CHEMISTRY COLLEGE

A chemist fills a reaction vessel with 0.750 M lead (II) (Pb2+) aqueous solution, 0.232 M bromide (Br) aqueous solution, and 0.956 g lead (II) bromide (PbBr2 solid at a temperature of 25.0°C. Under these conditions, calculate the reaction free energy AG for the following chemical reaction: Pb2+ (aq) + 2Br (aq) = PbBr2 (s) Use the thermodynamic information in the ALEKS Data tab. Round your answer to the nearest kilojoule.

Answers

Answer 1

Answer:

Answer:

The free energy = -20.46 KJ

Explanation:

given Data:

Pb²⁺ = 0.750 M

Br⁻ = 0.232 M

R = 8.314 Jk⁻¹mol⁻¹

T = 298K

The Gibb's free energy is calculated using the formula;

ΔG = ΔG° + RTlnQ -------------------------1

Where;

ΔG° = standard Gibb's freeenergy

R = Gas constant

Q = reaction quotient

T = temperature

The chemical reaction is given as;

Pb²⁺(aq) + 2Br⁻(aq) ⇄PbBr₂(s)

The ΔG°f are given as:

ΔG°f (PbBr₂) = -260.75 kj.mol⁻¹

ΔG°f (Pb²⁺) = -24.4 kj.mol⁻¹

ΔG°f (2Br⁻) = -103.97 kj.mol⁻¹

Calculating the standard gibb's free energy using the formula;

ΔG° = ξnpΔG°(product) - ξnrΔG°(reactant)

Substituting, we have;

ΔG° =[1mol*ΔG°f (PbBr₂)] - [1 mol *ΔG°f (Pb²⁺) +2mol *ΔG°f (2Br⁻)]

ΔG° =(1 *-260.75 kj.mol⁻¹) - (1* -24.4 kj.mol⁻¹) +(2*-103.97 kj.mol⁻¹)

= -260.75 + 232.34

= -28.41 kj

Calculating the reaction quotient Q using the formula;

Q = 1/[Pb²⁺ *(Br⁻)²]

= 1/(0.750 * 0.232²)

= 24.77

Substituting all the calculated values into equation 1, we have

ΔG = ΔG° + RTlnQ

ΔG = -28.41 + (8.414*10⁻³ * 298 * In 24.77)

= -28.41 +7.95

= -20. 46 kJ

Therefore, the free energy of reaction = -20.46 kJ

Answer 2

Answer:

Final answer:

To calculate the reaction free energy ΔG for this reaction, we need to use the standard free energy of formation values given in a data tab, the stoichiometry of the reaction, and the specific conditions of the reaction, including the concentrations of Pb2+ and Br−. After a series of calculations, we will get the ΔG value in joules, which can be converted to kilojoules.

Explanation:

The task here is to calculate the reaction free energy ΔG for the Pb2+(aq) + 2Br−(aq) = PbBr2(s) reaction at 25.0°C. From the given information, we can start by calculating the number of moles of PbBr2 from its mass. Then, referring to the thermodynamic data tab of the ALEKS, we find the standard free energy of formation (ΔGf°) values for Pb2+(aq), Br−(aq), and PbBr2(s). Now, we can use these values and the definition of ΔG for a reaction in terms of ΔGf° values and stoichiometry.

ΔG = ΣΔGf°(products) - ΣΔGf°(reactants).

Note that the equation must be balanced so each ΔGf° value is multiplied by the stoichiometric coefficient of that substance in the reaction. It is also important to remember to convert the answer to kilojoules if the ΔGf° values are given in joules/mole. Lastly, the concentrations of Pb2+ and Br− are included in the reaction quotient Q to show the reaction's non-standard conditions.

Learn more about Reaction Free Energy here:

brainly.com/question/14562388

#SPJ12

Related Questions

What is the formula for nickel (II) carbonate
Which of the following electron configurations represents an excited state of the indicated atom? Group of answer choices a.Na: 1s2 2s2 2p6 3s2 3p2 3s1 b.Ne: 1s2 2s2 2p6 c.N: 1s2 2s2 2p3 d.P: 1s2 2s2 2p6 3s2 3p2 4s1 e.He: 1s2
A car travels for 0.5 hours and goes 25 miles. What is the car's speed? (Remember sad + t)
Wich substances is most likely to form in a precipitation reaction?
Calculate the molality of a solution containing 22.75 g of glycerol (C3H8O3) in 79.6 g of ethanol (C2H5OH).

