Answer:
K=32J
Explanation:
Kinetic energy is given by:
K=12mv2
We are given that m=4kg and v=4ms.
⇒K=12(4kg)(4ms)2
=32Nm
=32J
Step-by-step explanation:
i have no idea if this helps or not
Answer:
11,180
Step-by-step explanation:
The usual assumption for organic growth is that it is exponential. Here, the number increased by a factor of 1000/200 = 5 in 8 hours. For t in hours, a model for population might be ...
b = (initial value)·(growth factor)^(t/(period of growth))
b = 200(5^(t/8))
Using t = 20, the predicted population is ...
b = 200(5^(20/8)) = 200·5^2.5 ≈ 11,180
There might be about 11,180 bacteria in 20 hours.
Answer:
To travel 20 Km, the hybrid car needs 0.3125 gallons of fuel.
Step-by-step explanation:
Proportions
The hybrid car can travel 40 miles per gallon.
Since one mile is equivalent to 1.6 Km, the distance traveled per gallon is 40*1.6 = 64 Km.
Now the distance is expressed in Km, we can find the gallons needed to travel 20 Km, by calculating 20/64 = 0.3125.
To travel 20 Km, the hybrid car needs 0.3125 gallons of fuel.
Answer:
The autonomous equation refers to a differential equation where the independent variable is absent. In such equations, the information about the location of points of inflection can be obtained by analyzing the second derivative of the equation. Points of inflection occur where the second derivative changes sign. By finding the critical points of the second derivative and determining their nature (whether they are minima, maxima, or points of inflection), we can identify the location of points of inflection.
-15m = -4m
-7m - 8 = m - 4
-3m - 8 = 4 - m
m - 4 = -7m - 8
-8 - 7m = -4 + m
-8 - 3m = 4 - m
To solve this problem, we must simplify the the equation:
Here is the base equation -2m - 5m - 8 = 3 + (-7) + m (Add all like terms):
#1 -2m - 5m - 8 = 3 + (-7) + m (Property of Addition)
#2 -7m - 8 = -4 + m (Most Simplified Equation)
The answer your would be the 2nd one. -7m - 8 = m - 4
Answer:
38b = s
Step-by-step explanation:
38 students multiplied by the number of buses = the total number of students that can be carried by bus.
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