a(1)= 3 5 a(n)=a(n−1)⋅(−9) What is the 3^{\text{rd}}3 rd 3, start superscript, start text, r, d, end text, end superscript term in the sequence?
Answers
Answer: -630
Step-by-step explanation:
Given the nth term of a sequence;
a(n)=a(n−1)⋅(−9) and the first term of the sequence a(1) as 35, the third term of the sequence can be gotten by using the formula at when n = 3
If n = 3 and a(1) = 35;
a(3) = 35(3-1)•(-9)
a(3) = 35×2×-9
a(3) = 70×-9
a(3) = -630
There the 3rd term of the series will give us -630 according to the nth term of the formula given.
Final answer:
The problem is about a recursive sequence where each term is the previous term multiplied by -9. After applying this rule twice, it is found that the 3rd term of the sequence is 243.
Explanation:
The problem provided indicates a recursive sequence, where each term is based on the previous term. The sequence is defined as a(1) = 3 and a(n) = a(n - 1) ⋅ (−9), which essentially means that each subsequent term is the previous term multiplied by -9.
To find the 3rd term, we apply this rule twice starting from the first term:
a(2) = a(1) * (-9) = 3 * (-9) = -27
a(3) = a(2) * (-9) = -27 * (-9) = 243
Therefore, the 3rd term of the sequence is 243.
Learn more about Recursive sequence here:
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Who procrastinates to study✋
Name the Ray that PQR and SQR share
13 squared? how does it mean and what is the solution?
Answers
Answer:
Option 3
Step-by-step explanation:
Brainliest please~
Answers
6(x/3 - x/2) = 12(6)
2x - 3x = 72
-x = 72
x = -72
Hope that helped :)
x = 4 and x = –4
x = 8 and x = –8
x = 16 and x = –16
Answers
The correct statement is that the solution of this equation x² – 16 = 0, is 4 and -4.
What is a quadratic equation?
It is a polynomial that is equal to zero. Polynomial of variable power 2, 1, and 0 terms are there. Any equation having one term in which the power of the variable is a maximum of 2 then it is called a quadratic equation. The general form of the quadratic equation is ax² + bx + c = 0
Given
The quadratic equation x² – 16 = 0
To find
The root of the quadratic equtaion?
How do find the solutions to the quadratic equation?
The quadratic equation x² – 16 = 0
We know the formula,
a² - b² = ( a - b ) ( a + b )
Then
x² – 4² = 0
(x - 4)(x + 4) = 0
x = 4 and -4
Thus, the solution of this equation x² – 16 = 0, is 4 and -4.
More about the quadratic equation link is given below.
Answer: The correct option is (B) x = 4 and x = -4.
Step-by-step explanation: We are given to find the solutions to the following quadratic equation :
Since the coefficient of x is zero in the given equation, so we will be using the method of square root to solve the equation.
From equation (i), we have
Thus, the required solution is x = 4 and x = -4.
Option (B) is correct.
Answers
JACK IS CORRECT.
4n²= 36 when n=3, not 144.
It is because you have to power up first, then you should multiply. But Katie did the opposite, so she was wrong.
Answers
Answer:
4
Step-by-step explanation:
2√x, √x + 1, 2√x + 1 sides of triangle
√x= y
2y, y+1, 2y+1
(2y)²+(y+1)²= (2y+1)²
4y²+y²+2y+1= 4y²+4y+1
y²-2y=0
y=0 (discarded as side can't be zero) or y= 2
so √x=2 ⇒ x= 4
Answer:
x= 4
According to the Pythagoras Theoram,
p²+b²= h²
=>x+2√x+1+4x = 4x +4√x +1
=> x = 4x - 4x +4√x- 2√x+ 1- 1
=>x= 2√x
=> x/√x = 2
=> √x = 2
Therefore, x= (√x)² = (2)² = 4