You have 2.2 mol Xe and 2.0 mol F2, but when you carry out thereaction you end up with only 0.25 mol XeF4. What is the percent yield

of this experiment?

Xe(g) + 2 F2 (g) - XeF. (g)

Answers

Answer 1

Answer:

The percentage yield of XeF from the concentration of the given reactants will be 25%.

The reaction states that 1 mole of Xe will give 1 mole of XeF, and 2 moles of fluorine, will gives 1 mole of XeF.

The limiting reactant can be calculated:

1 mole Xe = 2 moles of $\rm F_2$

2.2 moles of Xe = 2.2 $*$ 2 moles of $\rm F_2$

2.2 moles of Xe = 4.4 moles of $\rm F_2$

Since the amount of available $\rm F_2$ has been in the limiting, thus $\rm F_2$ has been the limiting reactant.

So, the yield of XeF in terms of $\rm F_2$ will be:

2 moles $\rm F_2$ = 1 mole XeF

Thus the theoretical yield of XeF is 1 mole.

The yield of XeF we get = 0.25 moles.

Thus the percentage yield = $\rm (Obtained)/(Theoretical\;yield)\;*\;100$

Percentage yield = $\rm (0.25)/(1)\;*\;100$

Percentage yield = 25%

Thus the percentage yield of XeF from the concentration of the given reactants will be 25%.

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Predict the products and write balanced net ionic equations for the following reactions. (g) SnCl2 is added to KMnO4 solution (acidic) forming Mn2

Answers

The product and balanced net ionic equations for the following reactions are SnCl₂ + 2KMnO₄ ⇒ 2 KCl + Sn(MnO₄)₂.

What is the net ionic equation?

Ionic equations are those equations that happened in an aqueous solution. The chemical equation is expressed in an electrolyte solution is expressed and dissociates ions.

In these reactions, each element or ion is dissociated into differently charged ions in a solution. Each of the ions is shown with different charges.

SnCl₂ + 2KMnO₄ ⇒ 2 KCl + Sn(MnO₄)₂. In the reaction, the tin chloride, and potassium magnesium oxide. It dissociates into charged ions, like potassium chloride and tin magnesium oxide. The chlorine will acquire a negative charge and magnesium oxide get a positive charge.

Thus, the net ionic equation is SnCl₂ + 2KMnO₄ ⇒ 2 KCl + Sn(MnO₄)₂.

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Answer:

The answer to your question is:

Explanation:

Reaction

SnCl₂ + 2KMnO₄ ⇒ 2 KCl + Sn(MnO₄)₂

1 ---- Sn ---- 1

2 ---- K ----- 2

2 ---- Mn ---- 2

8 ---- O ---- 8

2 ---- Cl ---- 2

Write a net ionic equation for the reaction that occurs when excess hydrochloric acid (aq) and potassium sulfite (aq) are combined. Note: Sulfites follow the same solubility trends as sulfates.

Answers

Answer: The net ionic equation for the given reaction is $2H^+(aq.)+SO_3^(2-)(aq.)\rightarrow H_2O(l)+SO_2(g)$

Explanation:

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are the ions which do not get involved in a chemical equation. It is also defined as the ions that are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of hydrochloric acid and potassium sulfite is given as:

$2HCl(aq.)+K_2SO_3(aq.)\rightarrow 2KCl(aq.)+SO_2(g)+H_2O(l)$

Ionic form of the above equation follows:

$2H^+(aq.)+2Cl^-(aq.)+2K^+(aq.)+SO_3^(2-)(aq.)\rightarrow 2K^+(aq.)+2Cl^-(aq.)+SO_2(g)+H_2O(l)$

As, potassium and chloride ions are present on both the sides of the reaction, thus, it will not be present in the net ionic equation.

The net ionic equation for the above reaction follows:

$2H^+(aq.)+SO_3^(2-)(aq.)\rightarrow SO_2(g)+H_2O(l)$

Hence, the net ionic equation for the given reaction is written above.

Final answer:

The net ionic equation for the reaction between hydrochloric acid and potassium sulfite is H+ (aq)+ SO3^2- (aq) → H+ (aq) + SO3^2- (aq), following the solubility trends of sulfates and sulfites under standard conditions.

Explanation:

The reaction between excess hydrochloric acid (HCl) and potassium sulfite (K2SO3) is a typical acid-base neutralization reaction. In the initial step, potassium sulfite dissociates into its ions in the aqueous solution:

K2SO3 (aq) → 2K+ (aq) + SO3^2- (aq)

Hydrochloric acid, being a strong acid, also dissociates completely:

HCl (aq) → H+ (aq) + Cl- (aq)

The hydrogen ion from the acid then reacts with the sulfite ion to form sulfuric acid and water, creating a net ionic equation :

2H+ (aq) + SO3^2- (aq) → H2SO3 (aq)

Because of the solubility trends of sulfates and sulfites under standard conditions, the sulfuric acid produced also dissociates into ions:

H2SO3 (aq) → 2H+ (aq) + SO3^2- (aq)

Therefore, the overall net ionic equation is:

H+ (aq)+ SO3^2- (aq) → H+ (aq) + SO3^2- (aq)

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Please it's due today

Answers

Answer:

Explanation:

Newton's third law. states that:

Action and reaction are equal and opposite.

Match the vocabulary word with the defination.___1.Hypothesis
___2.Variables
___3.Conclusion
___4.Scientific Method
___5.Procedure

a.The steps you take to complete the experiment
b.Factors that changes in an experiment
c.A possible solution to a problem
d.The result of the experiment
e.The process scientist follow to complete an investigation

Answers

Hypothesis - A possible solution to a problem

Variables - Factors that changes in an experiment

Conclusion - The result of the experiment

Scientific Method - The process scientists follow to complete an investigation

Procedure - The steps you take to complete the experiment

Answer:

1. d

2. b

3. d

4. e

5. a

explanation:

there's nothing else to explain

What is the atomic number of an element containing 12 neutrons and having a mass number of 24

Answers

The element is magnesium, its atomic number is 12.

A chemistry student must write down in her lab notebook the concentration of a solution of sodium hydroxide. The concentration of a solution equals the mass of what's dissolved divided by the total volume of the solution. Here's how the student prepared the solution: The label on the graduated cylinder says: empty weight: 4.5 g She put some solid sodium hydroxide into the graduated cylinder and weighed it. With the sodium hydroxide added, the cylinder weighed 48.772 g. She added water to the graduated cylinder and dissolved the sodium hydroxide completely. Then she read the total volume of the solution from the markings on the graduated cylinder. The total volume of the solution was 152.3 mL. What concentration should the student write down in her lab notebook? Be sure your answer has the correct number of significant digits.