Answers
Answer:
s = 22.352 m/s
Explanation:
Given data:
Time taken = 0.5 hours
Distance cover = 25 miles
Car speed = ?
Solution:
First of all we will convert the units.
1 hour = 3600 sec
0.5 hr ×3600 sec / 1hr = 1800 sec
miles to meter:
25 mi × 1609 m/ 1 mi = 40233.6 m
Formula:
s = d/t
s = speed
d = distance
t = time
Now we will put the values in formula.
s = 40233.6 m / 1800 sec
s = 22.352 m/s
Final answer:
The speed of the car, calculated by dividing the distance travelled (25 miles) by the time taken (0.5 hours), is 50 miles per hour.
Explanation:
The subject of the question falls under Mathematics, specifically a section of it named rate, time, and distance problems. The problem is asking us to calculate the speed of a car which can be obtained by dividing the distance travelled by the time taken. Given that the distance travelled by the car is 25 miles and the time taken is 0.5 hours, we can calculate the speed as follows.
- Denote the Speed as S, the distance as D, and the time as T.
- Since Speed = Distance/Time, we substitute our values into this equation
- Therefore, Speed = 25 miles / 0.5 hour = 50 miles/hour
So, the speed of the car is 50 miles per hour.
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Related Questions
What effect does salt have on most metals?
How many neutrons does the isotope N-14 have?
Which of the following correctly identifies which has the higher first ionization energy, CI or Ar, and supplies the best justification? a. Cl, because of its higher electronegativity b. Cl, because of its higher electron affinity c. Ar, because of its completely filled valence shell d. Ar, because of its higher effective nuclear charge Given the information in a table of bond dissociation energies, calculate the change in enthalpy, delta H, in units of kJ, for the following gas-phase reaction: H_2C = CH_2 + H-Br rightarrow CH_3CH_2Br a. +148 b. -148 c. +200 d. -200
Balance the chemical equation given below, and determine the number of moles of iodine that reacts with 10.0 g of aluminum._____ Al(s) + _____ I2(s) → _____ Al2I6(s)
Answers
For a given arrangement of ions, the lattice energy increases as ionic radius decreases and as ionic charge increases.
What is ion?
An atom or molecule is said to be an ion if one or more of whose valence electrons have been acquired or lost, providing it a net negative or positive electrical charge.
Faraday knew that metals disintegrated together into solution place at a single electrode and that a second metal was placed first from solution at the opposite electrode, as such matter had to be trying to move underneath the impact of an electrical current even though he was unable to identify the particles trying to move between the electrodes. For a given arrangement of ions, the lattice energy increases as ionic radius decreases and as ionic charge increases.
Therefore, for a given arrangement of ions, the lattice energy increases as ionic radius decreases and as ionic charge increases.
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Answer:
as the charge of the ions increases, the lattice energy increases. as the size of the ions increases, the lattice energy decreases.
Answers
Answer:
bxnhdjxjdjvxjsj sbdhhxhchdbd
Answers
Answer: 1.63 moles
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number of particles.
To calculate the moles, we use the equation:
Given mass = 223 g
Molar mass = 136.4
Thus there are 1.63 moles in 223 g of the compound.
= 223/136.42
= 1.634 moles.
Hope this helps!
Answers
Explanation:
It is known that the coefficients change in concentration and in the exponents. Hence, the reaction equation will be as follows.
According to the ICE table,
Initial : 0.10 1.50 0
Change : -x -4x +x
Equilibrium: 0.10 - x 1.50 - 4x x
Hence, the mass action expression is as follows.
=
As, the value of is huge, it means that the reaction is very product favored. Hence, we need to find the limiting reactant first and then we get to know what x should be.
In the given reaction ammonia is the limiting reactant, because there is less than 4 times the ammonia as the copper cation. Thus, we expect it to run out first, and so, x is approximately equal to 0.25 M.
So, putting the given values into the above equation as follows.
=
From here
= M
Therefore, we can "re-solve" for x to get and verify that it is still ≈0.250 M.
x =
=
= 0.37491425 M
Thus, we can conclude that concentration of () is 0.37491425 M.
Answers
Answer:
K₂O
Explanation:
Given parameters:
Mass of K = 36.7g
Mass of O = 7.51g
Unknown:
Empirical formula of the compound
Solution:
The empirical formula of a compound is it's simplest ratio by which the elements in the compound combines. It differs from the molecular formula that shows the actual atomic ratios.
To find the empirical formula, follow this process;
Elements K O
Mass 36.7 7.51
Molar
mass 39 16
Number of
moles 36.7/39 7.51/16
0.94 0.47
Divide by
the smallest 0.94/0.47 0.47/0.47
2 1
Empirical formula is K₂O
Final answer:
The empirical formula of the compound composed of 36.7 g of potassium and 7.51 g of oxygen is K2O.
Explanation:
To determine the empirical formula of a compound, we need to find the ratio of the elements present. In this case, we have 36.7 g of potassium and 7.51 g of oxygen. To find the ratio, we need to convert these masses to moles by dividing them by the molar masses of potassium and oxygen. The molar mass of potassium is 39.10 g/mol and the molar mass of oxygen is 16.00 g/mol. Dividing the masses by the molar masses gives us 0.939 mol potassium and 0.469 mol oxygen. The ratio between these two elements is approximately 2:1, so the empirical formula of the compound is K2O.
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i) Before adding NaOH
ii) After adding 24.00 mL NaOH
Answers
Answer:
i) pH = 0.6990
ii) pH = 2.389
Explanation:
i) Before adding aqueous NaOH, there are 25.00 mL of 0.2000 M HCl. HCl reacts with the water in the aqueous solution as follows:
HCl + H₂O ⇒ H₃O⁺ + Cl⁻
The HCl and H₃O⁺ are related to each other through a 1:1 molar ratio, so the concentration of H₃O⁺ is equal to the HCl concentration.
The pH is related to the hydronium ion concentration as follows:
pH = -log([H₃O⁺]) = -log(0.2000) = 0.699
ii) Addition of NaOH causes the following reaction:
H₃O⁺ + NaOH ⇒ 2H₂O + Na⁺
The H₃O⁺ and NaOH react in a 1:1 molar ratio. The amount of NaOH added is calculated:
n = CV = (0.2000 mol/L)(24.00 mL) = 4.800 mmol NaOH
Thus, 4.800 mmol of H₃O⁺ were neutralized.
The initial amount of H₃O⁺ present was:
n = CV = (0.2000 mol/L)(25.00 mL) = 5.000 mmol H₃O⁺
The amount of H₃O⁺ that remains after addition of NaOH is:
(5.000 mmol) - (4.800 mmol) = 0.2000 mmol
The concentration of H₃O⁺ is the amount of H₃O⁺ divided by the total volume. The total volume is (25.00 mL) + (24.00 mL ) = 49.00 mL
C = n/V = (0.2000 mmol) / (49.00 mL) = 0.004082 M
The pH is finally calculated:
pH = -log([H₃O⁺]) = -log(0.004082) = 2.389