Suppose 0.10 mol of Cu(NO_3)_2 and 1.50 mol of NH_3 are dissolved in water and diluted to a total volume of 1.00 L. Calculate the concentrations of Cu(NH_3)_4^2+ and of Cu^2+ at equilibrium.

Answers

Answer 1

Answer:

Explanation:

It is known that the coefficients change in concentration and in the exponents. Hence, the reaction equation will be as follows.

$Cu^(2+)(aq) + 4NH_(3)(aq) \rightarrow Cu(NH_(3))^(2)_(4)(aq)$

According to the ICE table,

$Cu^(2+)(aq) + 4NH_(3)(aq) \rightarrow Cu(NH_(3))^(2)_(4)(aq)$

Initial : 0.10 1.50 0

Change : -x -4x +x

Equilibrium: 0.10 - x 1.50 - 4x x

Hence, the mass action expression is as follows.

$K_(f) = ([Cu(NH3)^(2+)_(4)])/([Cu^(2+)][NH_(3)]_(4))$

= $(x)/((0.10 - x)(1.50 - 4x)^(4))$

As, the value of is huge, it means that the reaction is very product favored. Hence, we need to find the limiting reactant first and then we get to know what x should be.

In the given reaction ammonia is the limiting reactant, because there is less than 4 times the ammonia as the copper cation. Thus, we expect it to run out first, and so, x is approximately equal to 0.25 M.

So, putting the given values into the above equation as follows.

$1.03 * 10^(13) = (0.25)/((0.10 - 0.25)(1.50 - 4x))^(4)$

From here

$[NH_(3)] = 1.50 - 4x = ((2.33)/(1.03 * 10^(13)))^{(1)/(4)$

= M

Therefore, we can "re-solve" for x to get and verify that it is still ≈0.250 M.

x = $[Cu(NH_(3))^(2+)_(4)]$

= $\frac{1.50 - 2.31284 * 10{-4}}{4}]$

= 0.37491425 M

Thus, we can conclude that concentration of ( $Cu^(2+)$ ) is 0.37491425 M.

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Answer:

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1. On the basis of your results, what is the relationship between the temperature of the solvent and the rate of solution formation?

Answers

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Explanation:

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Answer:

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Explanation:

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A potassium ion (K+) would most likely bond with _____.

Mg+
O
Cl-
Na+

Answers

Answer:

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Explanation:

Answer:

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A wavelength of 4.73 x 10-7 m, and a frequency of

Answers

Answer:

Frequency =0.634×10¹⁵ s⁻¹

Explanation:

Given data:

Wavelength = 4.73×10⁻⁷ m

Frequency = ?

Solution:

Formula:

speed of light = wavelength× frequency

speed of light = 3×10⁸ m/s

Now we will put the values in formula.

3×10⁸ m/s = 4.73×10⁻⁷ m × frequency

Frequency = 3×10⁸ m/s /4.73×10⁻⁷ m

Frequency =0.634×10¹⁵ s⁻¹

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Answers

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