Answer:
Step-by-step explanation:
area of base = 5×11 = 55 ft²
area of triangle = ½×5×6 = 15 ft²
area of rectangular face = 6.5×11 = 71.5 ft²
surface area = 55 + 2×15 + 2×71.5 = 228 ft²
x = –1
No Real Solutions
x = 11 and x = 1
x = 11
The solution to the quadratic equation x² - 12x + 11 = 0 is x = 11 and x = 1.
Given the quadratic equation in the question:
x² - 12x + 11 = 0
To solve the quadratic equation x² - 12x + 11 = 0 by completing the square, first the constant term to the other side of the equation:
x² - 12x + 11 = 0
x² - 12x + 11 - 11 = 0 - 11
x² - 12x = -11
Next, find the value that is equal to the square of half of b:
( b/2 )² = ( -12/2 )² = (-6)²
Add (-6)² to each side of the equation:
x² - 12x + (-6)² = -11 + (-6)²
x² - 12x + 36 = -11 + 36
x² - 12x + 36 = 25
Factor the perfect trinomial sqaure:
( x - 6 )² = 25
Solve for x:
x - 6 = ±√25
x - 6 = ±5
x = 6 ± 5
Hence, x = 6 - 5 = 1
And x = 6 + 5 = 11.
Therefore, the values of x are 1 and 11.
Learn more about quadratic equations here: brainly.com/question/1863222
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Answer:
Step-by-step explanation:
x^2 – 12x + 11 = 0
(x-11)(x-1)
x= 11, 1 completing the square
B. 49
C. 8
D. 13
Parallelogram A B C D is shown.
By the definition of a parallelogram, AB∥DC. AD is a transversal between these sides, so ∠A and ∠D are
angles. Because AB and DC are
, the same-side interior angles must be
by the same-side interior angles theorem. Therefore, ∠A and ∠D are supplementary.
Answer:
By the definition of a parallelogram, AB∥DC. AD is a transversal between these sides, so ∠A and ∠D are
✔ same-side interior
angles. Because AB and DC are
✔ parallel
, the same-side interior angles must be
✔ supplementary
by the same-side interior angles theorem. Therefore, ∠A and ∠D are supplementary.
Step-by-step explanation:
Answer:
The answer above is correct!
The correct options are:
First box: option D. same-side interior
Second box: option C. parallel
Third box: option D. supplementary
Step-by-step explanation:
Hope this helped - just got it right on edge!
Brainliest would be greatly appreciated :)