10+3(2xz+3y)2xz what's the answer.

Answers

Answer 1
Answer: 10+3(2xz+3y)\cdot 2xz=10+(6xz+9y)\cdot 2xz=\n \n=10+12x^2z^2+18xyz

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What do you do on here like

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Answer:

I come here to get answers for my homework and help other people

Plzz give me brainliest, i really need it to level up

Answer:

we answer each others questions and have fun !!

Solve the equation:

3x-5 = 19-x

Answers

3x-5=19-x
3x-5-19+x=0
4x-24=0
4x=24
x=6

PLEASE ITS DUE TONIGHT!!!! Sally rides her bike to run errands. It takes her 18 minutes at 10 mph to get to her first stop. She spends 20 minutes riding at 12 mph to get to her second stop. It then takes her 15 minutes riding at 15 mph to get home. a. Draw a speed vs. time graph for the time that Sally spent riding her bike. b. How far did she travel?

Answers

Answer:

The equation that relates distance, rate, and time is

       d  =  rt

Step-by-step explanation:

Can you use the sss postulate or the sas postulate to prove ABC and AED are congruent ?

Answers

Answer:

Neither SSS nor SAS apply.

Step-by-step explanation:

SSS (Side-Side-Side)-

If three pairs of sides of two triangles are equal in length, then the triangles are congruent.

SAS (Side-Angle-Side)-

If two pairs of sides of two triangles are equal in length, and the included angles are equal in measurement, then the triangles are congruent.

It given in the picture that,

  1. AC = AD (Side)
  2. BC = DE (Side)
  3. m∠BAC = m∠EAD (Angle)

So, ΔABC and ΔAED will not be congruent by either SSS or SAS.

PLEASE HELP I WILL VOTE BRAINLIEST IF CORRECTGraph the following system of equations and find the x-coordinate of the solution.

Choices:
x = -2
x = 3
x = 2
x = 0

Answers

x = 3

y = 8

(3, 8)

Hope this helps! :)

The function f(t) = −5t 2 + 20t + 60 models the approximate height of an objectt seconds after it is launched. How many seconds does it take the object to hit the
ground?

Answers

Answer:

6 seconds.

Step-by-step explanation:

We have been given a function formula f(t)=-5t^2+20t+60 that models the approximate height of an object  t seconds after it is launched.

To find the number of seconds it will take the object to hit the ground, we need to find the zeros of our given function.

-5t^2+20t+60=0

Upon dividing our equation by -5 we will get,

t^2-4t-12=0

We will factor our given equation by splitting the middle term as:

t^2-6t+2t-12=0

t(t-6)+2(t-6)=0

(t-6)(t+2)=0

(t-6)=0\text{ or }(t+2)=0

t=6\text{ or }t=-2

Since time cannot be negative, therefore, it will take the object 6 seconds to hit the ground.

f(t) = -5t^2 + 20t + 60
-5(t^2 - 4t - 12)
-5(t + 2) (t - 6)
t = -2 or t = 6

6 seconds