1. Sodium 4-amino-1-naphthalenesulfonate makes it very soluble in water as it contains a hydrate salt sodium sulfate .
2. In the structure of this compound, sodium sulphate is polar in nature.
The molecular structure of sodium 4-amino-1-naphthalenesulfonate is .
The polar part of the structure sodium sulfate makes sodium 4-amino-1-naphthalenesulfonate a hydrate salt. Salt are polar and are usually soluble in water.
Find more information about Molecular formula here:
Answer: it contains a hydrate salt sodium sulfate NaO4S.
4-amino-1-naphthalenesulfonate is a sodium salt. Sodium sulfate is Polar.
Explanation:
The molecular structure of sodium 4-amino-1-naphthalenesulfonate is
C10H10NNaO4S
The polar part of the structure sodium sulfate NaO4S makes sodium 4-amino-1-naphthalenesulfonate a hydrate salt. Salt are polar and are usually soluble in water.
Answer:
The answer is "Option b, c, and d".
Explanation:
In such a gene, Autosomes are also the sequence for code and transposable elements, not the series of encoding. Through the expression of genes, such fragments of its introns are split through protein complexes throughout the translation process. There has been no kenaf fiber in the genomes of prokaryotic cells.
B. When infectious agents get into the human body, the body gets a surge of energy, causing a slight increase in body temperature, and you feel great.
C. When infectious agents get into the human body, your body responds by raising the core body temperature, causing a fever.
D.Nothing happens when the human body is exposed to an infectious agent.
Answer:
when infectious agents get into the human body your body responds by raising the core body temperature causing a fever
The answer is C it will raise your body temp and cause a fever
Answer:
35.6 g of W, is the theoretical yield
Explanation:
This is the reaction
WO₃ + 3H₂ → 3H₂O + W
Let's determine the limiting reactant:
Mass / molar mass = moles
45 g / 231.84 g/mol = 0.194 moles
1.50 g / 2 g/mol = 0.75 moles
Ratio is 1:3. 1 mol of tungsten(VI) oxide needs 3 moles of hydrogen to react.
Let's make rules of three:
1 mol of tungsten(VI) oxide needs 3 moles of H₂
Then 0.194 moles of tungsten(VI) oxide would need (0.194 .3) /1 = 0.582 moles (I have 0.75 moles of H₂, so the H₂ is my excess.. Then, the limiting is the tungsten(VI) oxide)
3 moles of H₂ need 1 mol of WO₃ to react
0.75 moles of H₂ would need (0.75 . 1)/3 = 0.25 moles
It's ok. I do not have enough WO₃.
Finally, the ratio is 1:1 (WO₃ - W), so 0.194 moles of WO₃ will produce the same amount of W.
Let's convert the moles to mass (molar mass . mol)
0.194 mol . 183.84 g/mol = 35.6 g
2Cl-(aq)--->Cl2(g)+2e-
Cr3+(aq)+3e- ---->Cr(s)
What is the final, balanced equation for this reaction?
1.) 2cr3+(aq)+6Cl-(aq) ------> 2Cr(s)+3Cl2(g)
2.) 2Cr3(aq)+2Cl-(aq)+6e- --->Cl2(g)+2Cr(s)
3.) Cr3+(aq)+6Cl-(aq)+3e- ---->2Cr(g)+3Cl2(g)
4.) Cr3+(aq)+2Cl-(aq)------>Cr(s)+Cl2(g)
Answer:
A
Explanation:
got it correct on edge
Matter is not created nor destroyed.
The total mass of the products is greater than the total mass of the reactants.
The total mass of the reactants is less that the total mass of the products.
Matter is not changed.
Answer
The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.
Answer:
Carbon (i) : quaternary carbon
Carbon (ii) : secondary carbon
Carbon (iii) : tertiary carbon
Carbon (iv) : secondary carbon
Explanation:
Carbons can be classified into 4 categories:
(1) Primary carbon: These are the atoms where the carbon atom is attached to one other carbon atom.
(2) Secondary carbon: These are the atoms where the carbon atom is attached to two other carbon atoms.
(3) Tertiary carbon: These are the atoms where the carbon atom is attached to three other carbon atoms.
(4) Quaternary carbon: These are the atoms where the carbon atom is attached to four other carbon atoms.
In the given structure:
Carbon (i) is attached to 4 further carbon atoms and hence, it is a quaternary carbon.
Carbon (ii) is attached to 2 further carbon atoms and hence, it is a secondary carbon.
Carbon (iii) is attached to 3 further carbon atoms and hence, it is a tertiary carbon.
Carbon (iv) is attached to 2 further carbon atoms and hence, it is a secondary carbon.