On one of the day you went to the gym, the ratio of men to women was 3 : 2. If 120 men used the gym, how many women were there?
Answers
Answer
Find out the how many women were there .
To prove
Let us assume that the x is the scalar multiple of men and women.
As given
The ratio of men to women was 3 : 2.
Than
The total number of men = 3x
The total number of women = 2x
As given
If 120 men used the gym.
thus
120 = 3x
x = 40
The total number of women = 2 × 40
= 80
Therefore 80 women were there in the gym .
3/2 is equal to 120/80.
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log3(2x-5)=2 Answer is 41/2. Why?
What is the approximate area of the shaded sector in the circle shown below? A) 26.5 cm^2 B) 11.78 cm^2 C) 5.89 cm^2 D) 53.0 cm^2
Write 11 5/8 as an improper fraction
Answers
The expression for the given phrase is 5x+11/3x+8.
The given phrase is five times the sum of a number eleven divided by three times the sum of the number eight.
What is an expression?
An expression is a combination of terms that are combined by using mathematical operations such as subtraction, addition, multiplication, and division.
Let the unknown number be x.
Five times the sum of a number eleven = 5x+11
Three times the sum of the number eight = 3x+8
So, the expression is 5x+11/3x+8
Therefore, the expression for the given phrase is 5x+11/3x+8.
To learn more about an expression visit;
brainly.com/question/28170201.
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The sum of the variable (x) or in other words, the unknown number, is being added with 11 for a sum. The entirety of that is being multiplied by 5. Now, that entire product (answer to multiplication) is being divided by the sum of that same variable (x) and 8 multiplied by 3.
Answers
Answers
t H(t) g(t)
2 208 95.4
3 224 127.6
4 208 159.8
5 160 192
The solution for H(t) = g(t) is in between 4 and 5 seconds.
B.
Between 4 and 5 seconds, the projectile and the second object will have the same.
Answer and Explanation :
Given : The function shows the height H(t), in feet, of a projectile after t seconds.
A second object moves in the air along a path represented by , where g(t) is the height, in feet, of the object from the ground at time t seconds.
To find :
Part A - Create a table using integers 2 through 5 for the 2 functions. Between what 2 seconds is the solution to H(t) = g(t) located?
Part B - Explain what the solution from Part A means in the context of the problem.
Solution :
For Part A -
Substitute the value of t from 2 to 5 in the equation H(t) and g(t)
t
2
3
4
5
To determine the interval in which H(t)=g(t), we have to plot the equation and the table points and see the intersection.
Refer the attached figure below.
The intersection point of both the equations are (4.647,180.62)
This point lies between t at 4 to 5.
Therefore, H(t)=g(t) between t=4 to t=5.
For Part B -
The Part A shows that the projectile destroyed along the path are same in interval [4,5] and gives the solution of equation.
B. Broken
C. Parallel
D. Curved
Answers
x/3≤ -6
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x^2 + 12 * x = -11
x^2 + 12 * x + 11 = 0
(x + 1) * (x + 11) = 0
1. x = - 1
2. x = - 11
The correct result would be x = - 1, or x = - 11.
Answers
Answer:
We know that our world is in 3 dimensions i.e. there are three directions and so, three co-ordinates are required.
Now, if we have to find a position of an object lying on a flat surface, this means that there are only two directions and so, two co-ordinates are needed.
So, we can define the domain ( xy-axis ) in such a way that there are two axis - horizontal where right area have positive values & left area has negative values and vertical where upward side have positive values & downward side has negative values.
For e.g. if we want to find the position of a pen on the table. We will make our own xy-axis and see in which quadrant the pen lies.
Let us say that the pen lies at (2,3), this means that the position of pen is in the first quadrant or it is 2 units to the right of y-axis and 3 units up to the x-axis.
This way we can see that two directions are sufficient to find the position of an object placed on a flat surface.
Final answer:
Position of an object on a flat surface can be adequately described using measurements in the vertical and horizontal directions from a certain reference point. This concept is inherent in the use of vector quantities in physics which allow us to describe motion in two perpendicular directions.
Explanation:
To describe the position of an object on a flat surface, we can use two measures: the vertical and horizontal displacement from a certain reference point. This reference point is often called the origin in a Cartesian coordinate system, which is a type of frame of reference.
Let's imagine you're looking at a map. If we want to specify a location on that map, we can describe it in terms of its distance east (or west) and north (or south) from a particular point. This technique uses horizontal and vertical measurements to describe the position.
This concept is inherent in the idea of vector quantities. In two dimensions, a vector describes motion in two perpendicular directions, such as vertical and horizontal. The principle that motions along perpendicular axes are independent allows us to analyze these two directions separately. Each vector in this context has vertical and horizontal components, and the length of the vector (representing the object's total displacement) is calculated based on these two components.
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