A particular string resonates in four loops at a frequency of 320 Hz . Name at least three other (smaller) frequencies at which it will resonate. Express your answers using two significant figures separated by commas.

Answers

Answer 1
Answer:

Answer:

160 Hz  ,  240 Hz  , 400 Hz

Explanation:

Given that

Frequency of forth harmonic is 320 Hz.

Lets take fundamental frequency = f₁

f_1=(320)/(4)\ Hz

f₁=80 Hz

Frequency of first harmonic = f₂

f₂=2 f₁

f₂ =2 x 80 = 160 Hz

Frequency of second harmonic = f₃

f₃= 3 f₁=3 x 80 = 240 Hz

Frequency of fifth harmonic = f₅

f₅=  5 f₁= 5 x 80 = 400 Hz

Three frequencies are as follows

160 Hz  ,  240 Hz  , 400 Hz

Answer 2
Answer:

Final answer:

The resonant frequencies of a string depend on its length, tension, and linear mass density. For a string resonating in four loops at 320 Hz, three possible smaller frequencies could be 160 Hz, 106.7 Hz, and 80 Hz.

Explanation:

When a string resonates, it vibrates at certain frequencies called its resonant frequencies. The resonant frequencies of a string depend on factors such as its length, tension, and linear mass density. In this case, the string resonates in four loops at a frequency of 320 Hz.

Three other possible resonant frequencies at which the string could vibrate with smaller loops include:

  1. 160 Hz: This is half the frequency of the given resonant frequency, which means the string vibrates with twice the number of loops.
  2. 106.7 Hz: This is one third of the given resonant frequency, which means the string vibrates with three times the number of loops.
  3. 80 Hz: This is one fourth of the given resonant frequency, which means the string vibrates with four times the number of loops.

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What is the magnitude of the force you must exert on the rope in order to accelerate upward at 1.4 m/s2 , assuming your inertia is 63 kg ? Express your answer with the appropriate units.

Answers

Answer:

The magnitude of the force you must exert on the rope in order to accelerate upward is 705.6 N

Explanation:

The magnitude of force, you must exert can be estimated as follows;

Since it is upward motion, we must consider acceleration due to gravity which opposes the upward motion.

F = m(a+g)

where;

F is the magnitude of the upward force

m is your mass, which is the measure of inertia = 63kg

a is the acceleration of the rope = 1.4 m/s²

F = 63(1.4 + 9.8)

F = 63(11.2)

F = 705.6 N

Therefore, the magnitude of the force you must exert on the rope in order to accelerate upward is 705.6 N

Answer:

705.6 N

Explanation:

Force: This can be defined as the product of mass a acceleration.

The S.I unit of force is Newton.

The expression for the force on the rope in order to accelerate upward is given as,

F-W = ma .......................... Equation 1

Where F = Force exerted on the rope, W = weight of the rope, m = mass of the rope, a = acceleration.

But,

W = mg........................ Equation 2

Where g = acceleration due to gravity

substitute equation 2 into equation 1

F-mg = ma

F = ma+mg

F = m(a+g).............. Equation 3

Given:  m = 63 kg, a = 1.4 m/s²

Constant: g = 9.8 m/s²

Substitute into equation 3

F = 63(1.4+9.8)

F = 63(11.2)

F = 705.6 N

The magnitude of the force exerted on the rope = 705.6 N

Why do societies stratify?

Answers

Answer:

Because of gender, caste, race, wealth, and religion etc.

Explanation:

Social stratification means society is divided in different categories, class, layers or groups due to gender, caste, race, wealth, and religion etc.

Society stratifies due to the following regions:

(1)  Gender discrimination means male- female difference.

(2) Unequal distribution of income and wealth

(3) Different types of religions

(4) Racism

(5) Type of education

(6) Social status etc.

Final answer:

Societies stratify, or divide their members into distinct groups or layers, based on various factors such as wealth, income, cultural beliefs, and status. Factors like prestige or age are also influential in some societies. Stratification systems can be either closed, allowing little social mobility, or open, where movement between classes is possible.

Explanation:

Societies stratify, or categorize people into different social standings, for various reasons. In many societies, stratification is an economic system, predominantly determined by wealth and income. Often, people interact chiefly with others of the same social standing, allowing economic and cultural factors to organize individuals into distinct groups or layers.

Societal stratification can also be driven by cultural beliefs that place value on specific attributes or characteristics such as prestige or age. For example, in some cultures, the elderly are esteemed, while in other societies, they are overlooked. Such cultural attitudes play a significant role in reinforcing stratification systems.

Also, stratification occurs when there is a difference in status or power between various societal roles, leading to a hierarchical organization of different groups - an example is the clear socioeconomic status (SES) division within society where individuals with more resources are seen at the top layer.

Closed and open stratification systems present themselves in different societies. Closed systems offer little opportunity for change in social position, whereas open systems, like class systems, are based on achievement, allowing movement and interaction between layers and classes.

