise the influence of variables other than the independent variable is referred to as a scientific control. It serves as a standard or point of reference against which other test findings are measured.
In a scientific experiment, an independent variable is the variable that is modified or manipulated in order to assess the effects on the dependent variable. In a scientific experiment, the dependent variable is the variable that is being tested and measured. The designation given to the set of independent and dependent variables that the scientist will regulate.
Hence the correct option is D.
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D. The name for the set of independent and dependent variables that will be controlled by the scientist.
217g of water.
What is the molality of the solution?
Answer:
THE MOLARITY IS 2.22 MOL/DM3
Explanation:
The solution formed was as a result of dissolving 37.5 g of Na2S in 217 g of water
Relative molecular mass of Na2S = ( 23* 2 + 32) = 78 g/mol
Molarity in g/dm3 is the amount of the substance dissolved in 1000 g or 1 L of the solvent. So we have;
37.5 g of Na2S = 217 g of water
( 37.5 * 1000 / 217 ) g = 1000 g of water
So, 172.81 g/dm3 of the solution
So therefore, molarity in mol/dm3 = mol in g/dm3 / molar mass
Molarity = 172.81 g/dm3 / 78 g/mol
Molarity = 2.22 mol/dm3
The molarity of the solution is 2.22 mol/dm3
Answer:
The answer is 2.22mol
Explanation:
The density of metal will be "0.469 g/mL".
The given values in the question are:
Now,
The density of metal will be:
→
By substituting the given values, we get
→
→
Thus the above is the appropriate answer.
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The density of the metal is 0.47 g/mL
The density of an object is defined as the mass of the object per unit volume of the object.
With the above formula, we can obtain the density of the metal. This is illustrated below:
Volume of metal = change in volume of water = 3.2 mL
Mass of metal = 1.5 g
Density = mass / volume
Density = 1.5 / 3.2
Therefore, the density of the metal is 0.47 g/mL
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1. Sodium 4-amino-1-naphthalenesulfonate makes it very soluble in water as it contains a hydrate salt sodium sulfate .
2. In the structure of this compound, sodium sulphate is polar in nature.
The molecular structure of sodium 4-amino-1-naphthalenesulfonate is .
The polar part of the structure sodium sulfate makes sodium 4-amino-1-naphthalenesulfonate a hydrate salt. Salt are polar and are usually soluble in water.
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Answer: it contains a hydrate salt sodium sulfate NaO4S.
4-amino-1-naphthalenesulfonate is a sodium salt. Sodium sulfate is Polar.
Explanation:
The molecular structure of sodium 4-amino-1-naphthalenesulfonate is
C10H10NNaO4S
The polar part of the structure sodium sulfate NaO4S makes sodium 4-amino-1-naphthalenesulfonate a hydrate salt. Salt are polar and are usually soluble in water.
conduction
convection
radiation
Answer:
verdadero/a
falso/b
verdadero/c
Explanation:
B. decrease down a group and increase across a period.
C. increase down a group and increase across a period.
D. increase down a group and remain constant across a period.
E. increase down a group and decrease across a period.
Answer: The correct answer is Option E.
Explanation:
Atomic radius is defined as the total distance measured from the nucleus of an atom to the outermost shell.
Trend down the group:
Moving from top to bottom, a new shell gets add up around the nucleus and the outermost shell gets far away from the nucleus. Due to this, the distance between the nucleus and outermost shell increases, which results in the increase of atomic radii of the atom.
Trend across the period:
Moving from left to right in a period, more and more electrons gets add up in the same shell. The attraction between the last electron and the nucleus increases. This results in the shrinkage of size of an atom. Thus, decreasing the atomic radii of the atom.
Hence, the correct answer is Option E.
E. increase down a group and decrease across a period. Atomic radii generally increase down a group due to extra electron shells and decrease across a period due to greater nuclear charge.
In general, the correct answer to this question is E: atomic radii increase down a group and decrease across a period on the Periodic Table. The atomic radii increase down a group due to the addition of extra electron shells. Each additional shell means a greater distance between the nucleus and the outermost electrons, which results in a larger atomic radius. On the other hand, as you move across a period from left to right, atomic radii typically decrease. This is due to an increase in positive charge in the nucleus which pulls the electrons closer, thus decreasing the atomic radius.
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