A sample of chlorine gas initially having a volume of 35.6 L was found to have a volume of 27.2 L at 15.6 atm. What was the initial gas pressure (in atm)? Assume constant temperature.

Answers

Answer 1

Answer:

Answer: The inital pressure of the gas is 11.9 atm

Explanation:

To calculate the initial pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

$P_1V_1=P_2V_2$

where,

$P_1\text{ and }V_1$ are initial pressure and volume.

$P_2\text{ and }V_2$ are final pressure and volume.

We are given:

$P_1=?\nV_1=35.6L\nP_2=15.6atm\nV_2=27.2$

Putting values in above equation, we get:

$P_1* 35.6L=15.6* 27.2\n\nP_1=11.9atm$

Thus inital pressure of the gas is 11.9 atm

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Answers

Final answer:

An example of a solution is salt and water.

Explanation:

An example of a solution is salt and water. When salt is mixed with water, it dissolves and forms a homogeneous mixture where the salt particles are evenly distributed throughout the water.

Learn more about solutions here:

brainly.com/question/30665317

The entropy of a substance above absolute zero will always be: a. Negative
b. Positive
c. Neither Negative nor positive

Answers

i will be positive. just because it’s positive

What coefficients must be added to balance the following reaction?_____ Pb + _____ H3PO4 yields _____ H2 + _____ Pb3(PO4)2

A: 3, 2, 1, 1

B: 3, 2, 2, 1

C: 3, 1, 3, 1

D: 3, 2, 3, 1

Answers

D: 3, 2, 3, 1 The Pb3(PO4) comes from having 3 Pb and 2 H3PO4. The H2 comes from the 2H3PO4

Find the mass of oxygen in grams produced by the decomposition of 100.0 g of CO2

Answers

The balanced chemical equation is :

$2CO_2->2CO+O_2\n\n$

Moles of $CO_2$ ,

$n = (100\ g)/(44.01\ g/mol)\n\nn=2.27\ mol$

Now, by given chemical equation , we can see 2 mole of $CO_2$ react with 1 mole of $O_2$ .

So , 2.27 mole react with :

$N=(2.27)/(2)\ mol\n\nN=1.135\ mol$

Mass of oxygen is :

$M = N * 16\n\nM=1.135* 16\ g\n\nM =18.16\ g$

Therefore, mass of oxygen in grams produced is 18.16 g.

Hence, this is the required solution.

Compare and contrast how observations and results can be used tosupport a conclusion to an experiment.

Answers

Answer:

by statistical analyses, especially by determining the p-value

Explanation:

In general, observations and results obtained from experimental procedures are subjected to a statistical test to check the robustness of the working hypothesis. The p-value is the most widely used statistical index in order to test such observations and results. The p-value is the statistical probability of obtaining extreme observed results when the null hypothesis is considered correct. A p-value lesser than 0.05 generally is considered statistically significant and then the null hypothesis can be rejected. In consequence, a very low p-value (which is obtained by statistical analysis of the observations and results), indicates that there is strong evidence in support of the alternative hypothesis.

Lewisite (2-chloroethenyldichloroarsine) was once manufactured as a chemical weapon, acting as a lung irritant and a blistering agent. During World War II, British biochemists developed an antidote which came to be known as British anti-Lewisite (BAL) (2,3-disulfanylpropan-1-ol). Today, BAL is used medically to treat toxic metal poisoning. Complete the reaction between Lewisite and BAL by giving the structure of the organic product and indicating the coefficient for the number of moles of HCl produced in the reaction.

Answers

Answer:

2 HCl

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

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