The oven tray is 600mm by 500mm. A cake tin is 25cm in diameter. How many cake tins can jenny fit on the oven tray at one time?

Answers

Answer 1
Answer: Area of Circle= \pir^(2)
                      = (22)/(7)( (25cm)/(2)) ^(2)
                      = 490.87cm^(2)

Area of Oven tray= 60cm x 50cm
                            = 3000cm^(2)

: . # tin that can hold on bake tray= 3000cm^(2)490.87cm^(2)                                 = 6.11
Thus making it logically 6..... 

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13=-5/4a PLEASEE HELP ME WITH THIS

Answers

Move 4a to the other side.

13(4a) = -5

52a  = -5

a = -5/52

hope this helped :D

What does 6x +3 - 1(-3 + x) equal?

Answers

Answer:

5x+6

Step-by-step explanation:

6x+3-1(-3+x) = 6x+3+3-x (expand the brackets)

=5x+6 (combine like terms)

6x+3-1(-3+x) = 5x+6

Hope this helps :)

It would equal to 6x+5

Form a union for the following sets. K = {2, 3, 5, 8}
L = {3, 5, 7}
a. { }
b. {3, 5}
c. {2, 3, 5, 7, 8}
d. {2, 7, 8}

Answers

Union of the represented sets should include all the sets without repetition
Here is an example for substituton A= {1,2,3} B={3,4,5} A union B = {1,2,3,4,5}. So, logically, the answer is c. {2, 3, 5, 7, 8} 
AuBuCuDuKuL={2,3,5,7,8}

A China cup and saucer cost 12$. The cup on its own cost 3$ more than the saucer. Form an eqaution for s and solve it. Find the cost of the cup

Answers

If the cup = S + 3
and the
saucer = S
then


(S + 3) + S = 12
2s + 3 = 12
2s = 9
s = 4.50

So by itself the saucer costs $4.50. To find the cost of the cup look to the beginning of the problem where we learned that

Cup = S + 3
cup = 4.50 + 3
cup = 7.50

So the saucer is $4.50 and the cup is $7.50...

4.50 + 7.50 = $12.00

It checks!

What is the slope of the line?

A. 2/5
B. -2/5
C. 5/2
D. -5/2

Answers

Answer:

  B.  -2/5

Step-by-step explanation:

For a "run" (x change) of 5, the "rise" (y change) is -2 units. Then the slope is ...

  slope = rise/run = -2/5

Answer:

 B.  -2/5

Step-by-step explanation:

The length of the sides of a triangular garden are 10m 11m 13m.Find the measure of the angle opposite the longest side to the nearest tenth of a degree

Answers

c^2=a^2+b^2-2abcosC
13^2=10^2+11^2-2×10×11×cos(°)
169=100+121-220cos(°)
220cos(°)=100+121-169
220cos(°)=52
cos(°)= 13/55
°=cos-1(13/55)
°=76.328°