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In a collision between two objects having unequal masses, how does magnitude of the impulse imparted to the lighter object by the heavier one compare with the magnitude of the impulse imparted to the heavier object by the lighter one?a. the lighter object receives a larger impulse

b. the heavier object receives a larger impulse

c. both objects receive the same impulse

d. the answer depends on the ratio of the masses

e. the answer depends on the ratio of the speeds

Answers

Answer 1

Answer:

Answer:

Explanation:

The impulse has as an expression

I = ∫ F dt

In addition, on impulse of isolated systems is

I =ΔP = m vf - m v₀

Let's replace

F dt = m (vf -vo)

The force in these shocks laqueunxcyerpoesjerce on the other, using the law of action and reaction state forces has the same magnitude and the time of the shock is equal for the two bodies, this implies that the impulse is equal for the two bodies

Let's check the answers

a) False as the forces are of action and reaction the impulse must be equal

b) False

c) True. Why do we have an action and reaction stop

d False

e) false

Answer 2

Answer:

Final answer:

In collision between two objects, despite difference in their masses, both objects receive the same impulse, as per Newton's third law.

Explanation:

In a collision between two objects with unequal masses, according to Newton's third law of motion, 'For every action, there is an equal and opposite reaction', the magnitude of the impulse imparted to the lighter object by the heavy object is exactly the same as the magnitude of the impulse imparted to the heavier object by the lighter one.

This is regardless of the masses or speeds of the objects involved. The direction of these impulses will be opposite, but their magnitudes will be the equal. So, option c. 'both objects receive the same impulse' is correct.

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Answers

Answer:

a) F = -1.82 10⁻¹⁵ N, b) K = 9.1 10⁻¹⁶ J

Explanation:

a) To calculate the force between the nucleus and the electrons, let's use the Coulomb equation

F = k q Q / r²

as the nucleus occupies a very small volume compared to electrons, we can suppose it as punctual

let's calculate

F = 9 10⁹ (-1.6 10⁻¹⁹) (79 1.6 10⁻¹⁹) / (10⁻¹⁰)²

F = -1.82 10⁻¹⁵ N

b) they ask us for kinetic energy

let's use Newton's second law

F = m a

acceleration is centripetal

a = v² / r

we substitute

F = m v² / r

v = √ (F r / m)

v = √ (1.82 10⁻¹⁵ 10⁻¹⁰ / 9.1 10⁻³¹)

v = √ (0.2 10⁻¹⁶)

v = 0.447 10⁸ m / s

kinetic energy is

K = ½ m v²

K = ½ 9.1 10⁻³¹ (0.447 10⁸)²

K = 0.91 10⁻¹⁵ J

K = 9.1 10⁻¹⁶ J

A 0.320 kg ball approaches a bat horizontally with a speed of 14.0 m/s and after getting hit by the bat, the ball moves in the opposite direction with a speed of 22 m/s. If the ball is in contact with the bat for 0.0600 s, determine the magnitude of the average force exerted on the bat.

Answers

Answer:

42.67N

Explanation:

Step one:

Given

mass m= 0.32kg

intital velocity, u= 14m/s

final velocity v= 22m/s

time= 0.06s

Step two:

Required

Force F

the expression for the force is

F=mΔv/t

F=0.32*(22-14)/0.06

F=(0.32*8)/0.06

F=2.56/0.06

F=42.67N

The average force exerted on the bat 42.67N

Light of wavelength 608.0 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 88.5 cm from the slit. The distance on the screen between the fifth order minimum and the central maximum is 1.61 cm. What is the width of the slit?

Answers

Answer:

The width of the slit is 0.167 mm

Explanation:

Wavelength of light, $\lambda=608\ nm=608* 10^(-9)\ m$

Distance from screen to slit, D = 88.5 cm = 0.885 m

The distance on the screen between the fifth order minimum and the central maximum is 1.61 cm, y = 1.61 cm = 0.0161 m

We need to find the width of the slit. The formula for the distance on the screen between the fifth order minimum and the central maximum is :

$y=(mD\lambda)/(a)$

where

a = width of the slit

$a=(mD\lambda)/(y)$

$a=(5* 0.885\ m* 608* 10^(-9)\ m)/(0.0161\ m)$

a = 0.000167 m

$a=1.67* 10^(-4)\ m$

a = 0.167 mm

So, the width of the slit is 0.167 mm. Hence, this is the required solution.

Sultan throws a ball horizontally from his window, 12 m above the garden. It reaches the ground afterSelect........seconds.

4.0

5.0

2.4

1.6

Answer and I will give you brainiliest

Answers

Answer:

2.4

Explanation:

Hope it help mark as Brainlist

As frequency increases in an electromagnetic wave, its photon energy decreases. A. True B. False

Answers

Answer:

False

Explanation:

Answer:

False

Explanation:

A P E X

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