Answer:
Check the explanation
Step-by-step explanation:
Kindly check the attached image below to see the step by step explanation to the question above.
25 pounds of potatoes on Saturday. What was the total
weight, in pounds, of potatoes purchased by Linda in the
two-day period?
A. 3
6
B. 3
1
C. 3
D. 3
*3
O O CONCO
5
E 3
6
Answer:b
Step-by-step explanation:
Write the fractions in order from least to greatest.
Answer:
D.
Step-by-step explanation:
Because in negative numbers greater is actually less
Answer:
change into improper fraction , find the common multiple and choose from the biggest because it is a negative fraction
Plz help me
Answer:
its most likey 4 the answer is 4
b. 8
c. 6
d. 2
Answer: Option d.
Step-by-step explanation:
The aditional variables are:
Region of the country. (where the options are Noth, Sout, East or West)
Type of business (where the options are Manufacturing, Financial, Information Services, or Other)
Then we are only adding 2 aditional variables to the model, the correct option is d.
Answer:
Line D
Step-by-step explanation:
Slope of a line passing through and is given by,
m =
Slope of line A passing through (-6, 3) and (0, 0)
m =
Negative and m < 1
Slope of line B passing through (-2, 4) and (0, 0)
m =
Negative and m < 1
Slope of line C passing through origin and (2, 5),
m = = 2.5
Positive and m > 1
Slope of line D passing through origin and (3, 2)
m =
Positive but m < 1
Therefore, Line D will be the answer.
Answer:
C(60) = 2.7*10⁻⁴
t = 1870.72 s
Step-by-step explanation:
Let x(t) be the amount of chlorine in the pool at time t. Then the concentration of chlorine is
C(t) = 3*10⁻⁴*x(t).
The input rate is 6*(0.001/100) = 6*10⁻⁵.
The output rate is 6*C(t) = 6*(3*10⁻⁴*x(t)) = 18*10⁻⁴*x(t)
The initial condition is x(0) = C(0)*10⁴/3 = (0.03/100)*10⁴/3 = 1.
The problem is to find C(60) in percents and to find t such that 3*10⁻⁴*x(t) = 0.002/100.
Remember, 1 h = 60 minutes. The initial value problem is
dx/dt= 6*10⁻⁵ - 18*10⁻⁴x = - 6* 10⁻⁴*(3x - 10⁻¹) x(0) = 1.
The equation is separable. It can be rewritten as dx/(3x - 10⁻¹) = -6*10⁻⁴dt.
The integration of both sides gives us
Ln |3x - 0.1| / 3 = -6*10⁻⁴*t + C or |3x - 0.1| = e∧(3C)*e∧(-18*10⁻⁴t).
Therefore, 3x - 0.1 = C₁*e∧(-18*10⁻⁴t).
Plug in the initial condition t = 0, x = 1 to obtain C₁ = 2.9.
Thus the solution to the IVP is
x(t) = (1/3)(2.9*e∧(-18*10⁻⁴t)+0.1)
then
C(t) = 3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴t)+0.1)
If t = 60
We have
C(60) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴*60)+0.1) = 2.7*10⁻⁴
Now, we obtain t such that 3*10⁻⁴*x(t) = 2*10⁻⁵
3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 2*10⁻⁵
t = 1870.72 s