Given the function f(x) = 5x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.Part A: Find the average rate of change of each section. (4 points)
Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other

Answers

Answer 1
Answer: Average rate of change  of section A = (f(1) - f(0))/ (1 - 0) = (5(1) - 5(0))/(1 - 0) = (5 - 0)/1 = 5
Average rate of change of section B = (f(3) - f(2))/(3 - 2) = (5(3) - 5(2))/(3 - 2) = (15 - 10)/1 = 5

Average rate of change of section B is equal to that of section A.

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Round 1330.464489 to one decimal place

Answers

Answer:

1330.5

Step-by-step explanation:

I rounded to the tenths place.

Answer:

1330.5

Step-by-step explanation:

Hope this helps! <3

(2a2 + a + 3) ÷ (a - 1)

Answers

Final answer is: 5a+3/a-1
Answer: 5a+3/a-1

Key: “/“ is a fraction bar
Key: 5a+3 is the numerator
Key: a-1 is the denominator

Hope this helps! <3

(a) Solve 7( k - 3 ) = 3k - 5 (b) Expand and simplify (2x + 3 )( x - 8)

(c) Solve 7 - 3= 2
                 4

Answers

a) 7(k-3)=3k-5\n 7k-21=3k-5\n 7k-3k=-5+21\n 4k=16\n k=\frac { 16 }{ 4 } \n k=4

b) (2x+3)(x-8)\n 2{ x }^( 2 )-16x+3x-24\n 2{ x }^( 2 )-13x-24

c) \frac { 7-3f }{ 4 } =2\n 7-3f=4\cdot 2\n 7-3f=8\n -3f=8-7\n -3f=1\n f=-\frac { 1 }{ 3 }
(a)\n7(k-3)=3k-5\n7(k)+7(-3)=3k-5\n7k-21=3k-5\ \ \ \ |add\ 21\ to\ both\ sides\n7k=3k+16\ \ \ \ |subtract\ 3k\ from\ both\ sides\n4k=16\ \ \ \ \ |divide\ both\ sides\ by\ 4\n\boxed{k=4}


(b)\n(2x+3)(x-8)=(2x)(x)+(2x)(-8)+(3)(x)+3(-8)\n\n=2x^2-16x+3x-24=\boxed{2x^2-13x-24}


(c)\n(7-3f)/(4)=2\ \ \ \ |multiply\ both\ sides\ by\ 4\n\n\not4^1\cdot(7-3f)/(\not4_1)=4\cdot2\n\n7-3f=8\ \ \ \ \ |subtract\ 7\ from\ both\ sides\n\n-3f=1\ \ \ \ \ |divide\ both\ sides\ by\ (-3)\n\n\boxed{f=-(1)/(3)}

Need help with: A circle with radius of 9 sits inside a circle with radius of 11 What is the area of the shaded region? Round your final answer to the nearest hundredth.

Answers

see the picture attached to better understand the problem

we know that
area of a circle=pi*r²

area of the larger circle
r= 11 units
Area=pi*11²-----> 379.94 units ²

area of smaller circle
area=pi*9²-----> 254.34 units²

area of the shaded region=area larger circle-area smaller circle
so
area of the shaded region=379.94-254.34-----> 125.60 units²

the answer is
125.60 units²

A recipe for sparkling grape juice 1 1/2 quarts of sparkling water and 3/4 of grape juice. How much sparkling water woild you need to mix with 9 quarts of grape juice. How much grape juice would you need to mix with 15/4 quarts of sparkling water?

Answers

According to the recipe the ratio of sparkling water to grape juice = 1 1/2 : 3/4.

Let us convert 1 1/2 into improper fraction and that is 3/2.

Now, 3/2: 3/4 or 3/2 ÷ 3/4 = 3/2 × 4/3 = 2/1 or 2:1.

Therefore, sparkling water quantity is two times of the quantity of grape juice.

Now, we need to find the number of quarts of sparkling water need to mix in 9 quarts of grape juice.


Since, sparkling water quantity is two times of the quantity of grape juice.

Therefore, we need 2 × 9 = 18 quarts of sparkling water to mix in 9 quarts of grape juice.


And now we need to find the number of quarts of grape juice would we need to mix with 15/4 quarts of sparkling water.

Therefore, we need 1/2 × 15/4 = 15/8 quarts of grape juice to mix with 15/4 quarts of sparkling water.



Answer:

a)x = 18\,qt, b)y = 1\,(7)/(8)\,qt

Step-by-step explanation:

a) The amount of sparkling water needed is determined by simple rule of three:

x = (9\,qt)/((3)/(4)\,qt)* (3)/(2)\,qt

x = 12* (3)/(2)\,qt

x = 18\,qt

b) The amount of grape juice needed is found by simple rule of three:

y = ((15)/(4)\,qt)/((3)/(2)\,qt ) * (3)/(4)\,qt

y = (30)/(12)* (3)/(4)\,qt

y = (90)/(48)\,qt

y = (15)/(8)\,qt

y = 1\,(7)/(8)\,qt

Which angle measure less than or equal to 360° is equivalent to an angle of 17π over 4

Answers

Hello,

17/4π rad = (4π+π/4  )rad

17/4 π mod 2π = π/4 (rad) or 45°