PHYSICS COLLEGE

You have built a device that measures the temperature outside and displays it on a dial as a measure of how far away from room temperature outside is. The way the dial works is that a needle with a charged ball on the end is placed between two charged parallel plates. The strength of the uniform electric field between the plates is proportional to the outside temperature. Given that the charged ball on the needle has a charge of?

Answers

Answer 1

Answer:

m=33.734 grams

E=41435.95 N/C

Explanation:

The detailed explanation of Answer is given in the attached file.

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Bill and Janet are pulling on opposite sides of a table. Bill pulls with a force of450 N to the left, and Janet pulls with a force of 300 N to the right. What is
the net force on the table?
O
A. 450 N to the right
O
B. 450 N to the left
C. 150 N to the left
O
D. 150 N to the right

Answers

Answer:

Explanation:

It is given that,

Force acting in left side, F = 450 N

Force acting in right side, F' = 300 N

Let left side is taken to be negative while right side is taken to be positive. So,

F = -450 N

F' = +300 N

The net force will act in the direction where the magnitude of force is maximum. Net force is given by :

$F_(net)=-450\ N+300\ N$

$F_(net)=-150\ N$

So, the net force on the table is 150 N and it is acting to the left side. Hence, the correct option is (c).

Answer:

C. 150 N to the left

Explanation:

If we take right to be positive and left to be negative, then:

∑F = -450 N + 300 N

∑F = -150 N

The net force is 150 N to the left.

A screw can be considered a type of

Answers

Fastener because a fastener is something that connects to objects and usually can come apart but can also be permanent

A 2-C charge experiences a force of 40 N when put at a certain location inspace. The electric field at that location is a. 2 N/C.b. 20 N/C. c. 30 N/C. d.
40 N/C. e. 60 N/C.

Answers

Answer:

E = 20 N/C

Explanation:

Given that,

Charge, q = 2 C

Force experience, F = 40 N

We need to find the electric field at that location.

The electric field in terms of electric force is given by :

F = qE

Where

E is the electric field

$E=(F)/(q)\n\nE=(40\ N)/(2\ C)\nE=20\ N/C$

So, the electric field at that location is 20 N/C.

A barbell spins around a pivot at its center at A. The barbell consists of two small balls, each with mass 450 grams (0.45 kg), at the ends of a very low mass rod of length d = 20 cm (0.2 m; the radius of rotation is 0.1 m). The barbell spins clockwise with angular speed 120 radians/s.What is the speed of ball 1?

Answers

The linear speed of the ball for the circular motion is determined as 12 m/s.

The given parameters;

mass of each ball, m = 450 g = 0.45 kg
length of the rod, L = 0.2 m
radius of the rod, r = 0.1 m
angular speed of the ball, ω = 120 rad/s

The linear speed of the ball is calculated as follows;

v = ωr

where;

ω is the angular speed of the ball
r is the radius of circular motion of the ball

The linear speed of the ball is calculated as follows;

v = ωr

v = 120 x 0.1

v = 12 m/s

Thus, the linear speed of the ball for the circular motion is determined as 12 m/s.

Learn more here:brainly.com/question/14404053

Answer:

The speed of ball is 12 $(m)/(s)$

Explanation:

Given:

Mass of ball $m = 0.45$ kg

Radius of rotation $r = 0.1$ m

Angular speed $\omega = 120 (rad)/(s)$

Here barbell spins around a pivot at its center and barbell consists of two small balls,

From the formula of speed in terms of angular speed,

$v = r \omega$

Where $v =$ speed of ball

$v = 120 * 0.1$

$v = 12 (m)/(s)$

Therefore, the speed of ball is 12 $(m)/(s)$

Tripling the displacement from equilibrium of an object in simple harmonic motion will bring about a change in the magnitude of the object's acceleration by what factor?

Answers

Answer:

acceleration will be tripled.

Explanation:

We know, when an object is performing Simple harmonic motion, the force

experience by it is directly proportional to its displacement from its mean position.

Also, F = ma , therefore, acceleration is also proportional to its displacement .

Now, F = kx

Therefore, $a=(k\ x)/(m)$

If we triple the displacement i.e, 3x.

Acceleration $a'=(k(3x))/(m)=3a.$

Therefore, acceleration is also tripled.

Hence, this is the required solution.

What is the magnitude of the force needed to hold the outer 2 cm of the blade to the inner portion of the blade?

Answers

Incomplete question.The complete question is here

What is the magnitude of the force needed to hold the outer 2 cm of the blade to the inner portion of the blade? The outer edge of the blade is 21 cm from the center of the blade, and the mass of the outer portion is 7.7 g. Even though the blade is 21cm long, the last 2cm should be treated as if they were at a point 20cm from the center of rotation.

Answer:

F= 0.034 N

Explanation:

Given Data

Outer=2 cm

Edge of blade=21 cm

Mass=7.7 g

Length of blade=21 cm

The last 2cm is treated as if they were at a point 20cm from the center of rotation

To Find

Force=?

Solution

Convert the given frequency to angular frequency

ω = 45 rpm * (2*pi rad / 1 rev) * (1 min / 60 s)

ω= 3/2*π rad/sec

Now to find centripetal force.

F = m×v²/r

F= m×ω²×r

Put the data

F = 0.0077 kg × (3/2×π rad/sec)²× 0.20 m

F= 0.034 N

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