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While doing her crossfit workout, Yasmeen holds an 7.0 kg weight at arm's length, a distance of 0.57 m from her shoulder joint. What is the torque about her shoulder joint due to the weight if her arm is horizontal? A 30 N m B. 4.0 N m C. 43N-m D. 39 N m

Answers

Answer:

D. 39 N m

Explanation:

m = mass of the weight used in crossfit workout = 7.0 kg

Force due to the weight used is given as

F = mg

F = (7.0) (9.8)

F = 68.6 N

d = distance of point of action of weight from shoulder joint = 0.57 m

τ = Torque about the shoulder joint due to the weight

Torque about the shoulder joint due to the weight is given as

τ = F d

Inserting the values

τ = (68.6) (0.57)

τ = 39 Nm

For every increase in mass the gravitational force blank If the total mass increase by effective for the gravitational force

Answers

For every increase in mass, the gravitational force increases. Gravitational force is directly proportional to the mass of the object.

What is gravitational force?

Gravitational force is the force by which an object attracts other objects into its center of mass. Earth attracts other objects gravitationally and that keep everyone stand to the ground.

Gravitational force directly proportional to the mass and inversely proportional to the distance between the objects. The expression relating the force and mass is written as:

g = G m/r²

Where G is the universal gravitational constant.

Therefore, as the mass of the object increase, the gravitational force exerted also increases. Similarly massive object experience more gravitation force by earth.

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Answer:

Increases by the same amount.Increases by a factor of 4.

Explanation:

i took it

A volumetric flask made of Pyrex is calibrated at 20.0°C. It is filled to the 150-mL mark with 34.5°C acetone. After the flask is filled, the acetone cools and the flask warms so that the combination of acetone and flask reaches a uniform temperature of 32.0°C. The combination is then cooled back to 20.0°C. (The average volume expansion coefficient of acetone is 1.50 10-4(°C)−1.) (a) What is the volume of the acetone when it cools to 20.0°C?

Answers

Answer:149.73 ml

Explanation:

Given

\beta \ of\ acetone=1.50* 10^(-4) ^(\circ)C^(-1)

change in volume is given by

\Delta V=V_(final)-V_(initial)

\Delta V=\nu_(initial)\beta _(acetone)\left [ T_f-T_i\right ]

V_(final)=\nu_(initial)+\nu_(initial)\beta _(acetone)\left [ T_f-T_i\right ]

V_(final)=150+150* 1.50* 10^(-4)\left [ 20-32\right ]

V_(final)=149.73 ml

Final answer:

The volume of the acetone when it cools to 20.0°C is approximately 142.39 mL.

Explanation:

In order to determine the volume of the acetone when it cools to 20.0°C, we can use the equation for the volume change caused by a temperature change at constant pressure, known as Charles's law. Charles's law states that the volume of a gas is directly proportional to its temperature in Kelvin. We can use the formula V2 = V1 * (T2 / T1) to calculate the volume of the acetone at the lower temperature.

Given that the initial volume of the acetone is 150 mL at a temperature of 34.5°C, we need to convert this temperature to Kelvin by adding 273.15. Therefore, T1 = 34.5°C + 273.15 = 307.65 K.

Since the final temperature is 20.0°C, the final temperature in Kelvin will be T2 = 20.0°C + 273.15 = 293.15 K. We can now plug these values into the equation to find the volume of the acetone at the lower temperature: V2 = 150 mL * (293.15 K / 307.65 K) = 142.39 mL.

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An internal explosion breaks an object, initially at rest,intotwo pieces, one of which has 1.5 times the mass of the other.If
7500 J were released in the explosion, how much kinetic energydid
each piece acquire?

Answers

Answer:

4500 J and 3000 J

Explanation:

According to conservation of momentum

      0 = m_1 V_1 + m_2 V_2

Given that m_2 = 1.5 m_1 , so

    V_1 = -1.5 V_2

  the kinetic energy of each piece is

    K_2= (1)/(2) m_2v_2^2

    K_1= (1)/(2) m_1v_1^2

substituting the value of V1 in the above equation

    K_1 = (1/2)( m_2 / 1.5 )( -1.5 V_2)^2 = 1.5 (1/2)m_2 V_2^2 = 1.5 K_2

  Given that

         K_1 + k_2 = 7500 J

       1.5 K_2 + K_2 = 7500

         K_2 = 7500 / 2.5

               = 3000 J

this is the KE of heavier mass

      K_1 = 7500 - 3000 = 4500 J

this is the KE of lighter mass

Final answer:

The question is about finding the kinetic energy acquired by each of two pieces of an object following an internal explosion, using principles of conservation of energy and momentum in physics.

Explanation:

The student has asked about an internal explosion that breaks an object into two pieces with different masses, releasing a certain amount of kinetic energy in the process. This question involves applying the principle of conservation of energy and momentum to find the kinetic energy acquired by each piece post-explosion.

Assuming piece 1 has a mass of m and piece 2 has a mass of 1.5m, the total mass of the system is 2.5m. Since 7500 J of energy was released in the explosion, to find the kinetic energy of each piece, we can use the fact that the total kinetic energy is equal to the energy released during the explosion. Let the kinetic energy of the smaller piece be K1 and of the larger piece be K2. Because the object was initially at rest and momentum must be conserved, the momenta of the two pieces must be equal and opposite. This relationship allows us to derive the ratio of the kinetic energies. We can solve for K1 and K2 proportionally. Finally, because the kinetic energy is a scalar quantity, adding the kinetic energies of the two pieces will equal the total energy released.

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