A sample that includes important subgroups that the researchers want to be able to generalize their results to is called

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Answer 1
Answer:

Answer: representative sample

Explanation:

A representative sample can be defined as a subset of the population. This sample includes subgroups that reflect the features of the larger group and are chosen for a specific purpose of study. For example, a classroom with 60 students having 30 females and 30 males, can generate a representative sample based on the gender differences.


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The concept of photons applies to which regions of the electromagnetic spectrum?A. visible light only
B. infrared light, visible light, and UV light only
C. X-rays and gamma rays only
D. all regions of the spectrum

Answers

Answer:

D. all regions of the spectrum

Explanation:

I did some research ; )

A point charge that is exactly q =3 mu or micro CC is at the origin. In this problem, assume that the Coulomb constant k = 8.99 times 109 N m2/C2 exactly.(a) Find the potential V on the x axis at x = 3.00 m and at x = 3.01 m. In this part, enter your answers to exactly 6 signfificant figures.

Answers

Answer:

a) 8,990.00 V   b) 8,960.13 V

Explanation:

a) The potential due to a point charge, can be found from the expression of  Coulomb's Law, as follows:

V = (k*q)/(r)

where k = 8.99*10⁹ N*m²/C², q = 3.00*10⁻⁶ C, and r = 3.00 m.

Replacing by this values, we can find the potential V as follows:

V = (8.99e9 N*m2/C2*3.00e-6C)/(3.00m) = 8,990.00 V

b) Repeating the process for r = 3.01m:

V = (8.99e9 N*m2/C2*3.00e-6C)/(3.01m) = 8,960.13 V

Final answer:

The potential V at x=3.00 m and x=3.01 m from a point charge at the origin is 8.99 * 10^3 V and 8.97 * 10^3 V, respectively. This calculation is based on Coulomb's Law.

Explanation:

The potential V at a distance r from a point charge q is given by Coulomb's Law:

V = k*(q/r)

Here, k = 8.99 * 10^9 N*m^2/C^2 is the Coulomb constant, q = 3 µC is the charge, and r is the distance from the origin along the x-axis. For x = 3.00 m and x = 3.01 m, we can substitute these values into the equation to find V:

  • V1 = ((8.99 * 10^9 N*m^2/C^2)* (3 * 10^-6 C)) / 3.00 m = 8.99 * 10^3 V (to 6 significant figures)
  • V2 = ((8.99 * 10^9 N*m^2/C^2)* (3 * 10^-6 C)) / 3.01 m = 8.97 * 10^3 V (to 6 significant figures)

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What is the medium through which the wave is moving?

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Answer:

STRING held by the man

Explanation:

Wave is defined as a disturbance that travels through a MEDIUM and transfer energy from one point to another without causing any permanent displacement of the medium itself.

The medium through which wave travels varies e.g water, string, air etc

According to the diagram, wave travels through the string held by the man. This string is referred to as the MEDIUM through which the wave moves. The wave generated produces both crest (D) and trough (C) when displaced from its initial position (A)

Rope or one could consider it to be C to B or A to D

Patricia places 1500g of fruit on a scale compressing it by 0.02m. What is the force constant of the spring on the scale. Hint: you need 2 equations to solve this.

Answers

Answer:

The force constant of the spring is 735 N/m.    

Explanation:

It is given that,

Mass of fruit, m = 1500 g = 1.5 kg

Compression in the scale, x = 0.02 m

We need to find the force constant of the spring on the scale. The force acting on the scale is given by using Hooke's law. So,

F=-kx

Also, F = mg

mg=kx

k is force constant

k=(mg)/(x)\n\nk=(1.5* 9.8)/(0.02)\n\nk=735\ N/m

So, the force constant of the spring is 735 N/m.

A proton (charge e), traveling perpendicular to a magnetic field, experiences the same force as an alpha particle (charge 2e) which is also traveling perpendicular to the same field. The ratio of their speeds, vproton/valpha is:

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Explanation:

Charge on proton, q₁ = e

Charge on alpha particles, q₂ = 2e

The magnetic force is given by :

F=qvB\ sin\theta

Here, \theta=90=sin(90) = 1

For proton, F_p=ev_pB..........(1)

For alpha particle, F_a=2ev_aB..........(2)

Since, a proton (charge e), traveling perpendicular to a magnetic field, experiences the same force as an alpha particle. So,

ev_pB=2ev_aB

(v_p)/(v_a)=(2)/(1)

So, the ratio of the speed of proton to the alpha particle is 2 : 1 .Hence, this is the required solution.

Final answer:

If a proton and an alpha particle experience the same force in a magnetic field, the proton must be traveling at twice the speed of the alpha particle. This is because the force exerted by a magnetic field on a moving charge depends on the charge of the particle, the speed of the particle, and the strength of the magnetic field.

Explanation:

The force exerted by a magnetic field on a moving charge depends on the charge of the particle, the speed of the particle, and the strength of the magnetic field. Given that a proton (charge e) and alpha particle (charge 2e) experience the same force in the same magnetic field, we can create an equation to solve for their speed ratio.

The force on a particle due to a magnetic field is given by F = qvB where q is the charge, v is the speed, and B is the magnetic field. Since the force on the proton and alpha particle are the same, we can set their force equations equal to each other.

This means that e * v_proton * B = 2e * v_alpha * B. Simplifying, the ratio v_proton/v_alpha = 2.

Therefore, the proton is moving twice as fast as the alpha particle.

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Which one of these are true about scale models? a. A map may have a scale model with the proportion of one centimeter to one kilometer. b. A scale model is always smaller than the object it represents, c. A model may be built to different scales.

Answers

Answer:

Option A is true

Explanation:

For option A, it's true because a map that has a scale model with the proportion of one centimeter to one kilometer is known as verbal scale which is a type of scale.

For option B, it's not true because though a scale model is most times always smaller than the object it represents, there are sometimes when the scale model is an enlarged view/representation of a small object.

For option C, it's true because there is no one scale that is confined to just a model. A model can use different scales to depict an object.