With 21 g of Zinc, and 7 g of CuCl2, how much ZnCl2 is made in grams?

Answers

Answer: 7.07 grams

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}*{\text{Molar Mass}}$

$\text{Moles of} zinc=(21g)/(65g/mol)=0.32moles$

$\text{Moles of} CuCl_2=(7g)/(134g/mol)=0.052moles$

$Zn+CuCl_2\rightarrow Cu+ZnCl_2$

According to stoichiometry :

1 mole of $CuCl_2$ require 1 mole of $Zn$

Thus 0.052 moles of $CuCl_2$ will require= $(1)/(1)* 0.052=0.052moles$ of $Zn$

Thus $CuCl_2$ is the limiting reagent as it limits the formation of product and $Zn$ is the excess reagent.

As 1 mole of $CuCl_2$ give = 1 mole of $ZnCl_2$

Thus 0.052 moles of $CuCl_2$ give = $(1)/(1)* 0.052=0.052moles$ of $ZnCl_2$

Mass of $ZnCl_2=moles* {\text {Molar mass}}=0.052moles* 136g/mol=7.07g$

Thus 7.07 g of $ZnCl_2$ will be produced from the given masses of both reactants.

What are four properties of water?

Answers

Answer:

Polarity

Cohesion

Adhesion

High Specific Heat

Explanation:

Group 17 elements form A. +1 ion B. -1 ion C. +7 ion D. -7 ion

Answers

Answer:

Explanation:

Use your periodic table to find out the charge on a Fl ion if your periodic table is constructed that way. In any event, the charge on Fl when it becomes an ion is -1. I don't think it has any other charge. So all of the elements in column 17 will have at least -1 in common.

Final answer:

Group 17 elements, also known as halogens, have seven valence electrons and tend to gain one electron to become stable, forming a -1 ion.

Explanation:

The elements in Group 17 on the periodic table are also known as halogens. These elements, which include fluorine, chlorine, bromine, iodine, and astatine, have seven valence electrons. Hence, they tend to gain one electron to achieve a stable electron configuration, forming a -1 ion. Therefore, the correct answer to your question is B. -1 ion.

Learn more about Group 17 elements here:

brainly.com/question/17088164

#SPJ6

A solution is dilute when?A. it has a lot of solute
B. has little solvent
C. it has a lot of solvent
D. has maximum solute

Answers

The answer to your equation is C. Hope this Helps!

C. It has more solvent
To dilute a solution means to add more solvent without the addition of more solute

What is the pOH of a 7.9 x 10 ^-4 M OH- solution?

pOH= ?

Answers

Answer: pOH of the given hydroxide ion concentration is 3.10

Explanation:

pOH is defined as the negative logarithm of hydroxide ion concentration. It is represented by the equation:

$pOH=-\log[OH^-]$

We are given:

Hydroxide ion concentration, $[OH^-]=7.9* 10^(-4)M$

Putting values in above equation, we get:

$pOH=-\log(7.9* 10^(-4))\n\npOH=3.10$

Hence, pOH of the given hydroxide ion concentration is 3.10

pOH is defined as -log([OH-]).

pOH = -log([OH-]) = -log(7.9 * 10^-4) = 3.1

Hope this helps!

Indicate the number of protons, neutrons, and electrons in each of the following species: 15N7, 33S16, 63Cu29, 84Sr38, 130Ba56, 186W74, 202Hg80

Answers

The number of protons neutrons, and electrons in each of the following species given are below;

What is the atomic number?

The total number of protons present in an atom is known as the atomic number of that atom. The atomic number has no correlation either with the number of neutrons or the number of electrons present inside an atom.

15N7 ⇒ 7 electrons, 8 neutrons, 7 protons

33S16 ⇒ 16 protons, 16 electrons, 17 neutrons

63Cu29 ⇒ 29 electrons, 34 neutrons,29 protons

84Sr38 ⇒ 38 electrons, 46 neutrons,38 protons

130Ba56 ⇒ 56 electrons, 74 neutrons,56 protons

186W74⇒ 74 electrons, 112 neutrons,74 protons

202Hg80 ⇒ 80 electrons, 122 neutrons ,80 protons

To learn more about the atomic number from here, refer to the link ;

brainly.com/question/14190064

#SPJ2

Answer:

1. 7 protons, 7 electrons, 8 neutrons