$297.89 with a 9.5% tax

Answers

Answer 1

Answer: The exact answer is 326.18955. So about $316.19

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The point P(x, y) is on the terminal ray of angle theta. If theta is between pi radians and 3pi/2 radians and csc theta= -5/2, what are the coordinates of P(x, y)?A. P(-sqr 21, -2) B. P(sqr 21, -2) C. P(-2, sqr 21) D. P(-2, -sqr 21)
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What's the nearest tenth of 6.40
Suree can run 6 miles per hour. One mile is equal to 5280 feet. What is her running speed in feet per minute?A. 14.67 ft per minute B. 88 ft per minute C. 5528 ft per minute D. 860 ft per minute
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What should be done to both sides of the equation in order to solve N/4 = -12.4

Answers

Mutiply each by four to get n=-49.6. Hope this helped.

Answer:

Multiply by 4.

Step-by-step explanation:

You drive from your home to a vacation resort 420 miles away. You return on the same highway. The average velocity on the return trip is 15 miles per hour slower than the average velocity on the outgoing trip. Express the total time required to complete the round trip, T, as a function of the average velocity on the outgoing trip, x.

Answers

Time required to complete the round trip $T=(420)/(x)+(420)/((x-15))$ where x is average velocity on the outgoing trip.

Step-by-step explanation:

Let average velocity of outgoing trip = x mph

The average velocity on the return trip is 15 miles per hour slower than the average velocity on the outgoing trip.

Average velocity of return trip = (x-15) mph

Distance to vacation place = 420 miles

Distance to vacation place = Time for outgoing trip x average velocity of outgoing trip

$420=t_1* x\n\nt_1=(420)/(x)$

Distance to vacation place = Time for return trip x average velocity of return trip

$420=t_2* (x-15)\n\nt_2=(420)/((x-15))$

We have total time T = t₁ + t₂

That is

$T=(420)/(x)+(420)/((x-15))$

Time required to complete the round trip $T=(420)/(x)+(420)/((x-15))$ where x is average velocity on the outgoing trip.

What mathematics concepts or principles did you apply to come up with the solution of each equation? explain how you applied these.please help me .....

Answers

You need to look at the question again, and notice the words "... did you ...".
From those words, it's clear that the question comes AFTER you have solved
several equations, and now, this question is asking you how you solved them.

The only way for YOU to answer this question is to solve the equations first.

And if you want someone ELSE to tell the math concepts and principles that
are used to solve them, then you have to show him what the equations are.

A principal of $835 in an account at 3% per quarter simple interest

Answers

Take $835 and multiply by 0.3 and you get $25.05
If you add $25.05 to $835 you will get $860.05
Keep adding $25.05 and you will have sums of $885.10, $910.15, $935.20
So your answer is D.

A beach has to enclose a rectangular area, because some endangered species are nesting there. They have 200 feet of rope to rope off the area with. What is the maximum area that they can rope off?

Answers

Area is equal to length times width. The perimeter (the amount of rope) has to equal twice the length added to twice the width so we're left with:
A = l * w
200 = 2l + 2w
solve for either l or w
l = 100 - w
plug into the area equation to get one equation with two variables
A = w(100 - w)
A = -w^2 + 100w
take the derivative
A' = -2w + 100
set the derivative equal to zero
0 = -2w + 100
2w = 100
w = 50
This is the width that maximizes the area
with a width of 50, the length must also be 50 to have a perimeter of 200
therefore, they can rope up to 50 * 50 = 2500 ft^2

Final answer:

The maximum area that can be roped off with 200 feet of rope is 2500 square feet by making the roped off area a square.

Explanation:

The question deals with the optimization of area given a fixed perimeter, which involves the principles of geometry and algebra. Since the area needs to be roped off is a rectangle, and you have 200 feet of rope, your rectangle will have dimensions length (L) and width (W) such that 2L + 2W = 200.

To maximize the area of a rectangle given a fixed perimeter, the rectangle should be a square. So, for a maximum area, the length and width should be equal. Thus, each dimension (length and width) would be 200/4 = 50 feet.

Finally, to find the maximum area, we multiply the length by the width: 50 feet * 50 feet = 2500 square feet. So, the maximum area that they can rope off with 200 feet of rope is 2500 square feet.

Learn more about Optimization of Area here:

brainly.com/question/29759875

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Lin has a scale model of a modern train. The model is created at a scale of 1 to 48. The height of the model train is 102 millimeters. What is the actual height of the train in meters? Round your answer to the thousandths (third) decimal place. Do not include units (meters) in your answer.