.4
.5
.6
D
.3
С
.5
.7
D
Þ(B and D) = [?]
ter
Answer:
0.35
Step-by-step explanation:
.5x.7
-3 x + 1/2 V = -3
Answer:
-6
Step-by-step explanation:
V = 6x + b
1/2 V -3 x = -3
V - 6x = -6
V - 6x = b
There are 9P3 = 504 ways the positions can be filled because the order in which the applicants are chosen doesn’t matter.
B.
There are 9C3 = 84 ways the positions can be filled because the order in which the applicants are chosen doesn’t matter.
C.
There are 9P3 = 504 ways the positions can be filled because the order in which the applicants are chosen matters.
D.
There are 9C3 = 84 ways the positions can be filled because the order in which the applicants are chosen matters.
The situation which is best described there is 9P3 = 504 ways the positions can be filled with order matters so option (C) will be correct.
Combination and permutation are two alternative strategies in mathematics to break up a collection of components into groups. This subset's components can be listed in any order when concatenated. The components of the subgroup are listed in a permutation in a particular order.
npr = factorial n/ factorial (n -r)
Given that,
Number of applicants = 9
Number of jobs = 3
Since the jobs are certain to the applicant so the order will matter.
Numberof ways to choose 3 people among 9 jobs
9p3 = factorial 9/factorial (9 -3)
9p3 = 9 × 8 × 7 × factorial 6/factorial 6
9p3 = 504
So there will be a total of 504 ways to feel the position such that order will also matter.
To learn more about permutation and combination
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Answer:
the correct answer is C
Step-by-step explanation:
; )
(95) x (3 x 104) = ?
Solve for x
Answer:
x is any Real number
Step-by-step explanation:
We first apply distributive property on the left to get rid of the grouping symbol, and then combining the like terms (linear terms on one side and numerical terms on the other side of the equation):
This equation results on a TRUE equality Zero = Zero, which means that any value we use for "x" in the original expression will always render an equality.
Therefore x is any Real number.
this question is incomplete
To write each combination of vectors as a single vector, we can simply add them together. For example, to write the combination of vectors AB + BC as a single vector, we would simply add the vectors AB and BC together.
Here is how to write each combination of vectors as a single vector:
AB + BC = AC
CD + DB = CB
DB - AB = BD
DC + CA + AB = AD
Here is a diagram to help visualize the addition of vectors:
[Diagram of vector addition]
In the diagram, vectors AB and BC are added together to create vector AC. Vector AC is the sum of vectors AB and BC.
We can also use the following formula to write the combination of vectors as a single vector:
A + B = (A_x + B_x, A_y + B_y)
where A_x and A_y are the components of vector A, and B_x and B_y are the components of vector B.
For example, to write the combination of vectors AB + BC as a single vector, we would use the following formula:
AB + BC = (AB_x + BC_x, AB_y + BC_y)
where AB_x and AB_y are the components of vector AB, and BC_x and BC_y are the components of vector BC.
To know more about vectors
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