) of basketball players has a bell shaped distribution with mean 72.5 inches and standard deviation 3.25 inches. A height of 79 inches is at what percentile?

Answers

Answer 1

Answer: 75.5+3.25=75.75÷79of inches

Answer 2

Answer: You have to find the z score and that will tell you the percent tile. x - m / S = z, so z = 2

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What’s the correct answer for this?

Answers

Answer:

Step-by-step explanation:

HJN IS SIMILAR TO PQN

Is the Mean Value Theorem applicable to the function f(x) = |x - 1| on the interval [0, 2]?Why or why not?

Answers

The only point that derivative of the function f(x) = |x - 1| is not continuous is at x = 0. You need to check whether the slope for the interval (0,2) is continuous to see if you can apply MVT. The interval (0,2) does not include end points, so 0 is not in this interval. The function is continuous over the interval, so MVT can be applied.

2 ( x - 6 ) = 3 ( x + 9 )

Answers

Steps to solve:

2(x - 6) = 3(x + 9)

~Distribute both sides

2x - 12 = 3x + 27

~Add 12 to both sides

2x = 3x + 39

~Subtract 3x to both sides

-x = 39

~Divide both sides by -1

x = -39

Best of Luck!

Answer:

2×-12=3×+27

2×-3×=27+12

-×=39

Step-by-step explanation:

Grouping like terms

then simplify to get x

=Initial Knowledge Check
Solve for x.
- 10= -6+ 2x
Simplify your answer as much as possible.
x=

Answers

Answer:

-2

Step-by-step explanation:

-10 = -6 + 2x

-10+6=2x

-4÷2x

-2=x

Find two consecutive positive integers such that the square of the first decreased by 67 is equal to three times the second

Answers

Answer:

The numbers are 10 and 11.

Step-by-step explanation:

Let $x$ and $x+1$ be consecutive positive integers.

When the problem says that the square of the first decreased by 67 this means $x^2-67$ and this is equal to three times the second $3(x+1)$ .

So $x^2-67=3(x+1)$ will be our equation.

Next, we solve the equation:

$x^2-67=3x+3\n\nx^2-70=3x\n\nx^2-3x-70=0$

Solve by factoring

$x^2-3x-70= \left(x^2+7x\right)+\left(-10x-70\right)\n\nx^2-3x-70=x\left(x+7\right)-10\left(x+7\right)\n\nx^2-3x-70=\left(x+7\right)\left(x-10\right)=0$