Incomplete question.The complete question is here
What is the magnitude of the force needed to hold the outer 2 cm of the blade to the inner portion of the blade? The outer edge of the blade is 21 cm from the center of the blade, and the mass of the outer portion is 7.7 g. Even though the blade is 21cm long, the last 2cm should be treated as if they were at a point 20cm from the center of rotation.
Answer:
F= 0.034 N
Explanation:
Given Data
Outer=2 cm
Edge of blade=21 cm
Mass=7.7 g
Length of blade=21 cm
The last 2cm is treated as if they were at a point 20cm from the center of rotation
To Find
Force=?
Solution
Convert the given frequency to angular frequency
ω = 45 rpm * (2*pi rad / 1 rev) * (1 min / 60 s)
ω= 3/2*π rad/sec
Now to find centripetal force.
F = m×v²/r
F= m×ω²×r
Put the data
F = 0.0077 kg × (3/2×π rad/sec)²× 0.20 m
F= 0.034 N
Answer:
The 1.5V battery can power the flashlight bulb drawing 0.60A for 83.33 minutes before it is depleted.
Explanation:
To determine how long a 1.5V battery can power a flashlight bulb drawing 0.60A, you can use the formula for calculating the energy (in joules) consumed by an electrical device over time:
Energy (Joules) = Power (Watts) × Time (Seconds)
In this case, the power (P) is given by the product of the voltage (V) and current (I):
Power (Watts) = Voltage (Volts) × Current (Amperes)
So, first, calculate the power consumption of the flashlight bulb:
Power (Watts) = 1.5V × 0.60A = 0.90 Watts
Now, you want to find out how long the battery can power the bulb, so rearrange the energy formula to solve for time:
Time (Seconds) = Energy (Joules) / Power (Watts)
Given that the battery stores 4.5 kJ (kilojoules), which is equivalent to 4,500 joules, and the power consumption is 0.90 watts:
Time (Seconds) = 4,500 J / 0.90 W = 5,000 seconds
Now, to express the time in more practical units, convert seconds to minutes:
Time (Minutes) = 5,000 seconds / 60 seconds/minute ≈ 83.33 minutes
So, the 1.5V battery can power the flashlight bulb drawing 0.60A for approximately 83.33 minutes before it is depleted.
Answer is 0.0024
Explanation
divide the length value by 1000.
Answer:
Option A is true
Explanation:
For option A, it's true because a map that has a scale model with the proportion of one centimeter to one kilometer is known as verbal scale which is a type of scale.
For option B, it's not true because though a scale model is most times always smaller than the object it represents, there are sometimes when the scale model is an enlarged view/representation of a small object.
For option C, it's true because there is no one scale that is confined to just a model. A model can use different scales to depict an object.
Answer:
when u learn something new it goes to ur short term memory
The block's kinetic energy is closest to 1500 Joules.
The energy is always conserved.
So that, the total kinetic energy will be sum of initial potential energy and kinetic energy during falling.
Given that, mass(m)=10kg, v=10m/s, h=10m,g=10m/s^2
K.E=(1/2)mv^2 + mgh
K.E=(1/2)*10*100 + (10*10*10)
K.E=500 + 1000=1500Joule
The block's kinetic energy is closest to 1500 Joules.
Learn more about the kinetic energy here:
Answer:
Kinetic energy = 1500 J
Explanation:
The computation of the block's kinetic energy is shown below:
As we know that
Conservation of energy is
PE_i + KE_i = PE_f + KE_f
where,
Initial Potential energy = PE_i = m gh = 10kg× 10m/s^2 × 10m = 1000 J
Initial Kinetic energy = KE_i = (0.5) m V^2 = (0.5) (10 kg) (10 m/s)^2 = 500 J
Final potential energy = PE_f = mgh = 0
As h = 0 which is at reference line
So
PE_i + KE_i = PE_f + KE_f
Now put these valeus to the above formulas
1000 J + 500 J = 0 + KE_f
After solving this
Kinetic energy = 1500 J
Answer:
Explanation:
given,
mass of the both ball = 5 Kg
length of rod = 2 L
where L = 0.55 m
angular speed = 45.6 rev/s
ω = 45.6 x 2 π
ω = 286.51 rad/s
v₁ = r₁ ω₁
v₁ =0.55 x 286.51 = 157.58 m/s
v₂ = r₂ ω₂
v₂ = 1.10 x 286.51 = 315.161 m/s
finding tension on the first half of the rod
r₁ = 0.55 r₂ = 2 x r₁ = 1.10