13 squared? how does it mean and what is the solution?
Answers
It means 13 times 13. Cubed is 13 times 13 times 13.
Related Questions
The orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula mc023-1.jpg. If Saturn’s orbital period is 29.5 years, what is its distance from the sun?
Write the ratio 12 to 18 as a fraction in simplest form.
Ex 2.68. find the stationary points on the curve y=3x^4 -4x³ -12x² +1 and determine whether they are maximum or minimum turning points
Is 6x = y proportional
Answers
Answer:
y = -1/2 x + 1
Step-by-step explanation:
(-2, 2) and (4, -1) are points of the linear function, that will be described as:
y = ax + b
setting x=-2, y=2:
2 = -2a + b, so b = 2 + 2a
setting x=4, y=-1:
-1 = 4a + b ⇒ -1 = 4a + 2 + 2a ⇒ -3 = 6a ⇒ a = -1/2, b = 1
y = -1/2 x + 1
Answer:
+5
Step-by-step explanation:
Answers
1 ounce = ?
Solve:-
1.92 ÷ 32 = 0.06
$0.06 per ounce.
Check:
0.06 × 32 = 1.92
Correct!
$0.06 per ounce.
(a) What is the slope of the graph?
(b) What is the F-intercept?
Answers
Answers
Answer:
A=30,32,44,48
B=22,34
intersect=26
numbers going outside is 24,28,36,38,40,42,46
b) 1/14
Step-by-step explanation:
a)The numbers that will go into the A bracket will be 30,32,44 and 48. The numbers that will go into the B bracket will be 22 and 34. The number that will go into the intersect will only be 26. And finally the numbers going on the outside of the venn diagram will be 24,28,36,38,40,42,46.
b)The answer will be 1/14
The pool must have been the same depth at the start of the interval as it was at the end of the interval.
The pool must have been deeper at the end of the interval than it was at the start of the interval.
The pool must have been more shallow at the end of the interval than it was at the start of the interval.
Answers
Answer: The pool must have been the same depth at the start of the interval as it was at the end of the interval.
Explanation:
The average rate of change is calculated as:
[final value - initial value] / time interval.
Then, the average rate of change does not take into account intermediates values, and you cannot draw any conclusion about such intermediate values.
In the given case you have:
average rate of change in depth = [final depth - initial depth] / 2 weeks.
0 = [final depth - initial depth] / 2 weeks.
⇒ 0 = final depth - initial depth
⇒ final depth = initial depth.
That is why the conclusion is the second statement of the answer choices: the pool must have been the same depth at the start of the interval as it was at the end of the interval.
In between the pool might have been deeper, more shallow, empty or change in any form, since the average rate of change does not tell the full history but only the net change.
Answers
Answer:
x=70
Step-by-step explanation:
Since they are supplementary angles (180°)
45° + (2x-5)° = 180°
(2x-5)° = 180° - 45°
(2x-5)° = 135°
2x° = 135° + 5°
2x° = 140°
x° = 140/2°
x° = 70°
Since they are supplementary angles (180°)
45° + (2x-5)° = 180°
(2x-5)° = 180° - 45°
(2x-5)° = 135°
2x° = 135° - 5°
2x° = 130°
x° = 130/2°
x° = 65°