a) The histograms suggest that the distributions of adoptions in each region are skewed to the right.
b) The histograms look similar because they both show similar patterns of adoption distribution among different regions.
c) A better way to express the number of adoptions might be to use adoption rates or percentages relative to the population size in each region.
a) The histograms show the distribution of adoptions in each region. The horizontal axis represents the number of adoptions, and the vertical axis represents the frequency (or count) of regions with a specific number of adoptions. Each bar in the histogram represents a specific number of adoptions and its height indicates how many regions have that number of adoptions.
b) The histograms look similar because they both show the distribution of adoptions in different regions. They have a similar shape, with the majority of regions having a lower number of adoptions, and a few regions having a higher number of adoptions. This similarity suggests that the adoption patterns in different regions follow a similar trend.
c) A better way to express the number of adoptions might be to use percentages or rates. Since the population of each region is different, the raw number of adoptions alone might not provide a fair comparison. By calculating the adoption rate (number of adoptions per 1000 people, for example) or expressing the number of adoptions as a percentage of the total population in each region, we can get a clearer picture of the adoption trends relative to the population size in each region.
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The histograms indicate that higher population regions tend to have more adoptions. They are similar as adoption rates and population sizes are interlinked. A better representation might be the adoption rate per population quota, which shows comparison between regions clearer.
a) The histograms show the "distribution of adoptions" and the "population of each region." We can infer that the distribution of adoptions largely mirrors the population distribution, meaning that regions with larger populations tend to have more adoptions.
b) The histograms look similar because adoption rates and population size are related. If a region has a larger population, it likely has more families, hence more potential for adoption.
c) A better way to express the number of adoptions might be to calculate the adoption rate per population. For example, the number of adoptions per 1,000 or 10,000 population members. This way, it directly relates the number of adoptions to the size of the population, and provides a percentage or ratio rather than absolute numbers. This method can be more helpful in making comparisons between regions.
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²-1
We will investigate the behavior of
both the numerator and denominator of h(x) near the point where x = 1. Let
f(x)= x³ + x -2 and g(x)=x²-1. Find the local linearizations of f and g at a = 1,
and call these functions Lf(x) and Lg(x), respectively.
Lf(x) =
L₂(x) =
Explain why h(x) ≈
Lf(x)
Lg(x)
for a near a = 1.
The local linearizations of f(x) and g(x) at a = 1 are Lf(x) = 4x - 5 and Lg(x) = 2x - 2 respectively. The function h(x) ≈ Lf(x)/Lg(x) because the local linearizations provide a good approximation of the numerator and denominator of h(x) near x = 1.
The local linearization of a function at a given point is an approximation of the function using a linear equation. To find the local linearization of a function f at a = 1, we need to find the slope of the tangent line at a = 1, which is equivalent to finding the derivative of f at x = 1. By taking the derivative of f(x) = x³ + x - 2, we get f'(x) = 3x² + 1. Evaluating f'(1), we find that the slope of the tangent line at a = 1 is 4. Therefore, the local linearization of f at a = 1, denoted as Lf(x), is given by Lf(x) = f(a) + f'(a)(x - a), which becomes Lf(x) = -1 + 4(x - 1) = 4x - 5.
Similarly, to find the local linearization of g(x) = x² - 1 at a = 1, we need to find the slope of the tangent line at a = 1. The derivative of g(x) is g'(x) = 2x. Evaluating g'(1), we find that the slope of the tangent line at a = 1 is 2. Therefore, the local linearization of g at a = 1, denoted as Lg(x), is given by Lg(x) = g(a) + g'(a)(x - a), which becomes Lg(x) = 0 + 2(x - 1) = 2x - 2.
When investigating the behavior of the function h(x) = (f(x))/(g(x)) near the point x = 1, we can approximate h(x) using the local linearizations of f and g at a = 1. Near the point a = 1, h(x) ≈ Lf(x)/Lg(x) because Lf(x) and Lg(x) provide a good approximation of the numerator and denominator, respectively, of h(x). This approximation holds as long as x is close to 1.
Answer: 371 / y
Step-by-step explanation: 371 is the dividend and y is the divisor
12 it
8
15 ft
What is the distance from point A to point B in feet?
A. 8ft B.7ft c.9ft D.6ft
The requried measure of the AB is given as 7ft. Option B is correct.
In a right-angled triangle, its sides, such as hypotenuse, and perpendicular, and the base is Pythagorean triplets.
Here,
From the diagram, applying Pythagoras' theorem to the right rectangle,
BC² = 15² - 12²
BC² = 81
BC = 9
Now,
AC = 16
AB + BC = 16
AB + 9 = 16
AB = 7 ft
Thus, the requried measure of the AB is given as 7ft. Option B is correct.
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Answer:9 ft
Step-by-step explanation:
Answer: He will need gallons of paint to paint the entire wall.
Step-by-step explanation:
Given : Area to paint = 142.5 square feet
Paint used to paint of the wall = gallon
Paint used to paint complete 1 wall = gallons
Paint used to paint complete 1 wall gallons
Hence, he will need gallons of paint to paint the entire wall.
Answer:
Step-by-step explanation:
Remark
Let the shorter base = x
Let the longer base = 3x
h = 5
Area = 60
Formula
Area = (b1 + b2)*h /2
Solution
60 = (x + 3x)*5 / 2 Multiply both sides by 2
2*60 = (x + 3x)*5 Combine like terms
120 = 4x *5
120 = 20x Divide by 20
120/20 = x
x = 6
Therefore the two bases are
x = 6
3x = 18
Answer:
C
Step-by-step explanation:
7y+9x=−2
please solve the system
45 points for who does
Answer:
Step-by-step explanation:
One method could be rewriting the second equation as x in terms of y and solving by replacing in the first equation.
Replace...
add on both sides.
Combine like terms
Now, to get rid of the fraction and isolate y, multiply by the reciprocal or the inverted fraction.
Simplify
Now replace the value of y in either equation to find x.
add 56
Divide by 9
To check whether these values are accurate, replace in either equation both values and you should have an equality. In this case I'll do it in both equations.
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