Answer:
No, because it is not the tens digit that goes up by 1 in these numbers, it is the unit digit.
Step-by-step explanation:
It is important to know the concepts of units, tenths and cents.
For example
1 = 1 unit
10 = 1*10 + 0 = The tens digit is one the unit digit is 0
21 = 2*10 + 1 = The tens digit is two and the unit digit is 1.
120 = 1*100 + 2*10 + 0 = The cents digit is 1, the tens digit is two and the unit digit is 0.
So
Adding 1 is the same as the unit digit going up by 1.
Adding 10 is the same as the tens digit going up by 1.
Adding 100 is the same as the cents digit going up by 1.
In this problem, we have that:
864,865,866,867,868,869
Each value is the 1 added to the previous value, that is, the unit digit goes up by 1.
Mariel thinks the tens digit goes up by 1 in these numbers. Do you agree?
No, because it is not the tens digit that goes up by 1 in these numbers, it is the unit digit.
Answer:
disagree, its the unit number that goes up by 1
Step-by-step explanation:
Answer:
The answer is 53 cm2 or c.
Answer:
54 :/
Step-by-step explanation:
Well if mary ate 9 raisins and Mimi ate 6 times as much you just have to do:
9 x 6 = 54
y = 9 x 6?
Answer:
6.
Step-by-step explanation:
Since the y-value is the same, the two points make a horizontal line. You can think of it as a number line, where the first point is at -4 and the second is at 2. So, the distance between -4 and 2 is 6.
Answer:
in standered form -
3x²+4x−14=0
Step-by-step explanation:
Hope this helps :)
Answer:
a) The probability of getting a seven is 4/52
b) At least one of the cards is a seven=0.2813
c) The probability that none of them are seven= 0.7187
d) The probability that two out the four cards is a seven= 0.043
Step-by-step explanation:
A deck contains 52 cards containing 4 sets of 13 cards . Each set has a seven card in it. Thus there are 4 seven cards in a deck of 52 cards.
a) The probability of getting a seven is 4/52=0.0769
b) At least one of the cards is a seven=
1- P(no seven)
= 1- 4C0 * 48C4/ 52C4= 1- 0.7187= 0.2813
c) The probability that none of them are seven=4C0 * 48C4/ 52C4= 0.7187
d) The probability that two out the four cards is a seven= First card is seven * second Card is seven * two cards are not seven
= 4/52* 3/51*48/50= 0.0769*0.0588*0.96= 0.043
The probability of drawing four sevens, at least one seven, no sevens, and exactly two sevens from a shuffled deck of cards is explained step-by-step.
(a) The deck contains 52 cards, out of which there are 4 sevens. So, the probability of drawing a seven on the first card is 4/52. After drawing the first seven, there are 51 cards left in the deck, including 3 sevens. So, the probability of drawing a seven on the second card is 3/51. Continuing this process, the probability of getting four sevens in a row is (4/52) * (3/51) * (2/50) * (1/49).
(b) The probability of at least one seven can be calculated by finding the probability of the complement event (no seven). The probability of no seven on the first card is 48/52. After drawing the first card, there are 51 cards left, so the probability of no seven on the second card is 47/51. Continuing this process, the probability of no seven in four cards is (48/52) * (47/51) * (46/50) * (45/49). Subtracting this probability from 1 gives us the probability of at least one seven.
(c) The probability of none of the four cards being a seven can be calculated similarly to part (b). The probability of no seven on the first card is 48/52. After drawing the first card, there are 51 cards left, so the probability of no seven on the second card is 47/51. Continuing this process, the probability of no seven in four cards is (48/52) * (47/51) * (46/50) * (45/49).
(d) To find the probability that exactly two of the four cards are sevens, we need to consider two cases: (1) the first two cards are sevens and the last two are not, and (2) the first two cards are not sevens and the last two are. The probability of the first case is (4/52) * (3/51) * (48/50) * (47/49), and the probability of the second case is (48/52) * (47/51) * (4/50) * (3/49). Adding these probabilities gives the total probability.
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